Steps for NMR Experiments small molecule Casper Wu
- Slides: 46
Steps for NMR Experiments small molecule 吳英彥 Casper Wu
OUTLINE 1. 樣品配製 2. 儀器選擇 3. NMR探頭選擇 4. 勻場 5. 1 D 1 H NMR 6. 1 D 13 C NMR 7. 2 D homonuclear NMR 8. 2 D heteronuclear NMR
2. 2 儀器選擇(靈敏度) For 1 H: = 26753 (s-1 Gauss-1) = 2. 6753 (s-1 Tesla-1) (1 Tesla = 104 Gauss) when Bo = 4. 69 T E = h = ( h. Bo)/2 = Bo/2 = 2 108 (s-1) = 200 MHz
2. 3 儀器選擇(靈敏度) Boltzmann equation: N /N = exp(- E/k. T) = exp[( h. Bo)/(2 k. T)] when Bo = 4. 69 T (200 MHz) N /N = 0. 999967 i. e. N = 106 N = 1000033 when Bo = 9. 38 T (400 MHz) N = 106 N = 1000066 field 2 sensitively 2
2. 4 儀器選擇(鑑別度) 600 MHz 500 MHz n-butyl acetate 400 MHz 300 MHz ppm Hz
2. 5 儀器選擇(鑑別度) 500 MHz 400 MHz uridine 300 MHz
3. 1 NMR探頭選擇 Inverse 1 H/2 D X gradient and 1 H sensitivity 50% Observe X 1 H/2 D gradient
3. 2 NMR探頭選擇 Fixed-channel probe Ø SEL: 1 H selective Ø DUL: 13 C and 1 H (inner 13 C, outer 1 H) Ø SEI: selective inverse (inner 1 H, outer X) Ø TXO: triple resonance observe Ø TXI: triple resonance inverse Ø QXI: quattro resonance inverce
3. 3 NMR探頭選擇 Broad-band probe Ø BBO: broad band observe Ø BBI: broad band inverse Ø TBO: tripe resonance broad band observe Ø TBI: tripe resonance broad band inverse Ø QNP: quattro nucleus probe (1 H/13 C/19 F/31 P, 1 H/13 C/15 N/31 P)
3. 5 NMR探頭選擇 ns = 100 exp. time = 11 min NS = 20000 exp. time = 14 hrs 3 mg sample
3. 6 NMR探頭選擇 Gradient (磁場梯度) Z-GRAD: z gradient XYZ-G: x, y, z gradient Ø 節省 5 倍以上的實驗時間 Ø 執行自動化的勻場動作 tuning與matching數值 gradient 接頭 tuning matching BBO z-grad
4. 1 (Shim)
4. 2 氘鎖定 (Deuterium Lock) 勻場(Shim) B 0 = 0 CDCl 3 B 0 0 h (CDCl 3) digital & shaped pulse deuterium lock Better shimming
4. 3 勻場(Shim) Z Z 3, Z 5 -Z 2, -Z 4 Z 2, Z 4
4. 4 勻場(Shim) Z 4 Z 2 and Z 4
5. 1 1 H NMR The number of signals shows how many different kinds of protons are present. The location of the signals shows how shielded or deshielded the proton is. The intensity of the signal shows the number of protons of that type. Signal splitting shows the number of protons on adjacent atoms.
5. 2 Solvent Suppression 提高濃度較稀或高含水量之樣品的靈敏度 H 2 O suppression 25 mg uridine in D 2 O H 2 O
5. 4. 1 1 D Selective Excitation 凸顯目標、簡化問題、減少實驗時間 1 D selective TOCSY 9 7 8 12 11 9 10 8 7 4 5 6 3 12 -ionone 2 1
5. 4. 2 1 D Selective Excitation COSY, TOCSY, NOESY, ROESY Cyclosporine
5. 4. 3 1 D Selective Excitation 1 D selective TOCSY
5. 4. 4 1 D Selective Excitation 1 D selective NOESY
6. 1 13 C NMR 12 C has no magnetic spin. 13 C has a magnetic spin, but is only 1. 1% of the carbon in a sample. The gyromagnetic ratio of 13 C is one-fourth of that of 1 H. Signals are weak, getting lost in noise.
6. 2. 1 Spin-Spin Splitting It is unlikely that a 13 C would be adjacent to another 13 C, so splitting by carbon is negligible. 13 C will magnetically couple with attached protons and adjacent protons. These complex splitting patterns are difficult to interpret.
6. 2. 2 Spin-Spin Splitting 54 6 13 C{1 H} NMR (1 H decoupling) 2 1 3 4 5 3 2 1 6 ethylbenzene 54 2 1 6 3
6. 3. 1 DEPT Distortionless Enhancement by Polarization Transfer CH 3 CH 2 CH 45 CH 90 135 CH + + + CH 2 + - CH 3 + +
6. 3. 2 DEPT 區分碳的級數 4 5 3 2 1 6 ethylbenzene 5 4 6 3 2 s 1
7. 1. 1 同核J-resolved (獲得偶合常數) X M X A 2, 3 -dibromopropionic acid M A
7. 1. 2 異核J-resolved (獲得偶合常數) 4 2 11 9 10 4 8 7 5 6 3 12 -ionone 2 1 3 56 11 9 7 10 12 8 1
7. 2. 2 COSY (獲得 3 J偶合關係) 3 3 1 2 5 4 6 n-butyl acetate 3 1 6 4 5
7. 2. 2 COSY 90 (獲得 3 J偶合關係) X M X A 2, 3 -dibromopropionic acid M A
7. 2. 3 COSY 45 (獲得 3 J與2 J偶合關係) M A X M X a A 2, 3 -dibromopropionic acid (a)vicinal spin-spin coupling (3 J) (b)geminal spin-spin coupling (2 J) a b
7. 3 TOCSY (獲得所有J-偶合關係) 3 3 1 2 5 4 6 n-butyl acetate 3 1 6 4 5
7. 4. 1 NOESY (獲得分子於空間中之關係) 12 1 (<5Å) 7 8 9 11 9 10 8 7 4 5 6 3 2 1 12 -ionone 9 8 11
7. 5 INADEQUATE (獲得 1 JC-C之關係) 2 5 6 4 3 1 2 3 Sucrose 5 4 6 1 5 34352 4 61 6
8. 1. 1 HMQC (獲得 1 JH-X之關係) (X = 13 C, > 0) 3 6 5 1 4 3 3 1 2 5 4 6 n-butyl acetate 2 1 6 4 5
8. 1. 2 HMQC (獲得 1 JH-X之關係) 3 1 2 9 6 3 7 4 8 5 7 9 6 uridine 8 5 2 3 5 2 6 7 99 8
8. 2 HSQC (獲得 1 JH-X之關係) (X = 15 N, < 0) 3 6 5 1 4 3 3 1 2 5 4 6 n-butyl acetate 2 1 6 4 5
8. 3. 1 HMBC (獲得n. JH-X, n 2之關係) 3 6 5 1 4 3 3 1 2 5 4 6 n-butyl acetate 2 1 6 4 5
8. 3. 2 HMBC satellite 1 3 1 2 5 4 6 6 n-butyl acetate 3 4 5
Thank You casper@rezwave. com. tw
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