Solving Systems by Graphing Warm Up Evaluate each

Solving Systems by Graphing Warm Up Evaluate each expression for x = 1 and y =– 3. 1. x – 4 y 2. – 2 x + y – 5 13 Write each expression in slopeintercept form. 3. y – x = 1 y=x+1 4. 2 x + 3 y = 6 y= 5. 0 = 5 y + 5 x y = –x Holt Mc. Dougal Algebra 1 x+2

Solving Systems by Graphing Objectives Identify solutions of linear equations in two variables. Solve systems of linear equations in two variables by graphing. Holt Mc. Dougal Algebra 1

Solving Systems by Graphing Vocabulary systems of linear equations solution of a system of linear equations Holt Mc. Dougal Algebra 1

Solving Systems by Graphing A system of linear equations is a set of two or more linear equations containing two or more variables. A solution of a system of linear equations with two variables is an ordered pair that satisfies each equation in the system. So, if an ordered pair is a solution, it will make both equations true. Holt Mc. Dougal Algebra 1

Solving Systems by Graphing Example 1 A: Identifying Solutions of Systems Tell whether the ordered pair is a solution of the given system. (5, 2); 3 x – y = 13 3 x – y =13 0 3(5) – 2 13 Substitute 5 for x and 2 for y in each equation in the system. 2– 2 0 15 – 2 13 0 0 13 13 The ordered pair (5, 2) makes both equations true. (5, 2) is the solution of the system. Holt Mc. Dougal Algebra 1

Solving Systems by Graphing Example 1 B: Identifying Solutions of Systems Tell whether the ordered pair is a solution of the given system. x + 3 y = 4 (– 2, 2); –x + y = 2 x + 3 y = 4 –x + y = 2 –(– 2) + 2 – 2 + 3(2) 4 – 2 + 6 4 4 2 2 Substitute – 2 for x and 2 for y in each equation in the system. The ordered pair (– 2, 2) makes one equation true but not the other. (– 2, 2) is not a solution of the system. Holt Mc. Dougal Algebra 1

Solving Systems by Graphing All solutions of a linear equation are on its graph. To find a solution of a system of linear equations, you need a point that each line has in common. In other words, you need their point of intersection. y = 2 x – 1 y = –x + 5 The point (2, 3) is where the two lines intersect and is a solution of both equations, so (2, 3) is the solution of the systems. Holt Mc. Dougal Algebra 1

Solving Systems by Graphing Example 2 A: Solving a System by Graphing Solve the system by graphing. Check your answer. y=x Graph the system. y = – 2 x – 3 The solution appears to be at (– 1, – 1). y=x Check Substitute (– 1, – 1) into the system. y = – 2 x – 3 y=x • (– 1, – 1) y = – 2 x – 3 (– 1) – 1 The solution is (– 1, – 1). Holt Mc. Dougal Algebra 1 (– 1) – 2(– 1) – 3 – 1 2– 3 – 1

Solving Systems by Graphing Check It Out! Example 2 a Solve the system by graphing. Check your answer. y = – 2 x – 1 y=x+5 Graph the system. The solution appears to be (– 2, 3). y=x+5 y = – 2 x – 1 Check Substitute (– 2, 3) into the system. y = – 2 x – 1 y=x+5 3 3 3 The solution is (– 2, 3). Holt Mc. Dougal Algebra 1 – 2(– 2) – 1 4 – 1 3 3 – 2 + 5 3 3

Solving Systems by Graphing Example 3: Problem-Solving Application Wren and Jenni are reading the same book. Wren is on page 14 and reads 2 pages every night. Jenni is on page 6 and reads 3 pages every night. After how many nights will they have read the same number of pages? How many pages will that be? Holt Mc. Dougal Algebra 1

Solving Systems by Graphing Example 3 Continued 1 Make a Plan Write a system of equations, one equation to represent the number of pages read by each girl. Let x be the number of nights and y be the total pages read. Total pages number is read every night plus already read. Wren y = 2 x + 14 Jenni y = 3 x + 6 Holt Mc. Dougal Algebra 1

Solving Systems by Graphing Example 3 Continued 2 Solve Graph y = 2 x + 14 and y = 3 x + 6. The lines appear to intersect at (8, 30). So, the number of pages read will be the same at 8 nights with a total of 30 pages. (8, 30) Nights Holt Mc. Dougal Algebra 1

Solving Systems by Graphing Example 3 Continued 3 Look Back Check (8, 30) using both equations. Number of days for Wren to read 30 pages. 2(8) + 14 = 16 + 14 = 30 Number of days for Jenni to read 30 pages. 3(8) + 6 = 24 + 6 = 30 Holt Mc. Dougal Algebra 1

Solving Systems by Graphing Check It Out! Example 3 Video club A charges $10 for membership and $3 per movie rental. Video club B charges $15 for membership and $2 per movie rental. For how many movie rentals will the cost be the same at both video clubs? What is that cost? Holt Mc. Dougal Algebra 1

Solving Systems by Graphing Check It Out! Example 3 Continued 1 Make a Plan Write a system of equations, one equation to represent the cost of Club A and one for Club B. Let x be the number of movies rented and y the total cost. Total cost is price for each rental plus membership fee. Club A y = 3 x + 10 Club B y = 2 x + 15 Holt Mc. Dougal Algebra 1

Solving Systems by Graphing Check It Out! Example 3 Continued 2 Solve Graph y = 3 x + 10 and y = 2 x + 15. The lines appear to intersect at (5, 25). So, the cost will be the same for 5 rentals and the total cost will be $25. Holt Mc. Dougal Algebra 1

Solving Systems by Graphing Check It Out! Example 3 Continued 3 Look Back Check (5, 25) using both equations. Number of movie rentals for Club A to reach $25: 3(5) + 10 = 15 + 10 = 25 Number of movie rentals for Club B to reach $25: 2(5) + 15 = 10 + 15 = 25 Holt Mc. Dougal Algebra 1

Solving Systems by Graphing Lesson Quiz: Part I Tell whether the ordered pair is a solution of the given system. 1. (– 3, 1); no 2. (2, – 4); yes Holt Mc. Dougal Algebra 1

Solving Systems by Graphing Lesson Quiz: Part II Solve the system by graphing. 3. y + 2 x = 9 (2, 5) y = 4 x – 3 4. Joy has 5 collectable stamps and will buy 2 more each month. Ronald has 25 collectable stamps and will sell 3 each month. After how many months will they have the same number of stamps? 4 months How many will that be? 13 stamps Holt Mc. Dougal Algebra 1

Solving Systems by Graphing Make a Graphic Organizer 1)Must fold Be Creative! 2)Must have color 3)Must write out the problem and include somewhere in the organizer 4)Must show all 3 methods of solving the problem in the organizer (Hint: All 3 answers should be the same!) Holt Mc. Dougal Algebra 1