TAIL This versus That T Title TAIL Decide

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TAIL This versus That T – Title

TAIL This versus That T – Title

TAIL Decide on an appropriate scale for each axis. Choose a scale that lets

TAIL Decide on an appropriate scale for each axis. Choose a scale that lets you make the graph as large as possible for your paper and data T - Title A – Axis

How to determine Intervals Mass Acceleration 3 22 4 15 6 10 13 5

How to determine Intervals Mass Acceleration 3 22 4 15 6 10 13 5 31 2 (kg) (m/s 2) • The interval is decided by your scale. • In this case your x-scale would be from 0 – 22 and your y-scale would be from 0 – 31. • The graph paper is 7 x 7

TAIL Choose an interval that lets you make the graph as large as possible

TAIL Choose an interval that lets you make the graph as large as possible for your paper and data T – Title A – Axis I – Interval 22 ÷ 7 = 3. 14 31 ÷ 7 = 4. 43 5 4 Al ro way un s up d !

TAIL Mass versus Acceleration 35 T – Title 30 A – Axis 25 20

TAIL Mass versus Acceleration 35 T – Title 30 A – Axis 25 20 I – Interval 15 10 5 0 4 8 12 16 20 24 28

TAIL Mass versus Acceleration 35 T – Title 30 A – Axis Mass (kg)

TAIL Mass versus Acceleration 35 T – Title 30 A – Axis Mass (kg) 25 20 I – Interval 15 10 L – Labels 5 0 4 8 12 16 Acceleration (m/s 2) 20 24 28

Mass versus Acceleration 35 mass is inversely proportional to acceleration 30 Mass (kg) 25

Mass versus Acceleration 35 mass is inversely proportional to acceleration 30 Mass (kg) 25 20 15 10 5 0 4 8 12 16 Acceleration (m/s 2) 20 24 28

Linearize Mass 3 0. 045 4 0. 067 6 0. 10 13 0. 20

Linearize Mass 3 0. 045 4 0. 067 6 0. 10 13 0. 20 31 0. 50 (kg) • The interval is decided by your scale. • In this case your x-scale would be from 0 – 0. 5 and your y-scale would not change. • The graph paper is 7 x 7 0. 50 ÷ 7 = 0. 071 0. 08

slope Mass versus Acceleration-1 35 Must use points that fall on the line 30

slope Mass versus Acceleration-1 35 Must use points that fall on the line 30 Mass (kg) 25 20 15 10 5 0 0. 08 0. 16 0. 24 0. 32 0. 40 Acceleration-1 (s 2/m) 0. 48 0. 56 . m/s 2 62. 4 kg 62. 4 N

slope 62. 4 N Mass versus Acceleration-1 So slope = force! 35 30 y

slope 62. 4 N Mass versus Acceleration-1 So slope = force! 35 30 y = mx + b Mass (kg) 25 20 15 10 ma = F 5 0 0. 08 0. 16 0. 24 0. 32 0. 40 Acceleration-1 (s 2/m) 0. 48 0. 56 We just derived Newton’s 2 nd Law