Percent Composition Empirical Formulas Molecular Formulas Percent Composition

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Percent Composition, Empirical Formulas, Molecular Formulas

Percent Composition, Empirical Formulas, Molecular Formulas

Percent Composition • Percent Composition – the percentage by mass of each element in

Percent Composition • Percent Composition – the percentage by mass of each element in a compound (*note: not the ratio of elements in the compound) • Law of Definite Proportions – compounds always contain the same proportions of elements by mass. Part _______ Percent = x 100% Whole So… Percent composition Mass of element in 1 mol of a compound or = __________ x 100% Mass of 1 mol of compound molecule

Formulas Percent composition allow you to calculate the simplest ratio among the atoms found

Formulas Percent composition allow you to calculate the simplest ratio among the atoms found in compound. Empirical Formula – formula of a compound that expresses lowest whole number ratio of atoms. Molecular Formula – actual formula of a compound showing the number of atoms present Examples: C 4 H 10 - molecular C 2 H 5 - empirical C 6 H 12 O 6 - molecular CH 2 O - empirical

Formulas Is H 2 O 2 an empirical or molecular formula? Molecular, it can

Formulas Is H 2 O 2 an empirical or molecular formula? Molecular, it can be reduced to HO HO = empirical formula

Calculating Molecular Formula A white powder is analyzed and found to have an empirical

Calculating Molecular Formula A white powder is analyzed and found to have an empirical formula of P 2 O 5. The compound has a molar mass of 283. 88 g/mol. What is the compound’s molecular formula? Step 3: Multiply Step 1: Molar Mass P = 2 x 30. 97 g = 61. 94 g O = 5 x 16. 00 g = 80. 00 g 141. 94 g Step 2: Divide MM by Empirical Formula Mass 238. 88 g =2 141. 94 g (P 2 O 5)2 = P 4 O 10

Calculating Molecular Formula A compound has an experimental molar mass of 78 g/mol. Its

Calculating Molecular Formula A compound has an experimental molar mass of 78 g/mol. Its % composition is found to be 92. 24% carbon and 7. 76% hydrogen. What is its molecular formula of this compound? First, determine the empirical formula using the % composition. Empirical formula of this compound is CH. Determine the multiple C = 12. 01 g/mol H = 1. 01 g/mol 13. 02 g/mol 78 g/mol 13. 02 g/mol =6 (CH)6 = C 6 H 6

Homework: Page 298 #1 Page 300 #2

Homework: Page 298 #1 Page 300 #2