Replacement Analysis Fundamentals Lecture No 46 Chapter 14

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Replacement Analysis Fundamentals Lecture No. 46 Chapter 14 Contemporary Engineering Economics Copyright © 2016

Replacement Analysis Fundamentals Lecture No. 46 Chapter 14 Contemporary Engineering Economics Copyright © 2016 Contemporary Engineering Economics, 6 th edition Park Copyright © 2016 by Pearson Education, Inc. All Rights Reserved

Chapter Opening Story A university medical center is considering replacing an old steam-driven chiller

Chapter Opening Story A university medical center is considering replacing an old steam-driven chiller at $7. 7 million. q At issue: o What basis do they make the replacement decisions? o How much savings in energy cost would justify the purchase of the new absorption chiller? Contemporary Engineering Economics, 6 th edition Park Copyright © 2016 by Pearson Education, Inc. All Rights Reserved

Replacement Terminology • Defender: an old machine • Challenger: a new machine • Current

Replacement Terminology • Defender: an old machine • Challenger: a new machine • Current market value: selling price of the defender in the market place Contemporary Engineering Economics, 6 th edition Park • Sunk cost: any past cost unaffected by any future decisions • Trade-in allowance: value offered by the vendor to reduce the price of a new equipment Copyright © 2016 by Pearson Education, Inc. All Rights Reserved

Example 14. 1: Sunk Cost associated with an Asset’s Disposal q Given: o Original

Example 14. 1: Sunk Cost associated with an Asset’s Disposal q Given: o Original investment = $20, 000 o Current market value = $10, 000 o Repair cost made in the past = $5, 000 q Find: (a) Sunk cost, (b) Relevant cost for replacement analysis Contemporary Engineering Economics, 6 th edition Park Copyright © 2016 by Pearson Education, Inc. All Rights Reserved

Solution q Relevant Cost for Replacement Analysis: o o Lost investment value, $10, 000

Solution q Relevant Cost for Replacement Analysis: o o Lost investment value, $10, 000 Repair cost made, $5, 000 Total sunk cost = $15, 000 Current market value = $10, 000 Contemporary Engineering Economics, 6 th edition Park Copyright © 2016 by Pearson Education, Inc. All Rights Reserved

Opportunity Cost Approach • Basic Principle: Treat the proceeds from sale of the old

Opportunity Cost Approach • Basic Principle: Treat the proceeds from sale of the old machine as the investment required to keep the old machine. • Compute the AEC for each alternative and select the one with the minimum AEC. Contemporary Engineering Economics, 6 th edition Park Copyright © 2016 by Pearson Education, Inc. All Rights Reserved

Example 14. 2: Opportunity Cost Approach q Given: o Defender • Market price: $10,

Example 14. 2: Opportunity Cost Approach q Given: o Defender • Market price: $10, 000 • Remaining useful life: 3 years • Salvage value: $2, 500 • O&M cost: $8, 000 o Challenger • Cost: $15, 000 • Useful life: 3 years • Salvage value: $5, 500 • O&M cost: $6, 000 q Find: Replace the defender now? Contemporary Engineering Economics, 6 th edition Park Copyright © 2016 by Pearson Education, Inc. All Rights Reserved

Solution: Replace the Defender Contemporary Engineering Economics, 6 th edition Park Copyright © 2016

Solution: Replace the Defender Contemporary Engineering Economics, 6 th edition Park Copyright © 2016 by Pearson Education, Inc. All Rights Reserved

Economic Service Life • Definition: Economic service life is the remaining useful life of

Economic Service Life • Definition: Economic service life is the remaining useful life of an asset that results in the minimum annual equivalent cost. • Annual Equivalent Cost (AEC) AEC = Capital Cost + Operating Cost Contemporary Engineering Economics, 6 th edition Park Copyright © 2016 by Pearson Education, Inc. All Rights Reserved

Mathematical Relationship • Capital Cost • Operating Cost • Total Cost • Objective: Find

Mathematical Relationship • Capital Cost • Operating Cost • Total Cost • Objective: Find n* that minimizes AEC(i) Contemporary Engineering Economics, 6 th edition Park n* Copyright © 2016 by Pearson Education, Inc. All Rights Reserved

Example 14. 3: Economic Service Life for a Lift Truck q Given: o o

Example 14. 3: Economic Service Life for a Lift Truck q Given: o o I = $18, 000 i = 12% Salvage value = − 20% over the previous year O&M = $3, 000 during the first year, and 15% increase over the previous year thereafter q Find: Economic Service Life Contemporary Engineering Economics, 6 th edition Park Copyright © 2016 by Pearson Education, Inc. All Rights Reserved

Cash flows if you kept n = 1 or n = 2 • n

Cash flows if you kept n = 1 or n = 2 • n = 1: $11, 400 0 1 $3, 000 $18, 000 • n = 2: $11, 520 0 1 $3, 000 2 $3, 450 $18, 000 Contemporary Engineering Economics, 6 th edition Park Copyright © 2016 by Pearson Education, Inc. All Rights Reserved

AEC Calculation If You Kept the Truck for 2 Years q Ownership Cost q

AEC Calculation If You Kept the Truck for 2 Years q Ownership Cost q Operating Cost q Annual Equivalent Cost Contemporary Engineering Economics, 6 th edition Park Copyright © 2016 by Pearson Education, Inc. All Rights Reserved

Conversion of an Infinite Number of Replacement Cycles to Infinite AEC Streams Contemporary Engineering

Conversion of an Infinite Number of Replacement Cycles to Infinite AEC Streams Contemporary Engineering Economics, 6 th edition Park Copyright © 2016 by Pearson Education, Inc. All Rights Reserved

Economic Service Life Calculation Using Excel q Economic Service Life = 6 Years with

Economic Service Life Calculation Using Excel q Economic Service Life = 6 Years with AEC(12%) = $7, 977 q What It Really Means q You purchase a brand new lift truck for every 6 years, assuming that the future replacement cost as well as operating costs remain constant. Then the equivalent annual cost of owning and operating the truck is $7, 977. Contemporary Engineering Economics, 6 th edition Park Copyright © 2016 by Pearson Education, Inc. All Rights Reserved

Sensitivity of Economic Service Life o For an asset with non-increasing operating cost, keep

Sensitivity of Economic Service Life o For an asset with non-increasing operating cost, keep the asset as long as it lasts. o If everything remains the same, a higher interest rate will tend to extend the economic service life (or defer the replacement decision). Contemporary Engineering Economics, 6 th edition Park Copyright © 2016 by Pearson Education, Inc. All Rights Reserved