Single Replacement Reactions Silver replacing Copper in reaction

  • Slides: 35
Download presentation
Single Replacement Reactions Silver replacing Copper in reaction of silver nitrate and copper Link

Single Replacement Reactions Silver replacing Copper in reaction of silver nitrate and copper Link to silver nitrate and copper

Ma Ma + Mb C

Ma Ma + Mb C

“Like replaces Like” � Element �Metals + Compound → Compound + replace metals and

“Like replaces Like” � Element �Metals + Compound → Compound + replace metals and halogens replace halogens. �MA + MBC → MAC + MB �Where MA and MB are metals, C is a nonmetal or negative polyatomic ion. �X 2 + MY → MX + Y 2 �Where M is a metal, X and Y are halogens (F, Cl, Br or I)

Example #1: Demo of Aluminum + Copper(II) chloride Al (s) + Cu. Cl 2

Example #1: Demo of Aluminum + Copper(II) chloride Al (s) + Cu. Cl 2 (aq) → � Aluminum Cu+2 Cl Copper(II) Chloride solution Blue color is due to presence of Cu+2 ion dissolved in water -1

What is the reddish solid that formed? Why has the solution turned from blue

What is the reddish solid that formed? Why has the solution turned from blue to colorless? Immediately after mixing Final appearance after 30 minutes

Predicting Products of Al + Cu. Cl 2 rxn �Neutral metals don’t dissolve; +

Predicting Products of Al + Cu. Cl 2 rxn �Neutral metals don’t dissolve; + charged metals ions do dissolve � Lines of evidence: � Reddish solid = copper � Blue color disappears = Cu+2 is disappearing � Al dissolves (clear, colorless ion in water) � Conclusion: Al has replaced Cu �Al (s) + Cu. Cl 2 (aq) →

Predicting Products of Al + Cu. Cl 2 rxn �Neutral metals don’t dissolve; +

Predicting Products of Al + Cu. Cl 2 rxn �Neutral metals don’t dissolve; + charged metals ions do dissolve � Lines of evidence: � Reddish solid = copper � Blue color disappears = Cu+2 is disappearing � Al dissolves (clear, colorless ion in water) � Conclusion: Al has replaced Cu �Al (s) + Cu. Cl 2 (aq) → Al+3 Cl-1 + Cu

Predicting Products of Al + Cu. Cl 2 rxn �Neutral metals don’t dissolve; +

Predicting Products of Al + Cu. Cl 2 rxn �Neutral metals don’t dissolve; + charged metals ions do dissolve � Lines of evidence: � Reddish solid = copper � Blue color disappears = Cu+2 is disappearing � Al dissolves (clear, colorless ion in water) � Conclusion: Al has replaced Cu �Al (s) + Cu. Cl 2 (aq) → Al+3 Cl-1 + Cu Cu. Cl 2 (aq) → Al. Cl 3 (aq) + Cu (s) � 2 Al(s) + 3 Cu. Cl 2 (aq) → 2 Al. Cl 3 (aq) + 3 Cu (s)

Halogen replaces Halogen �X 2 + MY → MX + Y 2 �Where M

Halogen replaces Halogen �X 2 + MY → MX + Y 2 �Where M is a metal, X and Y are halogens (F, Cl, Br or I) �KI(aq) + Cl 2 (aq) →

Halogen replaces Halogen �X 2 + MY → MA + Y 2 �Where M

Halogen replaces Halogen �X 2 + MY → MA + Y 2 �Where M is a metal, X and Y are halogens (F, Cl, Br or I) �KI(aq) + Cl 2 (aq) → K+1 Cl-1 + I 2 (diatomic!)

