Solving Parallel circuits How to Whiteboards Parallel circuits

Solving Parallel circuits • How to • Whiteboards

Parallel circuits have many currents, but only one voltage. How to solve: I 1 = (24 V)/(6 ) = 4 A 1. Draw/figure the currents: I 2 = (24 V)/(4 ) = 6 A 2. Add the currents through the I 3 = (24 V)/(8 ) = 3 A ammeters: A 1 = 4 + 6 + 3 = 13 A A 3 = 6 A A 2 = A 6 = 6 + 3 = 9 A V 1 = V 3 = 24 V (2 ways) A 4 = A 5 = 3 A V 3 = 0 (IR, R = 0) (ok I lied) A 1 A 2 I 1 24 V 6 A 4 I 3 A 3 4 I 2 V 1 A 6 8 V 2 V 3 A 5

Whiteboards 1|2|3|4

What are the currents through the 35, 14, and 23 resistors? (2 SF) A 2 I 3 I 1 14 35 120 V I 2 A 4 A 1 A 3 I 1 = (120 V)/(35 ) = 3. 43 A I 2 = (120 V)/(14 ) = 8. 57 A I 3 = (120 V)/(23 ) = 5. 22 A 3. 4, 8. 6, 5. 2 A 23 A 5

What are the readings on the meters? (2 SF) A 2 I 3 I 1 14 35 120 V I 2 A 4 A 1 A 3 A 1 = 3. 43 + 8. 57 + 5. 22 = 17 A A 2 = A 3 = 8. 57 + 5. 22 = 13. 8 = 14 A A 4 = 3. 43 = 3. 4 A A 5 = 5. 22 = 5. 2 A 17, 14, 3. 4, 5. 2 A 23 A 5 I 1 = 3. 43 A I 2 = 8. 57 A I 3 = 5. 22 A

What are the readings on the meters? (2 SF) A 2 A 1 I 1 72 V 18 A 1 = 4 + 3 + 2 = 9 A A 2 = 3 + 2 = 5 A A 3 = 3 A A 4 = 2 A 9. 0, 5. 0, 3. 0, 2. 0 A A 3 24 I 2 I 3 36 A 4 I 1 = 4. 0 A I 2 = 3. 0 A I 3 = 2. 0 A

What are the readings on the meters? (2 SF) A 1 A 2 17 13 2. 692 A 3. 182 A 11 35 V 2. 059 A A 4 A 3 A 1 = 2. 059 + 2. 692 = 4. 8 A A 2 =. 059 + 2. 692 + 3. 182 + 1. 522 = 9. 5 A A 3 = 3. 182 + 1. 522 = 4. 7 A A 4 = 3. 2 A 4. 8, 9. 5, 4. 7, 3. 2 A 1. 522 A V 1 23