PERIMETER OF IRREGULAR FIGURES WARMUP FIND THE PERIMETER

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PERIMETER OF IRREGULAR FIGURES

PERIMETER OF IRREGULAR FIGURES

WARM-UP FIND THE PERIMETER OF THE SQUARE 1 ¼ + 1 ¼ = 5

WARM-UP FIND THE PERIMETER OF THE SQUARE 1 ¼ + 1 ¼ = 5 inches 1 ¼ inches or 4(1 ¼ ) = 5

THE WIDTH OF A RECTANGLE IS 12 CM. WHAT IS THE PERIMETER OF THE

THE WIDTH OF A RECTANGLE IS 12 CM. WHAT IS THE PERIMETER OF THE RECTANGLE IF THE LENGTH IS 3 TIMES THE WIDTH? Step 1: Find the length Length = 3 w Length = 3 x 12 3 w Substitute w for 12 Length = 36 centimeters 12 cm Step 2: Find the Perimeter 2(3 w) + 2(12)= 2 (3 *12) + 2 (12) = 2( 36) + 2 ( 12) = 72 + 24= 96

FIND THE PERIMETER OF THIS IRREGULAR FIGURE 11 cm 6 cm 13 cm Missing

FIND THE PERIMETER OF THIS IRREGULAR FIGURE 11 cm 6 cm 13 cm Missing measurement? 8 cm Missing measurement? Missing Measurement: 3 cm Missing Measurement: 7 cm Perimeter: 11+ 6 + 3 + 7+ 8+ 13 = 48 cm

PERIMETER OF IRREGULAR FIGURES 22 mm 7. 35 mm 28. 25 mm 46 mm

PERIMETER OF IRREGULAR FIGURES 22 mm 7. 35 mm 28. 25 mm 46 mm Missing Measurement: 24 mm Missing Measurement: 22. 00 35. 60 7. 35 24. 00 28. 25 46. 00 + 35. 60 163. 20 mm = Perimeter

FIND THE PERIMETER OF THE FIGURE BELOW: 3 cm 5. 5 cm Missing Side:

FIND THE PERIMETER OF THE FIGURE BELOW: 3 cm 5. 5 cm Missing Side: 17 – 5. 5 = 6 cm 17 cm 6 cm 5. 5 cm 3 cm Find the Perimeter: 17 + 3 + 5. 5 + 6 + 6 + 5. 5 + 3 = 52 cm

Mr. Bill’s backyard is in the shape of a rectangle. It took him 678

Mr. Bill’s backyard is in the shape of a rectangle. It took him 678 feet of fence to enclose his back yard. If the length of the yard is twice as long as the width, the width being 113 feet long. What is the length of Mr. Bill’s yard?

WHAT IS THE LENGTH OF SIDE X, IF THE PERIMETER IS 900 MILLIMETERS? 135

WHAT IS THE LENGTH OF SIDE X, IF THE PERIMETER IS 900 MILLIMETERS? 135 + 211 + X = 900 mm 135 mm 211 mm X 692 + X = 900 mm - 692 -692 X= 208 mm