Halogen replaces Halogen �X 2 + MY → MX + Y 2 �Where M

Halogen replaces Halogen �X 2 + MY → MX + Y 2 �Where M is a metal, X and Y are halogens (F, Cl, Br or I) �KI(aq) + Cl 2 (aq) → K+1 Cl-1 + I 2 (diatomic!) �KI(aq) + Cl 2 (aq) → KCl + I 2

Halogen replaces Halogen �X 2 + MY → MX + Y 2 �Where M

Halogen replaces Halogen �X 2 + MY → MX + Y 2 �Where M is a metal, X and Y are halogens (F, Cl, Br or I) �KI(aq) + Cl 2 (aq) → K+1 Cl-1 + I 2 (diatomic!) �KI(aq) + Cl 2 (aq) → KCl + I 2 � 2 KI(aq) + Cl 2 (aq) → 2 KCl + I 2 �Link to Potassium Iodide and Chlorine

HW 3 -4 � 1) HCl + Zn →

HW 3 -4 � 1) HCl + Zn →

HW 3 -4 � 2) Zn. Cl 2 + Mg →

HW 3 -4 � 2) Zn. Cl 2 + Mg →

HW 3 -4 � 3) Cl 2 + Ca. Br 2 →

HW 3 -4 � 3) Cl 2 + Ca. Br 2 →

HW 3 -4 � 1) � 2) � 3) � 4) � 5) �

HW 3 -4 � 1) � 2) � 3) � 4) � 5) � 6) HCl + Zn → Zn. Cl 2 + Mg → Cl 2 + Ca. Br 2 → Al + Sn. Cl 2 → F 2 + Na. Cl → Br 2 + KI →

HW 3 -4 � 1) 2 HCl + Zn → Zn. Cl 2 +

HW 3 -4 � 1) 2 HCl + Zn → Zn. Cl 2 + H 2 � 2) Zn. Cl 2 + Mg → Mg. Cl 2 + Zn � 3) Cl 2 + Ca. Br 2 → Ca. Cl 2 + Br 2 � 4) 2 Al + 3 Sn. Cl 2 → 2 Al. Cl 3 + 3 Sn � 5) F 2 + 2 Na. Cl → 2 Na. F + Cl 2 � 6) Br 2 + 2 KI → 2 KBr + I 2

Combustion of Acetylene Ca. C 2 + 2 H 2 O → Ca(OH)2 +

Combustion of Acetylene Ca. C 2 + 2 H 2 O → Ca(OH)2 + C 2 H 2 + 5 O 2 → 4 CO 2 + Video link Woz video link H 2 O

Link. Check: to reaction animations Concept For each rxn identify the pattern and write

Link. Check: to reaction animations Concept For each rxn identify the pattern and write the products. Balance final equation. 1) 2 C 3 H 8 O +9 O 2 → 63 CO 2 + 8 4 H 2 O COMBUSTION OF A HYDROCARBON 2) 3 Mg + N 2 → Mg+2 N-3 SYNTHESIS ∆ 3) Sn. Br 4 → Sn + 2 Br 2 DECOMPOSITION → Mg 3 N 2

4) F 2 + 2 KBr → K KF F-1 + Br 2 2

4) F 2 + 2 KBr → K KF F-1 + Br 2 2 +1 SINGLE REPLACEMENT

Activity Series �Some processes are spontaneous in one direction but not the other �

Activity Series �Some processes are spontaneous in one direction but not the other � Example: Rock can fall from a cliff to the ground, but a rock on the ground can’t climb the cliff by itself.

Single replacement rxns will run in one direction but not the other �Example: Mg

Single replacement rxns will run in one direction but not the other �Example: Mg + 2 HCl → Mg. Cl 2 + H 2 �But Mg. Cl 2 + H 2 → No reaction �Link to Mg. Cl 2 + H 2 video Mg + HCl Energy Mg. Cl 2 + H 2 Rxn Progress

Data from your lab Metal Mg+2 (Mg. Cl 2) Cu+2 (Cu. Cl 2) Zn+2

Data from your lab Metal Mg+2 (Mg. Cl 2) Cu+2 (Cu. Cl 2) Zn+2 (Zn. SO 4) Mg X + Cu NR X NR Zn NR + X X = not tested NR = No reaction + + = reaction Link to activity series animations Mg + Cu. Cl 2 → +2 -1 Mg Cl + Cu

