Physics Velocity and Displacement with Acceleration Worksheet assistance

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Physics Velocity and Displacement with Acceleration Worksheet assistance

Physics Velocity and Displacement with Acceleration Worksheet assistance

Question #8 • In 1994, a human-powered submarine was designed in Boca Raton, Florida.

Question #8 • In 1994, a human-powered submarine was designed in Boca Raton, Florida. It achieved a maximum speed of 3. 06 m/s. Suppose this submarine starts from rest and accelerates at 0. 800 m/s 2 until it reaches maximum speed. The submarine then travels at constant speed for another 5. 00 s. Calculate the total distance traveled by the submarine • x =? • vi = 0 m/s • vf = 3. 06 m/s • a =. 8 m/s 2

Question #8, continued • Since we don’t have a time element, I will use

Question #8, continued • Since we don’t have a time element, I will use • • vf 2 = vi 2 + 2 ax 3. 062 = 0 + 2(. 8)x 9. 36 = 1. 6 x 5. 85 m = x • AND THEN, it travels with a constant speed for 5 s • a = 0 m/s 2 • v = x/t x = vt = (3. 06)(5) = 15. 3 m • Total distance travelled: 5. 85 + 15. 3 = 21. 15 m

Question #11 • The world’s fastest warship belongs to the United States Navy. This

Question #11 • The world’s fastest warship belongs to the United States Navy. This vessel, which floats on a cushion of air, can move as fast as 1. 7 × 102 km/h. Suppose that during a training exercise the ship accelerates +2. 67 m/s 2, so that after 15. 0 s its displacement is +6. 00 × 102 m. Calculate the ship’s initial velocity just before the acceleration. Assume that the ship moves in a straight line • a = 2. 67 m/s 2 • t = 15 s • x = 600 m • vi = ? ?

Question #11, continued • I will use the formula • x = xi +

Question #11, continued • I will use the formula • x = xi + vit + ½ at 2 • 600 = vi (15) + ½ (2. 67)(15)2 • 600 = 15 vi + 300. 375 • 299. 625 = 15 vi • 20 m/s =

Question #15 • In 1991, four English teenagers built an electric car that could

Question #15 • In 1991, four English teenagers built an electric car that could attain a speed 30. 0 m/s. Suppose it takes 8. 0 s for this car to accelerate from 18. 0 m/s to 30. 0 m/s. What is the magnitude of the car’s acceleration? • vi = 18 m/s • vf = 30 m/s • t=8 s • a = ? ?

Question #15, continued • Since displacement is not an issue here, I can use

Question #15, continued • Since displacement is not an issue here, I can use a simpler formula: • a = (vf – vi) / t • a = (30 – 18) / 8 • a = 12/ 8 • a = 1. 5 m/s 2