Specific Heat Capacity Temperature vs Heat Temperature is
- Slides: 16
Specific Heat Capacity
Temperature vs. Heat • Temperature is the measurement of the avg. KE of the particles in matter. • Heat energy that flows from a warmer object to a cooler object.
Learning Check A. When you touch ice, heat is transferred from 1) your hand to the ice 2) the ice to your hand B. When you drink a hot cup of coffee, heat is transferred from 1) your mouth to the coffee 2) the coffee to your mouth 4
Have you ever noticed that on a hot summer day the pool is cooler than the hot cement? OR maybe that the ocean is cooler than the hot sand?
Specific Heat Capacity Specific Heat: The amount of heat required to raise the temperature of 1 gram of a substance 1 degree Celsius. Joule-SI unit for work or energy Calorie-A unit of heat and energy equal to the amount of energy requires to raise the temperature of 1 gram of water by 1° Celsius. 1 calorie = 4. 184 J 1, 000 J = 1 KJ 4, 184 J =1 Calorie
Substance Water Ethanol Aluminum Granite Iron Specific Heat J/(g°C) 4. 184 2. 44 0. 897 0. 803 0. 449
Learning Check A. A substance with a large specific heat 1) heats up quickly 2) heats up slowly B. Sand in the desert is hot in the day, and cool at night. Sand must have a 1) high specific heat 2) low specific heat Lecture. PLUS Timberlake 99 10
Equation: q = c x m x ΔT ΔT = Tfinal – Tinitial q = the heat absorbed or released c = the specific heat of the substance m = the mass of the sample in grams ΔT = change in temperature
1. ) Copper metal has a specific heat (Cp) of 0. 385 J/g⁰C. Calculate the amount of heat (J) required to raise the temperature of 22. 8 g of copper from 20. 0⁰C to 875⁰C. q = c x m x ΔT q =. 385 J/g⁰C x 22. 8 g x 875 ⁰C - 20. 0 ⁰C q = 7505. 19 J gained
2) What is the specific heat of a 25. 0 g substance that absorbs 493. 4 J, and raises the temperature from 12. 0⁰C to 34⁰C? q = c x m x ΔT 493. 4 J absorbed = c x 25. 0 g x 34 ⁰C - 12. 0 ⁰C c =. 897 J/g⁰C
3) It takes 1, 250 J of energy to heat a certain sample of pure silver from 12. 0 0 C to 15. 2 0 C. Calculate the mass of the sample of silver. q = c x m x ΔT 1250 J absorbed =. 240 J/g⁰C x m x 15. 2⁰C -12. 0 ⁰C m = 1627 g
Tomorrow… • Be read for a CHECK UP first thing tomorrow! This is how I will know if you are: – Doing your homework! – Understand the content – And what we need to review and reinforce going forward! • Now… – Use your checklist for chapter 10 to complete your flashcards, you can also look at questions that we discussed in class today. – We will come up with more flashcards during opening discussion tomorrow.
- Spcific heat of water
- Specific heat
- Specific heat calculator
- Thermodynamics chapter 4
- Specific heat capacity of lead j/kg c
- Heat capacity units
- Required practical specific heat capacity
- Specific heat capacity of bread
- Heat change unit
- Latent heat def
- Difference between heat and thermal energy
- Specific heat capacity calculator
- Thermal energy equation
- Heat capacity of rubber
- How to find the specific heat capacity
- Specific heat capacity of cheese
- Specific heat of syrup