- Slides: 96
Solutions Chapter 12
Classification of Matter Solutions are homogeneous mixtures
12. 1 Solution Concentration Objectives o o To express the concentration of a solution in several different ways To convert between different concentration units
12. 1 Solution Concentration o o o The composition of a solution is expressed as concentration Concentration is always expressed as the quantity of solute present in a fixed quantity of the solution or solvent Remember your definitions from Ch 4!
Solute A solute is the dissolved substance in a solution. Salt in salt water Sugar in soda drinks Carbon dioxide in soda drinks Solvent A solvent is the dissolving medium in a solution. Water in salt water Water in soda
Types of Solutions
12. 1 Solution Concentration o Although molarity (moles of solute per liter of solution) is the preferred concentration unit for stoichiometry calculations, other concentration units are important for other types of calculations n o Ex: use of molality in determining changes in boiling point and freezing point since it is not affected by changes in temperature as is molarity The following slides illustrate the numerous ways to denote concentration……
Calculations of Solution Concentration Molarity - the ratio of moles of solute to liters of solution
12. 1 Solution Concentration o Calculate the molarity of KOH in a solution prepared by dissolving 8. 23 g of KOH in enough water to form 250 m. L of solution. n o A: 0. 587 M Calculate the number of moles of solute in 33 m. L of a 3. 11 M HNO 3 solution. n A: 0. 10 mol
Calculations of Solution Concentration Mole fraction – the ratio of moles of solute to total moles of solution
Mole Fraction, cont’d • Please note that more than two substances can be involved and that the sum of all mole fractions equals 1 ΧA + ΧB + ΧC + …. . = 1 Note we used these types of calculations when we calculated partial pressures of one component in a gas mixture
12. 1 Solution Concentration o What is the mole fraction of each gas in a mixture that contains 2. 3 g of neon, 0. 33 g of xenon, and 1. 1 g of argon? n A: Moles of each are as follows: Ne: 0. 114 moles Xe: 0. 0025 moles and Ar: 0. 0275 moles Therefore mole fractions are as follows: Ne: 0. 79 Xe: 0. 017 Ar: 0. 19
Calculations of Solution Concentration Mass percent - the ratio of mass units of solute to mass units of solution, expressed as a percent
12. 1 Solution Concentration o Determine the mass percent of a solution prepared by dissolving 5. 00 g of Na. Cl in 200 g of water. n o A: 2. 44% A solution of a mass of 25. 0 g contains 2. 00 g of glucose. Express the concentration in mass percent of glucose. n A: 8. 00%
Calculations of Solution Concentration Molality – moles of solute per kilogram of solvent
12. 1 Solution Concentration o o Be careful not to confuse molarity (M) and molality (m) Determine the molality of the solution made with 5. 00 g of Na. Cl in 200 g of water. n o A: 0. 428 m What mass of acetic acid (CH 3 CO 2 H, molar mass = 60. 05 g/mol) must be dissolved in 250 g of water to produce 0. 150 m solution? n A: 2. 25 g
12. 1 Solution Concentration o How many grams of water must be added to 4. 00 g of urea (CO(NH 2)2); molar mass = 60. 06 g/mol) to produce a 0. 250 m solution of the compound? n A: 266 g
12. 1 Solution Concentration o o Need to be able to convert from one concentration designation to another Remember to write the given concentration as a fraction and the desired units as a fraction and figure out how to get from point A to point B
12. 1 Solution Concentration o Find the (a) molality and (b) mole fraction of a 24. 5% solution of ammonia (NH 3) in water n o A: (a) 19. 0 m (b) 0. 256 Find the molarity of a 3. 10 molal aqueous ammonia solution that has a density of 0. 977 g/m. L. n A: 2. 88 M
12. 2 Principles of Solubility Objectives o o To predict the relative solubilities of substances in different solvents based on solute-solvent interactions To explain how disorder is a driving force in the mixing of substances
12. 2 Principles of Solubility o o For most solutes, there is a limit to the quantity that can dissolve in a fixed volume of a given solvent. The solubility of a solute is reached when the rate of dissolution and the rate of crystallization are equal
Saturation of Solutions Ø A solution that contains the maximum amount of solute that may be dissolved under existing conditions is saturated. Ø A solution that contains less solute than a saturated solution under existing conditions is unsaturated. Ø A solution that contains more dissolved solute than a saturated solution under the same conditions is supersaturated.
