Stoichiometry volume to volume Stoichiometry volume to volume

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Stoichiometry volume -to- volume:

Stoichiometry volume -to- volume:

Stoichiometry volume -to- volume: 1) Determine the volume of CO 2 produced when 78.

Stoichiometry volume -to- volume: 1) Determine the volume of CO 2 produced when 78. 4 L of C 2 H 2 burns at STP. 2 C 2 H 2(g) + 5 O 2(g) → 4 CO 2(g) + 2 H 2 O(g)

Stoichiometry volume -to- volume: 1) Determine the volume of CO 2 produced when 78.

Stoichiometry volume -to- volume: 1) Determine the volume of CO 2 produced when 78. 4 L of C 2 H 2 burns at STP. 78. 4 L ? L 2 C 2 H 2(g) + 5 O 2(g) → 4 CO 2(g) + 2 H 2 O(g) 4(22. 4)L 2(22. 4)L = X= = 157 L CO 2 Does it make sense?

Stoichiometry mass- to- volume:

Stoichiometry mass- to- volume:

Stoichiometry mass- to- volume: Calculate the volume of ammonia produced when 42 g of

Stoichiometry mass- to- volume: Calculate the volume of ammonia produced when 42 g of dinitrogen gas react with dihydrogen gas at STP. N 2(g) + 3 H 2(g) catalyst 2 NH 3(g)

Stoichiometry mass- to- volume: Calculate the volume of ammonia produced when 42. 0 g

Stoichiometry mass- to- volume: Calculate the volume of ammonia produced when 42. 0 g of dinitrogen gas react with dihydrogen gas at STP. 42. 0 g N 2(g) + 3 H 2(g) catalyst ? L 2 NH 3(g) 2(22. 4) L 28. 02 g = X= = 67. 2 L NH 3 Does it make sense?

Stoichiometry mass- to- # of particles:

Stoichiometry mass- to- # of particles:

Stoichiometry mass- to- # of particles: How many molecules of oxygen are produced when

Stoichiometry mass- to- # of particles: How many molecules of oxygen are produced when 29. 2 g of water is decomposed by electrolysis according to this balanced equation? 2 H 2 O(l) electricity 2 H 2(g) + O 2(g)

Stoichiometry mass- to- # of particles: How many molecules of oxygen are produced when

Stoichiometry mass- to- # of particles: How many molecules of oxygen are produced when 29. 2 g of water is decomposed by electrolysis according to this balanced equation? 29. 2 g ? molecules 2 H 2 O(l) electricity 36. 04 g 2 H 2(g) + O 2(g) 6. 02 x 1023 molec. = X= = 4. 88 x 1023 molec. Does it make sense?