Solving Equations with the Variable on Both Sides

Solving Equations with the Variable on Both Sides Objectives: • to solve equations with the variable on both sides. • to solve equations containing grouping symbols. • A. 4 d Solve multistep linear equations. • A. 4 f Apply these skills to solve practical problems. • A. 4 b Justify steps used in solving equations.

To solve these equations, • Use the addition or subtraction property to move all variables to one side of the equal sign. • Solve the equation using the method learned in Chapter 3 Section 3.

Let’s see a few examples: 1) 6 x - 3 = 2 x + 13 -2 x 4 x - 3 = 13 +3 +3 4 x = 16 4 4 x=4 Be sure to check your answer! 6(4) - 3 =? 2(4) + 13 24 - 3 =? 8 + 13 21 = 21

Let’s try another! 2) 3 n + 1 = 7 n - 5 -3 n 1 = 4 n - 5 +5 +5 6 = 4 n 4 4 Reduce! 3 = n 2 Check: 3(1. 5) + 1 =? 7(1. 5) - 5 4. 5 + 1 =? 10. 5 - 5 5. 5 = 5. 5

Here’s a tricky one! 3) 5 + 2(y + 4) = 5(y - 3) + 10 • Distribute first. 5 + 2 y + 8 = 5 y - 15 + 10 • Next, combine like terms. 2 y + 13 = 5 y - 5 • Now solve. (Subtract 2 y. ) 13 = 3 y - 5 (Add 5. ) 18 = 3 y (Divide by 3. ) 6=y Check: 5 + 2(6 + 4) =? 5(6 - 3) + 10 5 + 2(10) =? 5(3) + 10 5 + 20 =? 15 + 10 25 = 25

Let’s try one with fractions! 4) Steps: • Multiply each term by the least common denominator (8) to eliminate fractions. 3 - 2 x = 4 x - 6 3 = 6 x - 6 9 = 6 x so x = 3/2 • Solve for x. • Add 2 x. • Add 6. • Divide by 6.

Two special cases: 6(4 + y) - 3 = 4(y - 3) + 2 y 3(a + 1) - 5 = 3 a - 2 24 + 6 y - 3 = 4 y - 12 + 2 y 3 a + 3 - 5 = 3 a - 2 21 + 6 y = 6 y - 12 - 6 y 21 = -12 Never true! 21 ≠ -12 NO SOLUTION! 3 a - 2 = 3 a - 2 -3 a -2 = -2 Always true! We write IDENTITY.

Try a few on your own: • 9 x + 7 = 3 x - 5 • 8 - 2(y + 1) = -3 y + 1 • 8 -1 z=1 z-7 2 4

The answers: • x = -2 • y = -5 • z = 20