12. 2 Principles of Solubility o The addition of a small quantity of solute to a solution is a simple way to distinguish among unsaturated, and supersaturated solutions
Crashing Out of a Supersaturated Solution
12. 2 Principles of Solubility o o Solutions play a major role in chemical reactions Two of the most important factors that determine whether a given substance will dissolve in a solvent include: n the enthalpy change that accompanies solutesolvent interactions and n the change in disorder
Steps in Solution Formation H 1 Expanding the solute (requires input of energy) Separating the solute into individual components H 2 Expanding the solvent (requires input of energy) Overcoming intermolecular forces of the solvent molecules H 3 Interaction of solute and solvent to form the solution (releases energy) And: ΔHsoln = ΔH 1 + ΔH 2 + ΔH 3
Fig. 12 -5, p. 477
Heat of Solution The Heat of Solution is the amount of heat energy absorbed (endothermic) or released (exothermic) when a specific amount of solute dissolves in a solvent. Substance Na. OH NH 4 NO 3 KNO 3 HCl Heat of Solution (k. J/mol) -44. 51 +25. 69 +34. 89 -74. 84
12. 2 Principles of Solubility o o Surprisingly many substances with a + ΔHsoln still dissolve spontaneously. This is due to an increase in entropy (disorder) which is favorable
12. 2 Principles of Solubility of Molecular Compounds n n When trying to predict solubility you need to ask several questions… What intermolecular forces need to be broken? What intermolecular forces are being generated? Are the entropy increases sufficient to overcome any unfavorable ΔH values?
Predicting Solubilities… o Predict the solvent of each pair in which the given compound is more soluble n CCl 4 in water or hexane (C 6 H 14) n Urea (CO(NH 2)2) in water or CCl 4 n Iodine (I 2) in benzene or water
12. 2 Principles of Solubility of Ionic Compounds in Water n Note that water surrounds ions in a sphere of hydration. n Note that the Hδ+ of water molecules are oriented towards the anions in solution and the Oδ- are oriented around the cations. n Note that disorder increases significantly when ionic solids dissolve in solution.
Predicting Solution Formation Solvent/ Solute Polar/ Nonpolar/ polar H 1 solute H 2 H 3 solvent + large - large + small + large +/small +/small + large + small +/small Hsol’n +/small Outcome Solution forms + large No solution forms +/Solution small forms + large No solution forms
12. 3 Effects of Pressure and Temperature on Solubility Objectives o o To state the effects of pressure and temperature on solubility To calculate the solubility of gases using Henry’s Law To explain why the solubilities of solids and liquids do not change appreciably with changes in pressure To relate the sign of the enthalpy of solution to the increase or decrease in solubility with temperature
12. 3 Effects of Pressure and Temperature on Solubility o Effect of Pressure on Solubility n Pressure has very little effect on the solubilities of solids and liquids n The solubility of a gas is directly proportional to its partial pressure at a given temperature / [A] is calculated via Henry’s law (CA = k. PA) k = a proportionality constant that is characteristic of the particular solute, solvent, and temperature n For gaseous solutes, an increase in pressure is relieved by additional gas dissolving in the liquid
Henry’s Law Constants
12. 3 Effects of Pressure and Temperature on Solubility o What is the molal concentration of oxygen in water at 20°C that has been saturated with air at 1 atm? Assume that the mole fraction of oxygen in air is 0. 21. o Equation: C = k. P k for oxygen at 20°C is 1. 43 x 10 -3 molal/atm P = mole fraction x total pressure = 0. 21 x 1 atm = 0. 21 atm C = 1. 43 x 10 -3 molal/atm • 0. 21 atm = 3. 0 x 10 -4 molal
12. 3 Effects of Pressure and Temperature on Solubility o What is the molal concentration of nitrogen in water at 20°C that has been saturated with air at 1 atm? Assume that the mole fraction of nitrogen in air is 0. 79. o Equation: C = k. P k for nitrogen at 20°C is 7. 34 x 10 -4 molal/atm P = mole fraction x total pressure = 0. 79 x 1 atm = 0. 79 atm C = 7. 34 x 10 -4 molal/atm • 0. 79 atm = 5. 8 x 10 -4 molal
Predicting the solubility of solids or gases with changes in temperature o o To predict solubilities, I find it helpful to think of heat as a reactant (endothermic reactions) or a product (exothermic reactions) Le Chatelier’s Principle can then be used to predict what is favored A + solvent + heat ↔ solution B + solvent ↔ solution + heat
12. 3 Effects of Pressure and Temperature on Solubility o As temperature increases, the solubility increases for any substance with an endothermic enthalpy of solution and decreases for one with an exothermic enthalpy of solution. A + solvent + heat ↔ solution B + solvent ↔ solution + heat
12. 3 Effects of Pressure and Temperature on Solubility A + solvent + heat ↔ solution B + solvent ↔ solution + heat o o o Since the enthalpy of solution for most gases in water is exothermic their solubilities decrease with an increase in temperature. The solubilities of most solids increases as the temperature of the solution increases. Some substances that appear to violate these generalizations undergo a more complex dissolution process.
