SPECIFIC HEAT Calculations SPECIFIC HEAT CAPACITY The amount

SPECIFIC HEAT Calculations

SPECIFIC HEAT CAPACITY • The amount of heat required to raise the temperature of 1 gram of a substance 1 °C. • Symbol is c. • Unit is

SPECIFIC HEAT VALUES TO REMEMBER Liquid Water: Cwater = 4. 184 J/g°C Ice: Cwater = 2. 03 J/g°C Water Vapor (Steam): Csteam 2. 01 J/g°C

OTHER SPECIFIC HEAT VALUES Vegetable oil: 2. 00 Glass: 0. 840 Sand: 0. 290 Sodium: 1. 23 Concrete: 0. 880 H 2 gas: 14. 267 Calcium: 0. 650 Pick the item that would stay hot the longest? H 2 gas Which of these would heat up the fastest? Sand Would vegetable oil or sodium heat up slower? Vegetable oil

SPECIFIC HEAT CAPACITY FORMULA Q=mc∆t Q = heat absorbed or released m = mass c = specific heat of the substance ∆t = change in temperature

Q=MC∆T When heat (Q) is absorbed by a system, part of it (c) goes into storage as potential energy and part of it is used to make the molecules move around faster, raising the temperature (∆t).

LET’S TRY THIS How much energy would be needed to heat 450 grams of copper metal from a temperature of 25. 0ºC to a temperature of 75. 0ºC? (The specific heat of copper at 25. 0ºC is 0. 385 J/g ºC. ) q= m= c= ΔT =

EXPLANATION AND SOLVING Given mass, two temperatures, and a specific heat capacity, you have enough values to plug into the specific heat equation The change in temperature (ΔT) is: 75ºC - 25ºC = 50ºC q = m x C x ΔT. and plugging in your values you get q = (450 g) x (0. 385 J/g ºC) x (50. 0ºC) = 8700 J