program Savings 40 Yearsinput output var payment savings
- Slides: 31
40年後の預金計算のプログラム program Savings 40 Years(input, output); var payment, savings, monthint, month: real; begin write. Ln('毎月いくらずつ積み立てますか?(単位:万円)'); read. Ln(payment); savings : = 0; monthint : = 0. 01; month : =1; while month <= 480 do begin savings : = savings + (savings*monthint) + payment; month : = month +1; end; write. Ln('40年後の預金残高は,', savings: 10: 2, '万円です.'); end.
プログラム First. Array program First. Array(input, output); type realarray 4 = array[1. . 4] of real; var A: realarray 4; begin A[1] : = 10; A[2] : = 10; A[3] : = 10; A[4] : = 10; end. A[1] A[2] A[3] A[4] 10. 0
プログラム First. Array’ program First. Array(input, output); type realarray 4 = array[1. . 4] of real; var A: realarray 4; i : integer; begin i : = 1; while i <= 4 do begin A[i] : = 10; i : = i + 1; end. i A[1] A[2] A[3] A[4] 1 5 4 3 2 10. 0
配列要素の画面出力 i : = 1; while i <= 4 do begin write. Ln(A[i]); i : = i + 1; end. i 1 5 4 3 2 A[1] A[2] A[3] A[4] 10 10 10. 0
プログラム Second. Array program Second. Array(input, output); type realarray 4 = array[1. . 4] of real; var A: realarray 4; i : integer; begin i : = 1; while i <= 4 do begin A[i] : = i + 10; i : = i + 1; end; 以下省略 i A[1] A[2] A[3] A[4] 1 5 4 3 2 11. 0 12. 0 13. 0 14. 0
プログラム Fill. Saving. Table program Fill. Savings. Table(input, output); type realarray 480: array[1. . 480] of real; var table: realarray 480; payment, savings, monthint: real; month: integer; (次のページへ続く)
プログラム Fill. Saving. Table (続き) (前ページからの続き) begin write. Ln('毎月いくらずつ積み立てますか?(単位:万円)'); read. Ln(payment); savings : = 0; monthint : = 0. 01; month : =1; while month <= 480 do begin savings : = savings + (savings*monthint) + payment; table[month] : = savings; month : = month +1; end.
プログラム Savings. Table (1) program Savings. Table(input, output); type realarray 480 = array[1. . 480] of real; var table: realarray 480; payment, savings, monthint: real; month: integer;
プログラム Savings. Table (2) begin write. Ln('毎月いくらずつ積み立てますか?(単位:万円)'); read. Ln(payment); savings : = 0; monthint : = 0. 01; month : =1; while month <= 480 do begin savings : = savings + (savings*monthint) + payment; table[month] : = savings; month : = month +1; end; write. Ln('40年分の貯金計画が準備できました.');
プログラム Deposit program Deposit(input, output); type realarray 4 = array[1. . 4] of real; var deposit: realarray 4; i : integer; begin i : = 1; while i <= 4 do begin write. Ln('預金額はいくらですか?'); read. Ln(deposit[i]); i : = i + 1; end. i deposit[1] deposit[2] deposit[3] deposit[4] 1 5 4 3 2 10. 0 5. 0 7. 0 12. 0
deposit[1]~deposit[4]の総和を求め る方法 sum : = 0; deposit[1] を sum に加える deposit[2] . deposit[3] deposit[2] を sum に加える deposit[4] . deposit[3] を sum に加える . deposit[1]を sum に加えるには, deposit[4] を sum に加える . sum : = sum + deposit[1]; とする. 10. 0 5. 0 7. 0 12. 0
deposit[1]~deposit[4]の総和を求め る方法 sum : = 0; sum : = sum + deposit[1]; sum : = sum + deposit[2]; sum : = sum + deposit[3]; sum : = sum + deposit[4]; deposit[1] deposit[2] deposit[3] deposit[4] 10. 0 5. 0 7. 0 12. 0 sum 34. 0 22. 0 15. 0 10. 0 0
deposit[1]~deposit[4]の総和を求め る方法 sum : = 0; i : = 1; while i <= 4 do begin sum : = sum + deposit[i]; i : = i + 1; end; deposit[1] deposit[2] deposit[3] deposit[4] 10. 0 5. 0 7. 0 12. 0 sum 34. 0 22. 0 15. 0 10 0 i 2 1 5 4 3
プログラム Sum. N program Sum. N(input, output); var i, n, sum: real; begin readln(n); sum : = 0; i : =1; while i <= n do begin sum : = sum + i; i : = i + 1; end; write. Ln('合計は,', sum: 8: 2, 'です.'); end.
プログラム Factorial program Factorial(input, output); var i, n, product: real; begin readln(n); product : = 1; i : =1; while i <= n do begin product : = product * i; i : = i + 1; end; write. Ln(n: 8: 2, 'の階乗は,', product: 8: 2, 'です.'); end.
プログラム Asequence program Asequence(input, output); var i, n: integer; Asequence: string; begin readln(n); Asequence : = ''; i : = 1; while i <= n do begin Asequence : = Asequence & 'A'; i : = i + 1; end; write. Ln('Aの列は,', Asequence, 'です.'); end.
deposit[1]~deposit[4]の最大値を求 める方法 largestsofar : = deposit[1]; deposit[1] deposit[2] i : = 2; deposit[3] while i <= 4 do deposit[4] begin if deposit[i] > largestsofar do largestsofar begin largestsofar : = deposit[i]; i end; i : = i + 1; end; 10. 0 5. 0 7. 0 12. 0 10 5 4 3 2
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