RUNWAY OBSTRUCTIONS Chapter 7 pages 274 290 Runway

RUNWAY OBSTRUCTIONS Chapter 7, pages 274 -290

Runway Obstructions w Need to provide a clear path for aircraft l l Landing Take off w According to FAR Part 77

Runway Areas 4 1 2 (1/3) 3 1 Primary Surface 2 Horizontal Surface 3 Conical Surface 4 Approach Path Figure 7 -13

Note: 5 th edition figure

Figure 7 -14 a See video

Figure 7 -14 b

Table 7 -5

Runway Areas (2/3) w Primary l l 200 ft longer than R/W at each end Width 250, 500, 1000 w Horizontal l l 150 feet above runway Width 5000, 10000 ft w Conical l l 4000 feet wide beyond horizontal 20: 1 slope w All from runway centerline w See table 7 -6 Table 7 -6

Runway Areas (3/3) l l l Length 5000, 10000, 50000 ft Slope 20: 1, 34: 1, 40/50: 1 See table 7 -6 Outer end w Approach

Example w Precision instrument runway w 600 ft AMSL w Runway length 10000 ft w Center of runway (0, 0, 600) w Coordinates of various points (1/4)

Example X: 5200 Y: 500 Z: 600 Primary surface: 200 ft from runway edge, 1000 ft wide (2/4) X: 5200 Y: 0 Z: 600

Example X: 5200 Y: 10000 Z: 750 Horizontal surface: 10000 ft wide, 150 ft above runway Conical surface: 4000 ft wide, 20: 1 slope Approach surface: 50000 ft long; outer edge 16, 000 ft (3/4) X: 5200 Y: 14000 Z: 950 X: 55200 Y: 8000 Z: 1600

Example (4/4) 5200’ Displace x coordinate for ease of computation X 2: 50000 Y 2: 8000 X 1: 0 Y 1: 500 Intersection of Primary Surface and Flight Path … Using similar triangles, (Y 2 -Y 1)/(X 2 -X 1) = (Y-Y 1)/(X-X 1) (8000 -500)/(50000 -0) = (Y-500)/(X-0) (7500)/(50000)X = (Y-500) Add back in 5200’ (3/20) X + 500 = Y X 2 + Y 2 = 100002 X’: 9803. 9 Y: 1970. 6 Z = 9803. 9* 1/50 = 196. 1 X: 15003. 9 Y: 1970. 6 Z: 796. 1 Add back in 600’ AP Elevation

Note: 5 th edition figure