Reaction Stoichiometry Chemical reactions and equations Reactants Products

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Reaction Stoichiometry

Reaction Stoichiometry

Chemical reactions and equations Reactants Products

Chemical reactions and equations Reactants Products

Chemical reactions and equations Reactants Products CH 3 CHCH 2 + HCl CH 3

Chemical reactions and equations Reactants Products CH 3 CHCH 2 + HCl CH 3 CHCl. CH 3

The most important thing: It’s the same atoms Reactants Products CH 3 CHCH 2

The most important thing: It’s the same atoms Reactants Products CH 3 CHCH 2 + HCl CH 3 CHCl. CH 3

Chemical equation: before and after Mechanism: how you get there Step 1. Step 2.

Chemical equation: before and after Mechanism: how you get there Step 1. Step 2.

Balancing Equations: Use models CH 3 OH + O 2

Balancing Equations: Use models CH 3 OH + O 2

Balancing Equations: CH 3 CH 2 OH + O 2 CO 2 + H

Balancing Equations: CH 3 CH 2 OH + O 2 CO 2 + H 2 O

Balancing Equations: North Korean Rocket Fuel (CH 3)2 NNH 2(l) + N 2 O

Balancing Equations: North Korean Rocket Fuel (CH 3)2 NNH 2(l) + N 2 O 4(g) N 2(g) + H 2 O(g) + CO 2(g)

Reaction Stoichiometry Grams reactant Moles product Grams product CH 3 CH 2 OH +

Reaction Stoichiometry Grams reactant Moles product Grams product CH 3 CH 2 OH + 3 O 2 2 CO 2 + 3 H 2 O Balanced Equation gives mol conversion factors.

Pb(NO 3)2(aq) + 2 Na. Cl(aq) Pb. Cl 2(s) + 2 Na. NO 3(aq)

Pb(NO 3)2(aq) + 2 Na. Cl(aq) Pb. Cl 2(s) + 2 Na. NO 3(aq) If you have 5. 00 moles of Pb(NO 3)2, how many moles of Pb. Cl 2 can you make? How many moles of Na. NO 3 can you make?

If we react 115 g CH 3 CH 2 OH, what mass of H

If we react 115 g CH 3 CH 2 OH, what mass of H 2 O is formed? CH 3 CH 2 OH + 3 O 2 2 CO 2 + 3 H 2 O

Fuel Comparison: Determine the mass of CO 2 formed from burning 1. 00 kg

Fuel Comparison: Determine the mass of CO 2 formed from burning 1. 00 kg C, CH 4 and CH 3 CH 2 OH C + O 2 CO 2 CH 4 + O 2 CO 2 + H 2 O CH 3 CH 2 OH + O 2 CO 2 + H 2 O

C + O 2 CO 2

C + O 2 CO 2

CH 4 + O 2 CO 2 + H 2 O

CH 4 + O 2 CO 2 + H 2 O

Theoretical Yield and Percent Yield

Theoretical Yield and Percent Yield

What would cause the yield to be less than 100% What would cause the

What would cause the yield to be less than 100% What would cause the yield to be greater than 100%?

Using Amounts Tables: If we react 132 grams of CH 3 CH 2 OH,

Using Amounts Tables: If we react 132 grams of CH 3 CH 2 OH, how many grams of H 2 O are formed, how many grams of O 2 react? CH 3 CH 2 OH + 3 O 2 2 CO 2 + 3 H 2 O

Limiting Reactants 1. If you have 200 tires and 75 steering wheels, how many

Limiting Reactants 1. If you have 200 tires and 75 steering wheels, how many cars can you make? 1. 200 2. 75 3. 50 4. 100

A cake recipe calls for 3 eggs, 2 cups of flour, and 3 teaspoons

A cake recipe calls for 3 eggs, 2 cups of flour, and 3 teaspoons of sugar. If you have: • 9 eggs • 8 cups of flour • 12 teaspoons of sugar How many cakes can you make?

2 CO(g) + O 2(g) 2 CO 2(g) If you start with 4 CO

2 CO(g) + O 2(g) 2 CO 2(g) If you start with 4 CO molecules and 3 O 2 molecules, which mixture will result?

Determining the Limiting Reactant: If you have 5 P 4 molecules and 20 Cl

Determining the Limiting Reactant: If you have 5 P 4 molecules and 20 Cl 2 molecules, which will run out first? P 4 + 6 Cl 2 4 PCl 3

Limiting Reactants Simulation Course Website Simulations Chapter 3/Limiting Reactants

Limiting Reactants Simulation Course Website Simulations Chapter 3/Limiting Reactants

Reaction to make iron (steel) from iron ore: If you react 496 g Fe

Reaction to make iron (steel) from iron ore: If you react 496 g Fe with 122 g C, which is the limiting reactant? What amount of Fe can be produced? What mass of reactant in excess remains? 2 Fe 2 O 3 + 3 C 4 Fe + 3 CO 2

KEY: amounts reacted and formed determined from the limiting reactant. Amounts Table: 2 Fe

KEY: amounts reacted and formed determined from the limiting reactant. Amounts Table: 2 Fe 2 O 3 + 3 C 4 Fe + 3 CO 2

KEY: amounts reacted and formed determined from the limiting reactant. Amounts Table: 2 Fe

KEY: amounts reacted and formed determined from the limiting reactant. Amounts Table: 2 Fe 2 O 3 + 3 C 4 Fe + 3 CO 2

Amounts Tables 2 CO(g) + O 2(g) 2 CO 2(g) Initial Change Final

Amounts Tables 2 CO(g) + O 2(g) 2 CO 2(g) Initial Change Final

A hard somewhat Mind. Tap Question 14. 3 g CO react with 6. 48

A hard somewhat Mind. Tap Question 14. 3 g CO react with 6. 48 g H 2 O to form H 2 and CO 2. What are the masses of all species following the reaction?

Chemical Analysis: Use mass measurements to figure stuff out.

Chemical Analysis: Use mass measurements to figure stuff out.

A 5. 486 gram sample of a compound containing C, H and O is

A 5. 486 gram sample of a compound containing C, H and O is analyzed by combustion analysis and 9. 136 grams of CO 2 and 2. 993 grams of H 2 O are produced. What is the empirical formula?

A 5. 486 gram sample of a compound containing C, H and O is

A 5. 486 gram sample of a compound containing C, H and O is analyzed by combustion analysis and 9. 136 grams of CO 2 and 2. 993 grams of H 2 O are produced. What is the empirical formula?

A 5. 486 gram sample of a compound containing C, H and O is

A 5. 486 gram sample of a compound containing C, H and O is analyzed by combustion analysis and 9. 136 grams of CO 2 and 2. 993 grams of H 2 O are produced. What is the empirical formula?

Chemical Analysis A 8. 878 gram sample of manganese is heated in the presence

Chemical Analysis A 8. 878 gram sample of manganese is heated in the presence of excess sulfur. A metal sulfide is formed with a mass of 14. 06 g. Determine the empirical formula of the metal sulfide.

A sample of a substance with the empirical formula XCl 2 weighs 0. 5539

A sample of a substance with the empirical formula XCl 2 weighs 0. 5539 g. When it is dissolved in water and reacted with Ag. NO 3, all its chlorine is converted to insoluble Ag. Cl. The mass of the resulting Ag. Cl is found to be 1. 1807 g. The chemical reaction is XCl 2 + 2 Ag. NO 3 2 Ag. Cl + X(NO 3)2 (a) Calculate the formula mass of XCl 2. molar mass XCl 2 = _____ g mol 1 (b) Calculate the molar mass of X. Atomic mass X = g mol 1 X is an unknown element