Packet 4 Page 2 lesson The mole 1

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Packet 4 Page 2 lesson

Packet 4 Page 2 lesson

The mole • 1 Mole = 6. 02 X 1023 atoms, molecules or parts

The mole • 1 Mole = 6. 02 X 1023 atoms, molecules or parts • 1 mole = mass of the substance • 1 mole of any gas at STP = 22. 4 L (this is what is new)

For any gas Therefore: At STP 1 mole of any gas = 22. 4

For any gas Therefore: At STP 1 mole of any gas = 22. 4 L of the gas **this only works at STP and with gases!!

Steps • If you only have one substance and the word mole is in

Steps • If you only have one substance and the word mole is in the problems it is 2 steps Example: 15 MOLES of hydrogen gas = ? Liters at STP

Steps • If you only have one substance and the word mole is NOT

Steps • If you only have one substance and the word mole is NOT in the problem it is 3 steps Example: 15 grams of hydrogen gas = many liters at STP?

Steps If you have two different substances in the problem and an equation it

Steps If you have two different substances in the problem and an equation it is 4 steps (stoichiometry) Example: 15 grams of zinc = liters of hydrogen gas at STP?

Examples 1. 50 grams of CO 2 gas = ? Liters fill at STP?

Examples 1. 50 grams of CO 2 gas = ? Liters fill at STP? Mole is not in the problem it is 3 steps

Examples 2. 100. 2 L of CO gas = ? grams at STP

Examples 2. 100. 2 L of CO gas = ? grams at STP

Examples Zn + HCl Zn. Cl 2 + H 2 b. 25 liters of

Examples Zn + HCl Zn. Cl 2 + H 2 b. 25 liters of hydrogen = ? G of Zn STP

Examples Zn + HCl Zn. Cl 2 + H 2 b. 25 grams of

Examples Zn + HCl Zn. Cl 2 + H 2 b. 25 grams of Zn = ? Liters of hydrogen gas at STP

PAGE 3 - CORRECTIONS • PART 2 – 1 A – 10. 5 g

PAGE 3 - CORRECTIONS • PART 2 – 1 A – 10. 5 g Ca = ? L of H 2(g) at STP – 1 B – 30. 8 L hydrogen gas = ? G of H 3 P at STP – 2 – 100 L oxygen gas = ? Grams of water at STP – PAGE 5 – IGNORE #6 LETTER A – JUST BALANCE THE EQUATION