Similarity Lesson 8 2 Definition Similar polygons are
![Similarity Lesson 8. 2 Similarity Lesson 8. 2](https://slidetodoc.com/presentation_image_h/d58081756b2813bf9d09327bc1ed72aa/image-1.jpg)
![Definition: Similar polygons are polygons in which: 1. The ratios of the measures of Definition: Similar polygons are polygons in which: 1. The ratios of the measures of](https://slidetodoc.com/presentation_image_h/d58081756b2813bf9d09327bc1ed72aa/image-2.jpg)
![Similar figures: figures that have the same shape but not necessarily the same size. Similar figures: figures that have the same shape but not necessarily the same size.](https://slidetodoc.com/presentation_image_h/d58081756b2813bf9d09327bc1ed72aa/image-3.jpg)
![Proving shapes similar: 1. Similar shapes will have the ratio of all corresponding sides Proving shapes similar: 1. Similar shapes will have the ratio of all corresponding sides](https://slidetodoc.com/presentation_image_h/d58081756b2813bf9d09327bc1ed72aa/image-4.jpg)
![Example: ∆ABC ~ ∆DEF D 4 B A 5 8 6 C E 12 Example: ∆ABC ~ ∆DEF D 4 B A 5 8 6 C E 12](https://slidetodoc.com/presentation_image_h/d58081756b2813bf9d09327bc1ed72aa/image-5.jpg)
![Each pair of corresponding angles are congruent. <B <E <A <D <C <F Each pair of corresponding angles are congruent. <B <E <A <D <C <F](https://slidetodoc.com/presentation_image_h/d58081756b2813bf9d09327bc1ed72aa/image-6.jpg)
![∆MCN is a dilation of ∆MED, with an enlargement ratio of 2: 1 for ∆MCN is a dilation of ∆MED, with an enlargement ratio of 2: 1 for](https://slidetodoc.com/presentation_image_h/d58081756b2813bf9d09327bc1ed72aa/image-7.jpg)
![Given: ABCD ~ EFGH, with measures shown. 1. Find FG, GH, and EH. B Given: ABCD ~ EFGH, with measures shown. 1. Find FG, GH, and EH. B](https://slidetodoc.com/presentation_image_h/d58081756b2813bf9d09327bc1ed72aa/image-8.jpg)
![Theorem 61: The ratio of the perimeters of two similar polygons equals the ratio Theorem 61: The ratio of the perimeters of two similar polygons equals the ratio](https://slidetodoc.com/presentation_image_h/d58081756b2813bf9d09327bc1ed72aa/image-9.jpg)
![Given that ∆JHK ~ ∆POM, H = 90, J = 40, m M = Given that ∆JHK ~ ∆POM, H = 90, J = 40, m M =](https://slidetodoc.com/presentation_image_h/d58081756b2813bf9d09327bc1ed72aa/image-10.jpg)
![Given ∆BAT ~ ∆DOT OT = 15, BT = 12, TD = 9 Find Given ∆BAT ~ ∆DOT OT = 15, BT = 12, TD = 9 Find](https://slidetodoc.com/presentation_image_h/d58081756b2813bf9d09327bc1ed72aa/image-11.jpg)
- Slides: 11
![Similarity Lesson 8 2 Similarity Lesson 8. 2](https://slidetodoc.com/presentation_image_h/d58081756b2813bf9d09327bc1ed72aa/image-1.jpg)
Similarity Lesson 8. 2
![Definition Similar polygons are polygons in which 1 The ratios of the measures of Definition: Similar polygons are polygons in which: 1. The ratios of the measures of](https://slidetodoc.com/presentation_image_h/d58081756b2813bf9d09327bc1ed72aa/image-2.jpg)
Definition: Similar polygons are polygons in which: 1. The ratios of the measures of corresponding sides are equal. 2. Corresponding angles are congruent.
![Similar figures figures that have the same shape but not necessarily the same size Similar figures: figures that have the same shape but not necessarily the same size.](https://slidetodoc.com/presentation_image_h/d58081756b2813bf9d09327bc1ed72aa/image-3.jpg)
Similar figures: figures that have the same shape but not necessarily the same size. Dilation: when a figure is enlarged to be similar to another figure. Reduction: when a figure is made smaller it also produces similar figures.