12. 3 Effects of Pressure and Temperature on Solubility o The enthalpy of solution of potassium chromate (K 2 Cr. O 4) in water is +17. 4 k. J/mol. How does the solubility of this compound change when the temperature is lowered? o Decrease o At 1 atm pressure, the solubility of oxygen is 1. 43 x 10 -3 molal at 20°C and 8. 71 x 10 -4 molal at 60°C. What is the sign of the enthalpy of solution of oxygen? o Negative/Exothermic
Solubility Trends § The solubility of MOST solids increases with temperature. § The rate at which solids dissolve increases with increasing surface area of the solid. § The solubility of gases decreases with increases in temperature. § The solubility of gases increases with the pressure above the solution.
Therefore… Solids tend to dissolve best when: o Heated o Stirred o Ground into small particles Gases tend to dissolve best when: o The solution is cold o Pressure is high
12. 4 Colligative Properties of Solutions Objectives o o o To define and identify the colligative properties of solutions To relate the values of colligative properties to the concentration of solutions To calculate the molar masses of solutes from measurements of colligative properties
Colligative Properties of Solutions o Some questions to think about…. n n Why do we use Ca. Cl 2 in the winter time? Does it take longer for salted water or pure water to boil?
12. 4 Colligative Properties of Solutions o o Colligative Properties are those properties of solution that change in proportion to the concentration of solute particles and are not based upon the identity of those particles. Colligative properties include: n n Vapor Pressure Lowering Boiling Point Elevation Freezing Point Depression Osmotic Pressure
12. 4 Colligative Properties of Solutions o o All of the colligative properties fit the relationship: property = solute concentration x constant They differ in the units in which the solute concentration is expressed
12. 4 Colligative Properties of Solutions o Vapor Pressure of the Solvent n Adding a nonvolatile solute to a solvent always reduces the equilibrium vapor pressure below that of the pure solvent
Effect of solute on vapor pressure Pure Solvent Solution
12. 4 Colligative Properties of Solutions o Vapor Pressure of the Solvent o Raoult’s law expresses the relationship between vapor pressure of a pure solvent and the vapor pressure of a solution
Raoult’s Law The presence of a nonvolatile solute lowers the vapor pressure of the solvent. Psolvent = Observed Vapor pressure of the solution solvent = Mole fraction of the solvent P 0 solvent = Vapor pressure of the pure solvent
The relationship between vapor pressure of a pure solvent and the vapor pressure of a solution Psolvent = Xsolvent x P °solvent a = pure benzene mole fraction solute in b = 0. 02 c = 0. 04 d = 0. 06 e = 0. 08
12. 4 Colligative Properties of Solutions o If the term Xsolvent is replaced by (1 -Xsolute) and we rearrange the equation: ΔP = P°solvent – Psolvent = Xsolute • P°solvent
12. 4 Colligative Properties of Solutions o At 25°C the vapor pressure of pure benzene is 93. 9 torr. A solution of a nonvolatile solute in benzene has a vapor pressure of 91. 5 torr at the same temperature. What is the concentration of the solute expressed as a mole fraction? ΔP = Xsolute • P°solvent n o Xsolute = 0. 026 What is the solute concentration in a benzene solution that has a vapor pressure of 90. 6 torr at 25°C? n Xsolute = 0. 035
12. 4 Colligative Properties of Solutions o Boiling Point Elevation n Caused by the fact that solute particles “hold onto” solvent molecules and make it less likely for liquid solvent molecules to move to the gas phase n Equation: n Where ΔTb = elevation of the boiling point, m = the molality of the solute, and kbis the boiling point elevation constant depending on the solvent ΔTb = mkb
Boiling Point Elevation of Water Each mole of solute particles raises the boiling point of 1 kilogram of water by 0. 51 degrees Celsius. kb = 0. 51 C kilogram/mol m = molality of the solution i = van’t Hoff factor = 1 if a non-electrolyte is the solute
