Redox Reactions Reduction Oxidation Oxidation Reduction Gain of

  • Slides: 23
Download presentation
Redox Reactions. Reduction Oxidation

Redox Reactions. Reduction Oxidation

Oxidation: Reduction: • Gain of oxygen • Loss of electrons • Gain of electrons

Oxidation: Reduction: • Gain of oxygen • Loss of electrons • Gain of electrons Increase in oxidation number Decrease in oxidation number

LEO “GER” SAYS ________ L = Losing E = Electrons O = Oxidation G

LEO “GER” SAYS ________ L = Losing E = Electrons O = Oxidation G = Gaining E = Electrons R = Reduction

OIL RIG

OIL RIG

Oxidation Numbers Rules (Look at your rule list too) The following is not a

Oxidation Numbers Rules (Look at your rule list too) The following is not a complete list of rules. • The oxidation number of an atom in an element is zero. E. g. Mg in Mg, O in O 2.

Oxidation Numbers • The oxidation numbers of atoms in a compound add up to

Oxidation Numbers • The oxidation numbers of atoms in a compound add up to zero. F -1 O -2 Oxidation state of C in CO 2? H +1 O is -2 (total = – 4) Put the +! So C must be = +4 Cl -1

Oxidation Numbers • The oxidation numbers of atoms in a compound add up to

Oxidation Numbers • The oxidation numbers of atoms in a compound add up to zero. Oxidation state of Mg in Mg. Cl 2? +2 F -1 O -2 H +1 Cl -1

Oxidation Numbers • The oxidation numbers of atoms in a compound add up to

Oxidation Numbers • The oxidation numbers of atoms in a compound add up to zero. Oxidation state of N in NH 3? -3 F -1 O -2 H +1 Cl -1

Oxidation Numbers • The oxidation numbers of atoms in an ion add up to

Oxidation Numbers • The oxidation numbers of atoms in an ion add up to the charge on the ion. F -1 O -2 Oxidation state of S in SO 42 -? H +1 O = – 2 (total -8) Cl -1 S: = +6 ? ? ? X - 8 = -2 S

2 Experiments: 1. Burning magnesium 2. Copper in silver nitrate solution • Word equation

2 Experiments: 1. Burning magnesium 2. Copper in silver nitrate solution • Word equation • Balanced symbol equation

2 Mg(s) + O 2(g) 2 Mg. O(s) Oxidized: loss of e- Reduced: gain

2 Mg(s) + O 2(g) 2 Mg. O(s) Oxidized: loss of e- Reduced: gain of e- Put the e- in. Mg O Mg 2+ +2 e+2 e O 2 -

Cu(s) + 2 Ag. NO 3(aq) Cu(NO 3 )2(aq) + 2 Ag(s) Complete the

Cu(s) + 2 Ag. NO 3(aq) Cu(NO 3 )2(aq) + 2 Ag(s) Complete the halfequations Oxidized: loss of e- Reduced: gain of e- Cu Ag+ +e- Cu 2+ +2 e- Ag

Oxidation Numbers • The oxidation numbers of atoms in an ion add up to

Oxidation Numbers • The oxidation numbers of atoms in an ion add up to the charge on the ion. F -1 O -2 Oxidation state of S in S 2 -? H +1 Cl -1 -2

Oxidation Numbers • The oxidation numbers of atoms in an ion add up to

Oxidation Numbers • The oxidation numbers of atoms in an ion add up to the charge on the ion. Oxidation state of N in NH 4+? -3 F -1 O -2 H +1 Cl -1

Oxidation Numbers and names • To avoid any confusion when an element can have

Oxidation Numbers and names • To avoid any confusion when an element can have several oxidation numbers, the oxidation number is usually mentioned in the compound’s name. In names like “elementate(X)”, the number refers to “element” and not the associated oxygens. • So if we look at some examples , we get the following names: KMn. O 4 potassium manganate(VII) Na. Cl. O 3 sodium chlorate(V) Check the POCl 2 F phosphorus(V) oxydichlorofluoride numbers. Na. H 2 PO 3 sodium dihydrogenphosphate(III) K 2 Cr 2 O 7 potassium dichromate(VI)

Oxidation #s for each? KMn. O 4 Na. Cl. O 3 POCl 2 F

Oxidation #s for each? KMn. O 4 Na. Cl. O 3 POCl 2 F Na. H 2 PO 3 K 2 Cr 2 O 7 potassium manganate(VII) sodium chlorate(V) phosphorus(V) oxydichlorofluoride sodium dihydrogenphosphate(III) potassium dichromate(VI)

Oxidation #s for each? KMn. O 4 potassium manganate(VII) Mn = +7 O -2

Oxidation #s for each? KMn. O 4 potassium manganate(VII) Mn = +7 O -2 total -8 K = ? ? ? K + 7 -8 = 0 K = +1

Oxidation #s for each? Na. Cl. O 3 sodium chlorate(V) Cl = +5 O

Oxidation #s for each? Na. Cl. O 3 sodium chlorate(V) Cl = +5 O = -2 (total -6) Na is Na + 5 – 6 = 0 Na = +1 (which it always is anyways)

Oxidation #s for each? POCl 2 F phosphorus(V) oxydichlorofluoride P = +5 F =

Oxidation #s for each? POCl 2 F phosphorus(V) oxydichlorofluoride P = +5 F = -1 O = -2 Cl = ? 2 Cl +5 -1 -2 = 0 2 Cl +2 = 0 2 Cl = -2 Cl = -1

Oxidation #s for each? Na. H 2 PO 3 P = +3 O =

Oxidation #s for each? Na. H 2 PO 3 P = +3 O = -2 (total -6) H = +1 (total +2) Na = ? ? ? Na +3 -6 +2 = 0 Na = +1 sodium dihydrogenphosphate(III)

Oxidation #s for each? K 2 Cr 2 O 7 Cr = +6 (total

Oxidation #s for each? K 2 Cr 2 O 7 Cr = +6 (total +12) O = -2 (total -14) K = ? ? ? 2 K +12 – 14 = 0 2 K = +2 K = +1 potassium dichromate(VI)

Well done!

Well done!

Try Question #1 on homeworksheet

Try Question #1 on homeworksheet