 # Stoichiometry Mole to mole Stoichiometry is the process

• Slides: 11 Stoichiometry Mole to mole Stoichiometry is the process of calculating the products created or reactants needed in a chemical reaction, using a BALANCED chemical equation. Mole-Mole Consider the equation below: ___N + _3_H ___H 2(g) _1_N 2(g) _2_NH 3(g) 2(g) ___NH 2(g) 3(g) Balance it 1 st 1: 3: 2 Mole to mole ratio: _________ We can make a series of conversion factors using the above mole to mole ratio: 1 N 2 3 H 2 2 NH 3 1 N 2 2 NH 3 3 H 2 _1_N 2(g) + _3_H 2(g) _2_NH 3(g) Using the mole to mole ratio in conversion factor form. How many moles of nitrogen gas would you need to have in -order to make 10 moles of ammonia gas? 10 moles NH 3 x 1 mole N 2 2 mole NH 3 = 5 moles N 2 _1_N 2(g) + _3_H 2(g) _2_NH 3(g) How many moles of ammonia gas can you make with 12 moles of hydrogen gas? 12 moles H 2 x 2 moles NH 3 = 8 moles NH 3 3 moles H 2 __1_Fe _____Fe ___C _3_CO __CO ++ _2_Fe __Fe 2 O 2 O 3 3+ +_3_C Balance it 1 st. What is the mole to mole ratio? 1: 3: 3: 2 If you had 3 moles of Fe 2 O 3 how many moles of Fe can you produce? 3 moles Fe 2 O 3 x 2 mole Fe = 6 moles Fe 1 mole Fe 2 O 3 __1_Fe 2 O 3 + _3_CO + _2_Fe How many moles of C is needed to react completely with 4 moles of Fe 2 O 3? 4 moles Fe 2 O 3 x 3 moles C = 12 moles C 1 mole Fe 2 O 3 Mass to mass calculations. You can also do stoichiometry using gram to gram calculations, BUT you MUST always use the mole to mole ratio as a conversion between the gram to gram calculations. _1_N 2(g) + _3_H 2(g) _2_NH 3(g) 1 st let’s balance it and figure out the mole to mole ratio: 2 nd find the molar mass for N 2_28. 01 g, H 2__2. 01_g, and NH 3__17. 03_g 