PROGRAMMED INSTRUCTIONAL MATERIAL FOR SLOW LEARNERS The instructional

PROGRAMMED INSTRUCTIONAL MATERIAL FOR SLOW LEARNERS � The instructional material is divided into units called ‘Frames’ The learner goes through the frame. After that he is required to respond in one/two words. � The learner moves forward if he answers correctly, but is diverted to one or more remedial frames if he does not. These frames explains the matter a fresh, ask him questions to elicit the right answer and then return him to the original frame. � This cycle goes on till the learner passes through the whole instructional material at his own pace.

Instructional Material Topic – Time and Work , Time and Distance

FRAME- 1( Explanation Frame ) � Amount of work done by a person varies directly with the time taken. � Number of person performing a particular work varies inversely with time taken. � Speed and distance travelled in a particular time vary directly with each other. � Speed and time taken to cover a particular distance vary inversely with each other. � Distance travelled and time taken by (speed remaining constant) vary directly with each other.

FRAME 2 ( QUESTION) �Ramit can finish his work in 25 days, working 8 hours a day. If he wants to finish the same work in 20 days , how many hours should he work in a day.

FRAME 3 ( WORKSHEET ) � Let x hrs per day is needed to complete the work in 20 days Numbers of hrs /day _____ Number of days 25 20 � This is case of _____ variation. � So, ____× _____ = _____× ____ � X= ______

REMEDIAL FRAME 1 Numbers of hrs/ day Numbers of day 8 X 25 20

REMEDIAL FRAME 2 with explanation �This is case of inverse variation, because Ramit has to complete same work now in less days. So he should increase his working hrs per day. One quantity is increasing and another is decreasing.

REMEDIAL FRAME 3 8 × 25 = X × 20 � Because it is clear that number of working hrs/day increasing, number of days taken by him decreasing so product of different working hrs/day and corresponding days always comes to be same. �

REMEDIAL FRAME 4 SOLUTION �So, 20 x X = 8 x 25 X = 200÷ 20 = 10 �Answer : Ramit should work 10 hrs/day to complete his work in 20 days.