![Proving shapes similar 1 Similar shapes will have the ratio of all corresponding sides Proving shapes similar: 1. Similar shapes will have the ratio of all corresponding sides](https://slidetodoc.com/presentation_image_h/d58081756b2813bf9d09327bc1ed72aa/image-4.jpg)
Proving shapes similar: 1. Similar shapes will have the ratio of all corresponding sides equal. 2. Similar shapes will have all pairs of corresponding angles congruent.
![Example ABC DEF D 4 B A 5 8 6 C E 12 Example: ∆ABC ~ ∆DEF D 4 B A 5 8 6 C E 12](https://slidetodoc.com/presentation_image_h/d58081756b2813bf9d09327bc1ed72aa/image-5.jpg)
Example: ∆ABC ~ ∆DEF D 4 B A 5 8 6 C E 12 10 F Therefore: A corresponds to D, B corresponds to E, and C corresponds to F. 1. The ratios of the measures of all pairs of corresponding sides are equal. = = =
![Each pair of corresponding angles are congruent B E A D C F Each pair of corresponding angles are congruent. <B <E <A <D <C <F](https://slidetodoc.com/presentation_image_h/d58081756b2813bf9d09327bc1ed72aa/image-6.jpg)
Each pair of corresponding angles are congruent. <B <E <A <D <C <F
![MCN is a dilation of MED with an enlargement ratio of 2 1 for ∆MCN is a dilation of ∆MED, with an enlargement ratio of 2: 1 for](https://slidetodoc.com/presentation_image_h/d58081756b2813bf9d09327bc1ed72aa/image-7.jpg)
∆MCN is a dilation of ∆MED, with an enlargement ratio of 2: 1 for each pair of corresponding sides. Find the lengths of the sides of ∆MCN. C (0, 8) E (0, 4) M (0, 0) D N (3, 0) (6, 0) MC = 8 MN = 6 CN = 10
![Given ABCD EFGH with measures shown 1 Find FG GH and EH B Given: ABCD ~ EFGH, with measures shown. 1. Find FG, GH, and EH. B](https://slidetodoc.com/presentation_image_h/d58081756b2813bf9d09327bc1ed72aa/image-8.jpg)
Given: ABCD ~ EFGH, with measures shown. 1. Find FG, GH, and EH. B 4 C 6 A 7 D FG = 6 F 9 GH = 4. 5 E 3 G H 2. Find the ratio of the perimeter of ABCD to the perimeter of EFGH. EH = 10. 5 PABCD = 20 PEFGH = 30 =2 3
![Theorem 61 The ratio of the perimeters of two similar polygons equals the ratio Theorem 61: The ratio of the perimeters of two similar polygons equals the ratio](https://slidetodoc.com/presentation_image_h/d58081756b2813bf9d09327bc1ed72aa/image-9.jpg)
Theorem 61: The ratio of the perimeters of two similar polygons equals the ratio of any pair of corresponding sides.
![Given that JHK POM H 90 J 40 m M Given that ∆JHK ~ ∆POM, H = 90, J = 40, m M =](https://slidetodoc.com/presentation_image_h/d58081756b2813bf9d09327bc1ed72aa/image-10.jpg)
Given that ∆JHK ~ ∆POM, H = 90, J = 40, m M = x+5, and m O = y, find the values of x and y. First draw and identify corresponding angles. K H M J O <J comp. <K = 50 <K = <M 50 = x + 5 45 = x P <H = <O 90 = 180 = y y
![Given BAT DOT OT 15 BT 12 TD 9 Find Given ∆BAT ~ ∆DOT OT = 15, BT = 12, TD = 9 Find](https://slidetodoc.com/presentation_image_h/d58081756b2813bf9d09327bc1ed72aa/image-11.jpg)
Given ∆BAT ~ ∆DOT OT = 15, BT = 12, TD = 9 Find the value of x(AO). A x AT = BT OT TD O 15 B 12 x + 15 = 12 15 9 T 9 D x=5 Hint: set up and use Means-Extremes Product Theorem.
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