Solve 1 ANSWER 2 x9 3 ANSWER t

Solve. 1. ANSWER 2. x=9 3. ANSWER t = 5 4. How long would it take you To travel 2 miles going 60 mph? . ANSWER x = 6/5 ANSWER 2 minutes

Rate, Time, & Distance Problems Objective Solve word problems involving uniform motion

Uniform Motion If something is moving with UNIFORM MOTION it is moving at a speed that is not changing. n The speed stays constant through the entire trip. When solving word problems that talk about distance traveled, rate of speed, and the time it takes to make a trip, you should: n n n 1) set up a chart, 2) use the distance formula, and 3) draw a picture.

Rate Problems rate time = distance rt = d What distance would you travel in 6 hours at 60 mi/hr? Using the distance formula you can find out. n n n The distance is unknown (d). The time is 6 hours, so, t = 6. The rate is 60 mi/h, so r = 60. rxt=d 60 x 6 = d d = 360 miles

Rate Problems rate time = distance rt = d What is the average rate of speed if 275 miles are traveled in 5. 5 hours? n n n The distance is 275 miles, so d =275. The time is 5. 5 hours, so t = 5. 5. The rate is what you need to find. rxt=d r x 5. 5 = 275 d = 50 miles/hour

Rate Problems rate time = distance rt = d How long does it take to travel 288 miles at an average rate of 72 mph? n n n The distance is 288, so d = 288. The rate is 72 mi/h so, r = 72. The time is what you need to find. rxt=d d = 4 hours 72 x t = 288

There are 3 common types of uniform motion problems. D D A n e h t , hem t P d O na o s i ’ t t c i e If dir e t i s Oppo er n e h t h , t P P toge O ot n s i ach If it e y l o l t ua et equal q E t se hers, s h All ot other Motion in opposite directions Motion in the same direction A round trip

How to Set up the Chart rate time = distance rt = distance Rate Motion #1 Motion #2 Time Distance

MJ and Peter Parker leave school traveling in opposite directions. Peter is walking and MJ is biking, averaging 6 km/h more than Peter. If they are 18 km apart after 1. 5 h, what is the rate of each? Rate Time Distance MJ 6+x 1. 5 9 + 1. 5 x Peter x 1. 5 x D!! D A n e h t , P P O s ’ t i f + I = 18 MJ- 9 km/h Peter-3 km/h

Carla begins biking south at 20 km/h at noon. Dean leaves from the same point 15 min. later to catch up with her. If Dean bikes at 24 km/h, how long will it take him to catch up with Carla? 15 min = ¼ hour Rate Time Distance Carla 20 x 20 x Dean 24 x–¼ 24 x - 6 If it’s NOT OPP, then set equally!! = 1¼ or 1 hour 15 min

Mark drove his car to the garage at 48 km/h and then walked back home at 8 km/h. The drive took 10 min less than the walk home. How far did Mark walk and for how long? 10 min = 1/6 hour There Back Rate Time Distance 48 x – 1/6 48 x - 8 8 x 8 x If it’s NOT OPP, then set equally!! = Distance = 1 3/5 mile Time = 1/5 or 12 min