PVD in Discrete Fourier Transform Example 1 Discrete Slides: 10 Download presentation PVD in Discrete Fourier Transform Example 1 Discrete Fourier Transform 左聲道資料進行DFT x 0 = 20 x 1 = 30 x 2 = 40 x 3 = 50 y 0 = 20 + 30 + 40 + 50 = 140 y 1 = 20 + 30 e-2πi/4 + 40 e-4πi/4 + 50 e-6πi/4 = -20 + 20 i y 2 = 20 + 30 e-4πi/4 + 40 e-4πi*2/4 + 50 e-4πi*3/4 = -20 y 3 = 20 + 30 e-6πi/2 + 40 e-6πi*2/4 + 50 e-6πi*3/4 = -20 i 右聲道進行DFT x 0 = 90 x 1 = 80 x 2 = 70 x 3 = 60 y 0 = 90 + 80 + 70 + 60 = 300 y 1 = 90 – 80 i - 70 + 60 i = 20 – 20 i y 2 = 90 – 80 + 70 – 60 = 20 y 3 = 90 + 80 i – 70 – 60 i = 20 + 20 i 4 psychoacoustical phase threshold • 6 2d discrete fourier transformForward and inverse fourier transformDiscrete fourier transformWhat is radix 2 fftDiscrete fourier transform formulaFftshiftDiscrete fourier transformApplication of discrete fourier transformDiscrete time fourier transformImage processing and analysis birchfield pdfSinc to rect