Phys 221 Chapter 12 Equilibrium and Elasticity adzyubenkocsub
Phys 221 Chapter 12 Equilibrium [ and Elasticity ] adzyubenko@csub. edu © 2012, 2016 A. Dzyubenko http: //www. csub. edu/~adzyubenko © 2004, 2012 Brooks/Cole 1
Static Equilibrium l The object is said to be in equilibrium, when the velocity of an object is constant (including when the object is at rest) l The object is said to be in static equilibrium, when it is at rest l We will deal only with static equilibrium 2
The First Condition of Equilibrium l l The net external force acting on an object must be zero This is a statement of translational equilibrium – the linear acceleration of the center of mass of the object must be zero when viewed from an inertial reference frame l This is a necessary, but not a sufficient, condition to ensure that an object is in static equilibrium 3
The Second Condition of Equilibrium l The resultant external torque about any axis must be zero This is a statement of rotational equilibrium – the angular acceleration about any axis must be zero l In static equilibrium the object is at rest relative to observer – the angular speed of the object is zero l 4
QQ l Consider the object subject to the two forces. Choose the correct statement with regard to this situation. (a) The object is in force equilibrium but not torque equilibrium (b) The object is in torque equilibrium but not force equilibrium (c) The object is in both force and torque equilibrium (d) The object is in neither force nor torque equilibrium 5
More About Equilibrium Conditions l We restrict our discussion to situation in which all the forces lie in the xy plane l The two conditions of equilibrium provide the equations the location of the axis of the torque equation is arbitrary! Why? 6
More About Equilibrium Conditions l If an object is in translational equilibrium, l and the net torque is zero about one axis, l then the net torque must be zero about any other axis =0 7
More on the Center of Gravity l All the various gravitational forces acting on all the various mass elements of the object are equivalent to a single gravitational force acting through the point called the center of gravity l Need only to consider the force Mg acting at the center of gravity to compute the torque due to the gravitational force Fg 8
More on the Center of Gravity, cont l As long as g is uniform over the entire object the center of gravity is located at the center of mass of an object Similarly for 9
Conceptual Example l This one-bottle wine holder is a surprising display of static equilibrium. Why does the bottle remain at rest? 10
Problem Solving Strategy Objects in Static Equilibrium l Draw a simple, neat diagram of the system l Isolate the object being analyzed. Draw a freebody diagram l Show and label all external forces acting on the object, indicating where those forces are applied l Try to guess the correct direction for each force 11
Problem Solving Strategy Objects in Static Equilibrium l Establish a convenient coordinate system and find the components of the forces on the object along the two axis l Apply the first condition for equilibrium. Remember to keep track of the signs of the various force component 12
Problem Solving Strategy Objects in Static Equilibrium l Choose a convenient axis for calculating the net torque on the object. Choose an origin that simplifies your calculations as much as possible l The first and the seconditions for equilibrium give a set of linear equations containing several unknowns, and these equations can be solved simultaneously 13
Example: The Leaning Ladder l A uniform ladder of length l rests against a smooth, vertical wall. If the mass of the ladder is m and coefficient of static friction is µs, find the minimum angle Θmin at which the ladder does not slip 14
Elastic Properties: This is an optional Reading Assignment 15
Elastic Properties of Solids l l l In reality, it is possible to change the shape or the size (or both) of an object by applying external force As these changes take place internal forces in object resist the deformation Stress is a quantity that is proportional to the force causing a deformation The result of stress is strain – a measure of the degree of deformation For sufficient small stresses, strain is proportional to stress 16
Elastic Modulus l The elastic modulus is defined as the ratio of the stress to the resulting strain l Depends on the material being deformed and the nature of the deformation 17
Three Types of Deformation l Young’s modulus, which measures the resistance of a solid to a change in its length l Shear modulus, which measures the resistance to motion of the plains within a solid parallel to each other l Bulk modulus, which measures the resistance of solids or liquids to change in their volume 18
Young’s Modulus: Elasticity in Length l The tensile stress F/A is the ratio of the magnitude of the external force F to the crosssectional area A The tensile strain is the ratio of the change in length ΔL to the original length Li l Young’s modulus is l 19
Young’s Modulus, cont Y is typically used to characterize a rod or wire stressed under either tension or compression l Units of Y: N/m 2 20 l
Elastic Limit l Elastic limit of a substance is the maximum stress that can be applied to the substance before it comes permanently deformed and does not return to its initial length straight line 21
Shear Modulus: Elasticity of Shape l The shear stress F/A is the ratio of the tangential force to the area A of the face being sheared l The shear strain is the ratio Δx /h, where Δx is the horizontal distance that the sheared face moves and h is the height of the object l Shear modulus 22
Bulk Modulus: Volume Elasticity l The response of an object to changes in a force of uniform magnitude applied perpendicularly over the entire surface of the object immersed in fluid l an object undergoes a change in volume but no change in shape l l The volume stress the ratio of the magnitude of the total force F exerted on a surface to the area A of the surface l l The quantity P = F/A is called pressure The volume strain is equal to the change in volume ΔV 23 divided by the initial volume Vi
Bulk Modulus: Volume Elasticity, cont l Bulk modulus An increase in pressure causes a decrease in volume => B is a positive number l The reciprocal of the bulk modulus is called the compressibility of the material l Both solids and liquids have a bulk modulus l l No shear modulus and no Young’s modulus for liquids 24
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