Quadratic Functions 4 What is the discriminant Using

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Quadratic Functions (4) • What is the discriminant • Using the discriminant

Quadratic Functions (4) • What is the discriminant • Using the discriminant

 25 = 1 = (92) = (-4) = In +5 or -5 +1

25 = 1 = (92) = (-4) = In +5 or -5 +1 or -1 +9 or -9 can’t do What can we say about. . . To get a solution for x ?

What can we say about. . . In If it’s negative then it has

What can we say about. . . In If it’s negative then it has no solutions ---> cannot square root a negative number If it’s zero then it only has only solution

The discriminant This is the discriminant of the equation ax 2+bx+c=0

The discriminant This is the discriminant of the equation ax 2+bx+c=0

Using the discriminant The discriminant can be used to give us important information about

Using the discriminant The discriminant can be used to give us important information about the roots of our quadratic. The “roots” are basically our solutions when ax 2+bx+c=0 Roots

Which is which? b 2 -4 ac = 0 b 2 -4 ac <

Which is which? b 2 -4 ac = 0 b 2 -4 ac < 0 b 2 -4 ac > 0 b 2 -4 ac < 0 b 2 -4 ac = 0 b 2 -4 ac > 0

Using the discriminant If b 2 -4 ac > 0 Equation has two distinct

Using the discriminant If b 2 -4 ac > 0 Equation has two distinct roots. If b 2 -4 ac < 0 Equation has no real roots. If b 2 -4 ac = 0 Equation has repeated roots.

How it is used - example Calculate the discriminant of 2 x 2+7 x+7=0

How it is used - example Calculate the discriminant of 2 x 2+7 x+7=0 and hence prove 2 x 2+7 x+7 is always > 0 a = [coefficient of x 2] = 2 b = [coefficient of x] = 7 c= [constant] =7 If b 2 -4 ac < 0 b 2 - 4 ac = 72 – (4 x 2 x 7) = 49 - 56 = -7 Equation has no real roots. Therefore, doesn’t cross the x-axis and is always positive

How it is used - example For what values of ‘k’ does the equation

How it is used - example For what values of ‘k’ does the equation 2 x 2 -3 x+k=0 have real roots If b 2 -4 ac > 0 Equation has two distinct roots. a = [coefficient of x 2] = 2 b = [coefficient of x] = -3 c= [constant] =k b 2 - 4 ac > 0 (-3)2 – (4 x 2 x k) > 0 9 – 8 k >0 9 > 8 k 9/8 > k k < 9/8

Have a go For what values of ‘k’ does the equation 3 x 2

Have a go For what values of ‘k’ does the equation 3 x 2 + 5 x+k=0 have no real roots If b 2 -4 ac < 0 Equation has no distinct roots. a = [coefficient of x 2] = 3 b = [coefficient of x] = 5 c= [constant] =k b 2 - 4 ac < 0 52 – (4 x 3 x k) < 0 25 – 12 k < 0 25 < 12 k 25/12 < k k > 25/12