TEST REVIEW SEDIMENTARY IGNEOUS METAMORPHIC SEDIMENTARY 1 IGNEOUS
- Slides: 33
TEST REVIEW
SEDIMENTARY IGNEOUS METAMORPHIC
SEDIMENTARY 1 IGNEOUS METAMORPHIC
2 SEDIMENTARY IGNEOUS METAMORPHIC
SEDIMENTARY 3 IGNEOUS METAMORPHIC
SEDIMENTARY 4 IGNEOUS METAMORPHIC
SEDIMENTARY 5 IGNEOUS METAMORPHIC
6 SEDIMENTARY IGNEOUS METAMORPHIC
SEDIMENTARY 7 METAMORPHIC IGNEOUS
SEDIMENTARY 8 IGNEOUS METAMORPHIC
SEDIMENTARY 9 METAMORPHIC IGNEOUS
10. FALSE SEDIMENTARY IGNEOUS METAMORPHIC
12 11 Crystals in intrusive rock are larger.
13. SEDIMENTARY
14. INNER CORE SOLID 15. CRUST
16 CRUST MANTLE OUTER CORE INNER CORE
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18 The deeper the layer, the higher the temperature.
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20 v i t D e 21 a l e R g n i t a
22 FALSE
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24 Only one layer. In all three regions.
25 26. It went extinct.
27 Oldest E D ______ B A ______ C ______ Youngest
28 Atomic symbol B Atomic number 5 Na 11 H 1 Y Cu H Sg V 31 39 1 106 23 Protons 5 11 1 31 39 1 106 23 Neutrons 6 12 1 37 50 0 159 28 Electrons 5 11 1 31 39 1 106 23 Mass Number 11 23 2 68 89 1 265 51 29. One is H-2, the other is H-1. They are isotopes.
30 a. Protons positive b. Neutrons no charge c. Electrons negative
31 protons an element. It also tells you the number of electrons The atomic number tells you the number of in one atom of in a neutral atom of that element. The atomic number gives the “identity “of an element as well as its location on the Periodic Table. No two different elements will have the atomic number. same
32 mass number of an element is the total number of protons and neutrons in the nucleus of the atom. The
33 7 – 3 = 4 neutrons
34. After 11, 200 years, a sample of radium 226 has decayed. It has a half-life of 1600 years. The sample was originally 162 grams. How much is left? How many half-lives have gone by? 11, 200 ÷ 1, 600 = 7 half-lives 162 ÷ 2 = 81 81 ÷ 2 = 40. 5 ÷ 2 = 20. 25 ÷ 2 = 10. 125 ÷ 2 = 5. 0625 ÷ 2 = 2. 53 ÷ 2 = 1. 27 grams
35. A fossil log sample was sent to the lab for carbon-dating. The 14 C to 14 N ratio was determined. Of the original 240 grams of 14 C only 15 grams of 14 C remain. The half-life of 14 C is 5, 730 years. How many half-lives have gone by? 240 ÷ 2 =120 ÷ 2 = 60 30 ÷ 2 = 15 g 14 C 60 ÷ 2 = 30 4 half-lives 4 x 5730 = 22, 920 years 240 – 15 = 225 g 14 N
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