Problem 01 01 HOMEWORK01 o The oven shown

Problem 01 -01 HOMEWORK-01 o The oven shown in the figure is heated with a source having thermal flow of Q. Total thermal capacitance in the oven is C, thermal resistance between the oven and outside is R. To is the outside temperature. The temperature in the oven is T. Heat flow is set by electrical control as Q=K 1 V 1. V 1 is the actuation voltage. K 1 is the control gain. The temperature in the oven is measured as the voltage V 2 with a thermistor and V 2=K 2 T. K 2 is the sensor gain. Heat transfer between oven and outside in difference of 1 Celsius is 0. 5 k. J/s. To increase the temperature of substances up 1 Celsius in a isolated room, the necessity of heat is 2 k. J. Heat flow is Q=30 k. J/s as the voltage of 4 V is applied. Output voltage of 4 V corresponds to the temperature of 80 o. C. o Establish the closed loop block diagram. Gc(s)=Kp Answer:

Problem 01 -02 (Kuo, p. 215) Tw: Water temperature Hot water reservoir Elektro-pnoumatic transducer Controller unit Fan Heated air, TAo Air input, TAi Heat exchanger Temperature sensor, Ts Fill the missing transfer functions in the given closed loop diagram. Answer:

Problem 01 -03 The reservoir shown in the figure is filled with a source having fluid flow of Q 1. The reservoir capacity is C=A/ρg, where A is the cross-section of the reservoir, ρ is the density and g is the gravity. The output fluid flow is Q 2. The pressure loss in the output is ∆p 2=RQ 2. The water level in the reservoir is h 1. V 1 is the input voltage and V 2 is the output voltage. The open loop transfer function is given below. Qd is the disturbance. Establish the closed loop block diagram. Transfer function from Q=Q 1+Qd to h 1 : Answer:

Problem 01 -04 θL is the angular displacement of the load of JL for the system shown in the figure. Transfer function equation is given below. θr is the reference input. Kp is the control gain. Establish the closed loop block diagram. Answer: