Oxidation Reduction Ch 20 Intro to Redox Why

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Oxidation & Reduction Ch 20

Oxidation & Reduction Ch 20

Intro to Redox Why do we call it “oxidation” ? ØIn the past scientists

Intro to Redox Why do we call it “oxidation” ? ØIn the past scientists believed there was a gain or loss of oxygen. This is FALSE!

Definition of Redox Reaction ØOxidation Reduction Reaction (Redox): A reaction in which electrons are

Definition of Redox Reaction ØOxidation Reduction Reaction (Redox): A reaction in which electrons are transferred from one substance to another.

Definition of Redox Reaction • Oxidation cannot occur without reduction • Definition of Oxidized:

Definition of Redox Reaction • Oxidation cannot occur without reduction • Definition of Oxidized: 1. Losing of electrons (LEO) 2. Increasing the ox. number, ie: 0 to +1 or -2 to -1 • Definition of Reduced: 1. Gaining of electrons (GER) 2. Reducing the ox. number, ie: -1 to -2 or 1 to 0

Redox Rules to memorize! The Statue of Liberty’s outer layer of copper has undergone

Redox Rules to memorize! The Statue of Liberty’s outer layer of copper has undergone redox

Oxidation Rule #1 Oxidation number of a neutral atom, molecule, or compound = zero

Oxidation Rule #1 Oxidation number of a neutral atom, molecule, or compound = zero i. e. atom: Mg, H 2, Na i. e. All H 2 O 2 N 2 Cl 2 Br 2 I 2 F 2 i. e. compounds: (the total ox#s adds up to 0 NH 3 Si. Cl 4 K 3 PO 4 H 2 O

Rule #2 Oxidation number of an ion = charge of ion i. e. monotomic:

Rule #2 Oxidation number of an ion = charge of ion i. e. monotomic: Mg+2 , O– 2, Al +3 , Br – i. e. Polyatomic: NH 4+, CO 3– 2, SO 4– 2, NO 3 –

Rule #3 The oxidation number for H is +1 Exception: when bonded to a

Rule #3 The oxidation number for H is +1 Exception: when bonded to a less electronegative element (metal), then it is -1. i. e. +1 -1 +2 -1 Li. H, Na. H, Mg. H 2 +1 -1 HF, HCl

Rule#4 Oxygen’s oxidation number is -2, in a compound Two exceptions: peroxides and fluorine

Rule#4 Oxygen’s oxidation number is -2, in a compound Two exceptions: peroxides and fluorine +1 ? = -1 in H 2 O 2 where O is -1 2(+1) + 2( ? ) = 0 +2 -1 with OF 2 ? +2(-1) = 0 where O is +2 fluorine (more electronegative)

Rule #5 • The most electronegative element fluorine ALWAYS has an oxidation number of

Rule #5 • The most electronegative element fluorine ALWAYS has an oxidation number of -1 when it is bonded to another element. • i. e. HF

Question Time Assign oxidation numbers to each element 4. Na. H 5. HCl 1.

Question Time Assign oxidation numbers to each element 4. Na. H 5. HCl 1. Cl 2 6. K 3 PO 4 2. Cl – 7. Ca. SO 4 3. Mg. Cl 2 8. KF

Classwork Redox Rules 1. Oxidation numbers of the nitrogen a. N 2 O b.

Classwork Redox Rules 1. Oxidation numbers of the nitrogen a. N 2 O b. NO c. N 2 O 4 d. N 2 O 5 e. NO 2 - f. NO 3 - 2. Oxidation number of the sulfur atom: a. H 2 S b. S c. H 2 SO 4 d. S 2 - e. HS- f. SO 2 g. SO 3 3. Indicate the oxidation number of phosphorus in each of the following compounds: a. HPO 3 b. H 3 PO 2 c. H 3 PO 3 d. H 3 PO 4 e. H 4 P 2 O 7 f. H 5 P 3 O 10

Half Reactions

Half Reactions

Example of a complete electron transfer reaction • 2 Mg + O 2 2

Example of a complete electron transfer reaction • 2 Mg + O 2 2 Mg. O • Mg atom transfers two electrons to each oxygen atom. • As a result Mg atoms become Mg 2+ and oxygen atoms become O 2 • Mg loses two electrons • O gains two electrons

Example of an electron transfer reaction • 2 Mg + O 2 2 Mg.

Example of an electron transfer reaction • 2 Mg + O 2 2 Mg. O • Mg atom transfers two electrons to each oxygen atom. • As a result 2 Mg atoms become Mg 2+ and two oxygen atoms become O 2 • Mg loses two electrons • O gains two electrons

General examples of Oxidation ½ Reaction • When an electron is lost (An electron

General examples of Oxidation ½ Reaction • When an electron is lost (An electron is found on the product side) there is oxidation X 0 X+1 + e – • When an electron is gained (An electron is found on the reactant side) there is reduction e – + Y+1 Y 0

Using the Rules Oxidation Number • If oxidation number goes up it is oxidized.

Using the Rules Oxidation Number • If oxidation number goes up it is oxidized. • If oxidation number goes down it is reduced.

Two ways to remember oxidation/reduction (redox) L E O goes G E R O

Two ways to remember oxidation/reduction (redox) L E O goes G E R O S E L E C T R O N S X I D A T I O N A I N L E C T R O N S E D U C T I O N O I L R I G X I D A T I O N S O S I N G E D U C T I O N S A I N G

½ Reaction Examples: Fill in the electrons, then tell if it is oxidation or

½ Reaction Examples: Fill in the electrons, then tell if it is oxidation or reduction. • Ex 1 start Na 0 • Ex 2 1 e – + Fe+3 • Ex 3 N+1 • Ex 4 2 e – + Mg+2 finish Na+1 +1 e – oxidized Fe+2 N+2 +1 e – Mg 0 start homework reduced oxidized reduced

Using the Rules-Last Lesson for CP Balance the reactions, write the oxidation numbers for

Using the Rules-Last Lesson for CP Balance the reactions, write the oxidation numbers for each atom. Loss of electron oxidation (LEO) Ex 5 +1 -1 0 +2 -1 0 2 HCl + Zn Zn. Cl 2 + H 2 Gain of electron reduction (GER)

Using the Rules (last lesson this year for CP) • Balance the reactions, then

Using the Rules (last lesson this year for CP) • Balance the reactions, then write oxidation # for each atom. • Ex 6 Mg + N 2 Mg 3 N 2 • Ex 7 H 2 S + Cl 2 HCl + S • Ex 8 Fe + O 2 Fe 2 O 3

Summary of Oxidation/Reduction • There are two definitions of oxidation and reduction: Oxidation Reduction

Summary of Oxidation/Reduction • There are two definitions of oxidation and reduction: Oxidation Reduction 1. _______________ 2. _______________

Classwork with ½ reactions Assign oxidation numbers for each element. Then, for the following

Classwork with ½ reactions Assign oxidation numbers for each element. Then, for the following balanced redox reactions answer the following questions: 1) Ag. NO 3 + Cu Cu. NO 3 + Ag a. Write all the oxidation numbers. Identify what charges change. b. Write the ½ reactions on the lines. Ag. NO 3 + 1 e – Ag ____________ (oxidation or reduction) Cu Cu. NO 3 + 1 e – ____________ (oxidation or reduction) c. Add the electrons to each ½ reaction. d. Identify each ½ reaction as oxidation or reduction. Finish classwork, then start homework.

2) Zn(s) + HCl(aq) H 2(g) + Zn. Cl 2(aq) – Write all the

2) Zn(s) + HCl(aq) H 2(g) + Zn. Cl 2(aq) – Write all the oxidation numbers. – Write the ½ reactions. ___________________ (oxidation or reduction) – Add the electrons to each ½ reaction. – Identify each ½ reaction as oxidation or reduction.

3) Sb. Cl 5 + 2 KI Sb. Cl 3 + I 2 +

3) Sb. Cl 5 + 2 KI Sb. Cl 3 + I 2 + 2 KCl – Write all the oxidation numbers. – Write the ½ reactions. ___________________ (oxidation or reduction) – Add the electrons to each ½ reaction. – Identify each ½ reaction as oxidation or reduction.

H Balancing Redox Reactions using Half. Reaction method in Acidic Conditions • • •

H Balancing Redox Reactions using Half. Reaction method in Acidic Conditions • • • Assign oxidation numbers to each atom Write the 2 half reactions Balance all elements except O & H Balance O by adding H 2 O Balance H by adding H+ (Acidic solution) Add OH- ions to each side of the equation to neutralize H+ ions. Cancel H 2 O molecules. (Basic solution) Balance charge by adding e. Balance e- by multiplying by a factor Add the ½ reactions, cancel e. Check that atoms and charges balance

Ex 1: Mn. O 4 – + Fe+2 → Fe+3 + Mn+2

Ex 1: Mn. O 4 – + Fe+2 → Fe+3 + Mn+2

Cl 2 + S 2 O 32– → Cl – + SO 42–

Cl 2 + S 2 O 32– → Cl – + SO 42–

Mn. O 4 – + SO 32– → Mn+2 + SO 42–

Mn. O 4 – + SO 32– → Mn+2 + SO 42–