12. 4 Colligative Properties of Solutions o o A solution is prepared by dissolving 1. 00 g of a nonvolatile solute in 15. 0 g of acetic acid. The boiling point of this solution is 120. 17°C. The normal boiling point of acetic acid is 117. 90°C and kb is 3. 07°C/m. Find the molar mass of the solute. A: molar mass = 90. 1 g/mol Find the molar mass of a nonvolatile solute, if a solution of 1. 20 g of the compound dissolved in 20. 0 g of benzene has a boiling point of 80. 94 C. The normal boiling point of benzene acid is 80. 10°C and kb is 2. 53°C/m. A: molar mass = 1. 8 x 102 g/mol
12. 4 Colligative Properties of Solutions Freezing Point Depression n When a solute is present, both the vapor pressure of the solvent and the triple point temperature is lowered. As a result, freezing point is also depressed. Pressure, atm o 1 atm Temperature °C
12. 4 Colligative Properties of Solutions ΔTf = mkf n Equation: n Where ΔTf = depression of the freezing point, m = the molality of the solute, and kf is the freezing point depression constant depending on the solvent
BP Elevation & FP Depression Constants
Freezing Point Depression of Water Each mole of solute particles lowers the freezing point of 1 kilogram of water by 1. 86 degrees Celsius. kf = 1. 86 C kilogram/mol m = molality of the solution i = van’t Hoff factor = 1 if the solute is a non-electrolyte
12. 4 Colligative Properties of Solutions o o Pure ethylene dibromide freezes at 9. 80°C. A solution made by dissolving 0. 213 g of ferrocene (molecular formula Fe(C 5 H 5)2, molar mass = 186. 04 g/mol) in 10. 0 g of ethylene dibromide has a freezing point of 8. 45°C. What is the freezing point depression constant for the solvent ethylene dibromide? A: kf = 11. 8°C/m Benzophenone has a freezing point of 49. 00°C. A 0. 450 molal solution of urea in this solvent has a freezing point of 44. 59°C. Find the freezing point depression constant for the solvent benzophenone. A: kf = 9. 80°C/m
12. 4 Colligative Properties of Solutions o Osmotic Pressure n n n Semi-permeable membranes allow some substances to move across but not others and are especially important to transport in biological systems Osmosis = the diffusion of solvent across a semipermeable membrane Osmotic pressure = the pressure difference needed for no net transport of solvent to occur across a semi-permeable membrane that separates the solution from the pure solvent
Osmotic Pressure H 2 O
Osmotic Pressure Calculations = Osmotic pressure M = Molarity of the solution (= n/V) R = Gas Constant = 0. 08206 L atm/mol K i = van’t Hoff factor = 1 for non-electrolytes
12. 4 Colligative Properties of Solutions o o Of all the colligative properties, osmotic pressure is the most sensitive. Because it is so sensitive it used to measure the molar masses of very large molecules and substances that are only slightly soluble in water.
12. 4 Colligative Properties of Solutions o Hemoglobin is a large molecule that carries oxygen in human blood. A water solution that contains 0. 263 g of hemoglobin in 10. 0 m. L of solution has an osmotic pressure of 7. 51 torr at 25°C. What is the molar mass of hemoglobin? o A: molar mass = 6. 51 x 104 g/mol o A 5. 70 mg sample of a protein is dissolved in water to give 1. 00 m. L of solution. If the osmotic pressure of this solution is 6. 52 torr at 20°C, what is the molar mass of the protein? o A: molar mass = 1. 60 x 104 g/mol
12. 5 Colligative Properties of Electrolyte Solutions Objectives o o To predict the ideal van’t Hoff factor of ionic solutes To calculate the expected colligative properties for solutions of electrolytes
12. 5 Colligative Properties of Electrolyte Solutions o o o Solutions of ionic and molecular solutes behave differently. van’t Hoff (1852 -1911) noticed that the effect of some solutes on colligative properties was greater than expected van’t Hoff factor = i n n Works best for dilute electrolyte solutions = 1 for nonelectrolytes Ideal value = # of particles formed when electrolytes dissociate Ideal value of i is typically greater than the measured value of i
Dissociation Equations and the Determination of i i = 2 Na. Cl(s) Na+(aq) + Cl-(aq) Ag. NO 3(s) Ag+(aq) + NO 3 -(aq) i = 2 i = 3 Mg. Cl 2(s) Mg 2+(aq) + 2 Cl-(aq) Na 2 SO 4(s) 2 Na+(aq) + SO 42 -(aq) i = 3 Al. Cl 3(s) Al 3+(aq) + 3 Cl-(aq) i = 4
Ideal vs. Real van’t Hoff Factor The ideal van’t Hoff Factor is only achieved in VERY DILUTE solution.
