Settlement Building 10 at MIT Geotechnical Engineering Geotechnical

Settlement Building 10 at MIT Geotechnical Engineering

Geotechnical Engineering

The building underwent differential settlement and was slightly

Settlement of building in downtown Adapazari

Geotechnical Engineering

TEORI KONSOLIDASI Proses mengecilnya volume tanah secara perlahan-lahan pada tanah jenuh dengan permebilitas rendah akibat pengaliran sebagian air pori. Proses ini berlangsung terus sampai dengan kelebihan tekanan air pori yang disebabkan oleh kenaikan tegangan total telah hilang p ANALOG KONSOLIDASI U 0 = 0 p U 1 = p p p = U 2 + p 1 p p = U 3 + p 2 U 4 = 0

Laju penurunan akibat keluarnya air pori

DOUBLE DRAINED POROUS Ht H Ht POROUS

SINGLE DRAINED POROUS H Ht TIDAK POROUS Casagrande (1938), Taylor (1948)

penurunan akibat konsolidasi

U 0 10 20 30 40 50 60 70 80 90 Tv 0 0. 008 0. 031 0. 071 0. 126 0. 197 0. 287 0. 403 0. 567 0. 848 100 ¥ U, % Casagrande (1938), Taylor (1948) 0 10 20 30 40 50 60 70 80 90 100 0 0. 2 0. 4 0. 6 Tv 0. 8 1

Casagrande dan Fadum (1940) Log-time Fitting Method H 0 0. 25 1 2. 25 4 9 16 25 36 49 64 81 100 121 144 169 196 400 1444 19. 202 19. 074 18. 712 18. 541 18. 44 18. 306 18. 237 18. 196 18. 167 18. 13 18. 107 18. 096 18. 093 18. 082 18. 075 18. 06 18. 051 18. 031 18. 53 19. 20 19. 10 18, 97 19. 00 R 0 18. 90 Settlement, mm t U=50% 18. 80 18. 70 18. 60 R 50 18. 40 18. 30 18. 09 R 100 18. 20 18. 10 0. 1 1 2, 3 10 100 Log(time), min 10000

Tv 0 0. 008 0. 031 0. 071 0. 126 0. 197 0. 287 0. 403 0. 567 0. 848 100 ¥ U, % U 0 10 20 30 40 50 60 70 80 90 100 0 0. 2 0. 197 0. 4 0. 6 Tv 0. 8 1

Taylor (1948) Square Root of Time Method U=90% 19. 4 0 0. 25 1 2. 25 4 9 16 25 36 49 64 81 100 121 144 169 196 400 1444 H 0 0. 5 1 1. 5 2 3 4 5 6 7 8 9 10 11 12 13 14 20 38 19. 202 19. 074 18. 712 18. 541 18. 44 18. 306 18. 237 18. 196 18. 167 18. 13 18. 107 18. 096 18. 093 18. 082 18. 075 18. 06 18. 051 18. 031 19. 2 19 18. 8 H, mm t 18. 6 18. 4 18. 2 18 17. 8 0 O 3, 35 5 OR = 1, 15 OP P R 10 t, mm½ 15 20

Tv 0 0. 008 0. 031 0. 071 0. 126 0. 197 0. 287 0. 403 0. 567 0. 848 100 ¥ U, % U 0 10 20 30 40 50 60 70 80 90 100 0 0. 2 0. 4 0. 6 Tv 0. 848 1

Uji Konsolidasi Di Lab Z 1 , 1 Pasir Z 2 , 2 Lapisan lempung Cc p 0=Z 1 1 + Z 2 2 p akibat bangunan Pasir H

P (k. N/m 2) Initial Dial Reading Final Dial Reading H, mm 0 25 50 100 200 400 800 0 10 10. 215 10. 351 10. 481 10. 652 10. 849 11. 05 10. 75 0 0. 215 0. 351 0. 481 0. 652 0. 849 1. 05 0. 75 20 19. 79 19. 65 19. 52 19. 35 19. 15 18. 95 19. 25 e= (H-Hs)/Hs

P Initial Dial Final Dial H, mm (k. N/m 2) Reading 0 25 50 100 200 400 800 0 10 10. 215 10. 351 10. 481 10. 652 10. 849 11. 05 10. 75 0 0. 215 0. 351 0. 481 0. 652 0. 849 1. 05 0. 75 H, mm 20 19. 79 19. 65 19. 52 19. 35 19. 15 18. 95 19. 25 e= (H-Hs)/Hs 0. 727 0. 709 0. 697 0. 685 0. 671 0. 653 0. 636 0. 662

q= 400 k. N/m 2 Cc = 0. 731 Cv = 5 E-10 m 2/det e 0 = 0. 727 q = 400 k. N/m 2 B = 2 m B= 2 m Z= 7 m B+Z= 9 m 2 (B+Z)2 = 81 m 2 = 18, 6 k. N/m 3 H 1 = 5 m pasir H 2 = 4 m = 18, 4 k. N/m 3 Cc = 0, 731 Cv = 5 X 10 -10 m 2/det p 0 = S z = 5*18, 6+2*18, 4 p 0 = p =A 0/Az*q = S= 129. 8 k. N/m 2 19. 7531 0. 1042 m 10. 4161 cm t =1272345025 det 353429. 174 jam U= 0. 45 Su = 4. 6873 14726. 2156 Hr Tv = 0. 159 40. 3458 th Ht = 2 pasir Z=7 m p 0 = p = lempung

NORMALLY CONSOLIDATED e Z p = Z Log p

OVER CONSOLIDATED e Z 0 Z 1 p 0 = Z 0 p 1 = Z 1 Log p p 0 = Z 0 > p 1 = Z 1

NORMALLY CONSOLIDATED OVER CONSOLIDATED e e e 0 Log p e Log p e e 0, 42 e Log p P 0 Log p

OVER CONSOLIDATED e e 0 0, 42 e P 0 Pc Log p

OVER CONSOLIDATED e Log p e 0, 42 e P 0 Pc Log p

e = p (k. N/m 2) H (mm) 0, 08635 x H 0 20 0 0 50 19, 649 0, 351 0, 0303 0, 696 = 0, 245 x 2, 7 100 19, 519 0, 481 0, 0415 0, 685 = 0, 662 200 19, 348 0, 652 0, 0563 0, 670 400 19, 151 0, 849 0, 0733 0, 653 800 18, 906 1, 094 0, 0945 0 19, 25 0, 75 0, 0648 0, 632 0, 662 e 0, 727 e = w Gs

e 1 = 0, 663 e 2 = 0, 641 200 600 Cc = Indeks kompresi Compresion index

p (k. N/m 2) H (mm) 0 20 50 e= 0, 08635 x H e 0 0 0, 727 19, 649 0, 351 0, 0303 0, 696 100 19, 519 0, 481 0, 0415 0, 685 200 19, 348 0, 652 0, 0563 0, 670 400 19, 151 0, 849 0, 0733 0, 653 800 18, 906 1, 094 0, 0945 0, 632 0 19, 25 0, 75 0, 0648 0, 662 av = koefisien pemampatan mv =koefisen perubahan volume