Data from your lab Metal Mg+2 (Mg. Cl 2) Cu+2 (Cu. Cl 2) Zn+2

Data from your lab Metal Mg+2 (Mg. Cl 2) Cu+2 (Cu. Cl 2) Zn+2 (Zn. SO 4) Mg X + Cu NR X NR Zn NR + X X = not tested NR = No reaction + + = reaction Link to activity series animations Mg + Cu. Cl 2 → → Mg Cl NR 2 + Cu

Using an activity series chart (table 3 -3) to predict whether a rxn will

Using an activity series chart (table 3 -3) to predict whether a rxn will occur �Is the element in reaction a metal or a halogen? (To decide which chart column to use) �What is the metal or halogen in the compound? �If the element is higher on the activity chart than the metal or halogen in the compound the reaction will occur.

Example #1: Will the following rxn occur? � Ag + HCl → � Step

Example #1: Will the following rxn occur? � Ag + HCl → � Step #1: Element is Ag = metal � Step #2: Metal in compound is always first element in formula = H. � On metal activity chart, is element, Ag, higher than No, Ag H? is lower No reaction will occur. Link to animation activity series

Example #2: Will a rxn occur? � F 2 + KCl → � Step

Example #2: Will a rxn occur? � F 2 + KCl → � Step #1: Element = F 2, a halogen � Step #2: Halogen is formula is always second = Cl � Step #3: Is element (F) higher than halogen (Cl) in compound? � Yes; rxn will occur. � Products: Cl 2 and KF

Applications of Activity Series: A more active metal being used to protect a metal

Applications of Activity Series: A more active metal being used to protect a metal supporting a structure � Using Zinc (more active) to protect iron (less chemically active but physically stronger); the iron inside the concrete is helping to support the weight of the bridge

HW 3 -5 � 1) Ni + Mg. SO 4 → � 2) Mg

HW 3 -5 � 1) Ni + Mg. SO 4 → � 2) Mg + Ni. SO 4 →

HW 3 -5 � 1) � Ni + Mg. SO 4 → NR (Ni

HW 3 -5 � 1) � Ni + Mg. SO 4 → NR (Ni less active than Mg) Mg + Ni. SO 4 → Mg. SO 4 + Ni � 3) Cl 2 + KI → � 4) I 2 + KCl → � 5) Cu + HCl → � 6) Ca + HCl → � 2)

HW 3 -5 � 3) Cl 2 + KI → � 4) I 2

HW 3 -5 � 3) Cl 2 + KI → � 4) I 2 + KCl →

HW 3 -5 � 3) Cl 2 + 2 KI → 2 KCl +

HW 3 -5 � 3) Cl 2 + 2 KI → 2 KCl + I 2 � (Cl is more active than I) � 4) I 2 + KCl → NR

HW 3 -5 � 1) Ni + Mg. SO 4 → � 2) Mg

HW 3 -5 � 1) Ni + Mg. SO 4 → � 2) Mg + Ni. SO 4 → � 3) Cl 2 + KI → � 4) I 2 + KCl → � 5) Cu + HCl → � 6) Ca + HCl →

HW 3 -5 � 1) Ni + Mg. SO 4 → � 2) Mg

HW 3 -5 � 1) Ni + Mg. SO 4 → � 2) Mg + Ni. SO 4 → � 3) Cl 2 + KI → � 4) I 2 + KCl → � 5) Cu + HCl → � 6) Ca + HCl →

HW 3 -5 � 1) � Ni + Mg. SO 4 → NR (Ni

HW 3 -5 � 1) � Ni + Mg. SO 4 → NR (Ni less active than Mg) Mg + Ni. SO 4 → Mg. SO 4 + Ni � 3) Cl 2 + 2 KI → 2 KCl + I 2 � 2) � (Cl is more active then I) � 4) I 2 + KCl → NR � 5) Cu + HCl → NR � 6) Ca + 2 HCl → Ca. Cl 2 + H 2