12. 5 Colligative Properties of Electrolyte Solutions o o Arrange the following solutions in order of increasing osmotic pressure: 0. 02 M sucrose, 0. 02 M HNO 3, 0. 01 M Ba. Cl 2 A: 0. 02 M sucrose, 0. 01 M Ba. Cl 2 , 0. 02 M HNO 3
12. 6 Mixtures of Volatile Substances Objectives o o To calculate the vapor pressure of each component and the total vapor pressure over an ideal solution To interpret positive and negative deviations from Raoult’s law in terms of the relative strengths of the intermolecular attractions in the solution
12. 6 Mixtures of Volatile Substances o o o At times, liquid solutions can contain two or more volatile components. Raoult’s Law can be modified to account for more than one volatile component in a solution The vapor over a solution of two volatile components contains a larger fraction of the more volatile substance than does the solution.
Liquid-liquid solutions in which both components are volatile Modified Raoult's Law: P 0 is the vapor pressure of the pure solvent PA and PB are the partial pressures
Pressure (torr) Vapor Pressure of an Ideal Solution Total Pressure Benzene Toluene Mole fraction of toluene
12. 6 Mixtures of Volatile Substances o At 60°C the vapor pressure of benzene is 384 torr and that of toluene is 133 torr. A mixture is made by combining 1. 20 mol of toluene with 3. 60 mol of benzene. Find: (a) The mole fraction of toluene in the liquid (b) The partial pressure of toluene above the liquid (c) The partial pressure of benzene above the liquid (d) The total vapor pressure (e) The mole fraction of toluene in the vapor phase
12. 6 Mixtures of Volatile Substances o o o It is important to note that not all volatile components behave ideally throughout the range of composition (mole fraction = 0 to mole fraction = 1) Positive deviations indicate the observed vapor pressure is greater than expected. n Occurs when A-B interactions are weaker than the average of the attractions in the pure components of the mixture Negative deviations indicate the observed vapor pressure is less than expected n Occurs when intermolecular forces between dissimilar molecules are stronger than the average intermolecular forces in the pure substances
Positive Deviations from Raoult’s Law Weak solute-solvent interaction results in a vapor pressure higher than predicted Endothermic mixing = Positive deviation
Negative Deviations from Raoult’s Law Strong solute-solvent interaction results in a vapor pressure lower than predicted Exothermic mixing = Negative deviation
12. 6 Mixtures of Volatile Substances o o Fractional distillation allows two volatile liquids to be separated. Enrich the vapor phase with more volatile compound during each successive evaporation/condensation step
12. 6 Mixtures of Volatile Substances o Azeotrope n n n Many liquids form constant boiling mixtures called azeotropes The composition of the liquid and vapor phases are the same Complete separation of volatile liquids that form an azeotrope cannot be achieved by fractional distillation
12. 6 Mixtures of Volatile Substances Pressure Example of an azeotrope: HNO 3 1 atm 0. 4 Mole fraction of HNO 3 1. 0
o Additional slides follow that review some other terms/examples related to solutions but are not presented in Reger’s Ch 12….
Definition of Electrolytes and Nonelectrolytes An electrolyte is: A substance whose aqueous solution conducts an electric current. A nonelectrolyte is: A substance whose aqueous solution does not conduct an electric current. Try to classify the following substances as electrolytes or nonelectrolytes…
Electrolytes? 1. Pure water 2. Tap water 3. Sugar solution 4. Sodium chloride solution 5. Hydrochloric acid solution 6. Lactic acid solution 7. Ethyl alcohol solution 8. Pure sodium chloride 9.
Answers to Electrolytes ELECTROLYTES: NONELECTROLYTES: Tap water (weak) Na. Cl solution HCl solution Lactate solution (weak) Pure water Sugar solution Ethanol solution Pure Na. Cl
Electrolytes vs. Nonelectrolytes The ammeter measures the flow of electrons (current) through the circuit. If the ammeter measures a current, and the bulb glows, then the solution conducts. If the ammeter fails to measure a current, and the bulb does not glow, the solution is non-conducting.
Osmotic Pressure The minimum pressure that stops the osmosis is equal to the osmotic pressure of the solution
Suspensions and Colloids Suspensions and colloids are NOT solutions. Suspensions: The particles are so large that they settle out of the solvent if not constantly stirred. Colloids: The particles intermediate in size between those of a suspension and those of a solution.
Types of Colloids Examples Dispersing Medium Dispersed Substance Colloid Type Fog, aerosol sprays Gas Liquid Aerosol Smoke, airborn germs Gas Solid Aerosol Whipped cream, soap suds Liquid Gas Foam Milk, mayonnaise Liquid Emulsion Paint, clays, gelatin Liquid Sol Marshmallow, Styrofoam Solid Gas Solid Foam Butter, cheese Solid Liquid Solid Emulsion Ruby glass Solid sol
The Tyndall Effect Colloids scatter light, making a beam visible. Solutions do not scatter light. Which glass contains a colloid? colloid solution