p 01 Rate Eqn Order of Rxn C

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p. 01 Rate Eqn. & Order of Rxn C. Y. Yeung (CHW, 2009)

p. 01 Rate Eqn. & Order of Rxn C. Y. Yeung (CHW, 2009)

p. 02 Rate Equation (Rate Law) the mathematical equation relating the rate of rxn

p. 02 Rate Equation (Rate Law) the mathematical equation relating the rate of rxn to the [reactants]. Examples: 3 A + 2 B C rate x y [A] [B] order of rxn w. r. t. [A] order of rxn w. r. t. [B]

p. 03 rate x y = k[A] [B] rate constant (varies with temp. !!)

p. 03 rate x y = k[A] [B] rate constant (varies with temp. !!) * usually, order of reaction = 0, 1 or 2. Therefore, the rate equation shows that: rate of rxn is affected by [reactants] rate of rxn is affected by temperature

p. 04 Example: rate = k [A]m[B]n If [B] and temp. are kept constant,

p. 04 Example: rate = k [A]m[B]n If [B] and temp. are kept constant, when [A] doubles, rate of reaction increases 4 times. Find the value of m. rate = k’ [A]m rate 1 = k’ [A]m and rate 2 = k’ (2[A])m 1 rate 1 k’ [A]m then = = m rate 2 k’ (2[A]) 4 1 m 1 = 2 4 the rxn is 2 nd order w. r. t. [A]. m=2

p. 05 If [B] and temp. are kept constant, when [A] doubles, rate of

p. 05 If [B] and temp. are kept constant, when [A] doubles, rate of reaction increases 4 times. How to do it? [A] Expt. 1 [A]01 03 [B] Initial rate [A] 02 [B] Rate 1 [A]01 Expt. 2 [A]02 [B] Rate 2 Expt. 3 [A]03 [B] Rate 3 …. . [A] …. . t initial rate method kept constant Repeat expt. with constant [A] and different [B], find n!

Determination of k, m and n by graphical rate = k’ [A]m [A] [B]

Determination of k, m and n by graphical rate = k’ [A]m [A] [B] Initial rate Expt. 1 [A]1 [B] Rate 1 Expt. 2 [A]2 [B] Rate 2 Expt. 3 [A]3 [B] Rate 3 …. . p. 06 method Plot rate vs [A] : rate m=1 m=2 m=0 …. . [A] Only m could be found!

p. 07 rate = k’ [A]m log (rate) = m log [A] + log

p. 07 rate = k’ [A]m log (rate) = m log [A] + log k’ y = mx + c log (rate) m=2 m=1 log k’ m=0 log [A] i. e. Both k (=k’/[B]) and m could be found!

1992 Paper II, Q. 2(a) p. 08

1992 Paper II, Q. 2(a) p. 08

1992 Paper II, Q. 2(a) : Ans. p. 09

1992 Paper II, Q. 2(a) : Ans. p. 09

Differential Rate Equation: rate = - d[A] dt if m = 0 - d[A]

Differential Rate Equation: rate = - d[A] dt if m = 0 - d[A] dt = p. 10 slope of tangent at a point on the conc. - time graph. (NOT accurate!) m k’ [A] when t = 0, [A] = [A]0 = k’ - d[A] = k’dt - d[A] = k’ dt - [A] = k’t + C C = - [A]0 [A] = - k’t + [A]0 integrated rate eqn. (zeroth order) No calculation of tangent slope!

p. 11 Therefore …. for Zeroth Order Rxn Monitor the variation of conc. along

p. 11 Therefore …. for Zeroth Order Rxn Monitor the variation of conc. along with time by Chemical / Physical Method, Time [A] t 1 t 2 t 3 t 4 [A]1 [A]2 [A]3 [A]4 [A] = - k’t + [A]0 slope = - k’ t

p. 12 To conclude …. (1) Rate Equation shows that the rate of rxn

p. 12 To conclude …. (1) Rate Equation shows that the rate of rxn is affected by conc. (order) & temp (k). Find the order of rxn (m, n) by Initial Rate Method (many combinations of [A] & [B]!) Plot log (rate) = m log[A] + log k’, both m, k’ and k could be found.

p. 13 To conclude …. (2) Initial Rate Method gives Differential Rate Equation, but

p. 13 To conclude …. (2) Initial Rate Method gives Differential Rate Equation, but m and k may not be accurately found from the initial rates (=slope of tangent). Integrated Rate Equation can give better m and k, as no calculation of tangent is involved.

p. 14 To conclude …. (3) To collect data for Integrated Rate Eqn. ,

p. 14 To conclude …. (3) To collect data for Integrated Rate Eqn. , only one combination of [A] & [B] is needed. Measure [A] at different t. Integrated Rate Eqn. of Zeroth Order: [A] = -k’t + [A]0

p. 15 Next …. Integrated Rate Eqn. of 1 st and 2 nd Order

p. 15 Next …. Integrated Rate Eqn. of 1 st and 2 nd Order To study whether the decomposition of H 2 O 2 is 1 st order w. r. t. [H 2 O 2]. (expt. 8)

p. 16 Assignment Pre-lab [due date: 12/2(Thur)] p. 47 Q. 1 -6 [due date:

p. 16 Assignment Pre-lab [due date: 12/2(Thur)] p. 47 Q. 1 -6 [due date: 12/2(Thur)]