REVIEW Systems of Equations 1 SOLVE BY GRAPHING
REVIEW Systems of Equations
1. SOLVE BY GRAPHING: x+y=0 2 x – y = -6
1. SOLVE BY GRAPHING: x+y=0 2 x – y = -6 ANSWER: (-2, 2)
2. SOLVE BY SUBSTITUTION: x - 5 y = 32 2 x – 9 y = 57
2. SOLVE BY SUBSTITUTION: x – 5 y = 32 2 x – 9 y = 57 ANSWER: (-3, -7)
3. SOLVE BY ELIMINATION: x + 7 y = -28 3 x – 5 y = 20
3. SOLVE BY ELIMINATION: x + 7 y = -28 3 x – 5 y = 20 ANSWER: (0, -4)
4. SOLVE BY GRAPHING: x + 3 y = -6 2 x + 6 y = 30
4. SOLVE BY GRAPHING: x + 3 y = -6 2 x + 6 y = 30 ANSWER: 0
5. SOLVE BY SUBSTITUTION: x+y=3 5 x – 4 y = 6
5. SOLVE BY SUBSTITUTION: x+y=3 5 x – 4 y = 6 ANSWER: (2, 1)
6. SOLVE BY ELIMINATION: 2 x - 3 y = -2 9 x – 10 y = 12
6. SOLVE BY ELIMINATION: 2 x - 3 y = -2 9 x – 10 y = 12 ANSWER: (8, 6)
7. SOLVE BY YOUR METHOD OF CHOICE: At the local fast food restaurant, four burgers and three fries have a total of 2290 calories. Six burgers and two fries have 2560 calories. How many calories does each item contain?
7. SOLVE BY YOUR METHOD OF CHOICE: At the local fast food restaurant, four burgers and three fries have a total of 2290 calories. Six burgers and two fries have 2560 calories. How many calories does each item contain? ANSWER: BURGERS = 310 FRIES = 350
8. SOLVE BY YOUR METHOD OF CHOICE: The Smith family went to theater to see a movie. Adult tickets cost $12 and child tickets cost $9. If they spent $72 total and purchased 7 tickets, how many of each were purchased?
8. SOLVE BY YOUR METHOD OF CHOICE: The Smith family went to theater to see a movie. Adult tickets cost $12 and child tickets cost $9. If they spent $72 total and purchased 7 tickets, how many of each were purchased? ANSWER: ADULTS = 3 CHILDREN = 4
9. SOLVE BY YOUR METHOD OF CHOICE: The cost of 12 bananas and 7 apples is $5. 36. Eight bananas and 5 apples cost $3. 68. Find the cost of each banana and each apple.
9. SOLVE BY YOUR METHOD OF CHOICE: The cost of 12 bananas and 7 apples is $5. 36. Eight bananas and 5 apples cost $3. 68. Find the cost of each banana and each apple. ANSWER: BANANA = $0. 26 APPLE = $0. 32
10. SOLVE BY YOUR METHOD OF CHOICE: Isaac has 43 nickels and quarters in his wallet (it’s very heavy). If his total amount of change is worth $7. 75, how many of each kind of coin does Isaac have?
10. SOLVE BY YOUR METHOD OF CHOICE: Isaac has 43 nickels and quarters in his wallet (it’s very heavy). If his total amount of change is worth $7. 75, how many of each kind of coin does Isaac have? ANSWER: NICKELS = 15 QUARTERS = 28
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