Over Lesson 8 3 Over Lesson 8 3

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Over Lesson 8– 3

Over Lesson 8– 3

Over Lesson 8– 3

Over Lesson 8– 3

Special Products Lesson 8 -4

Special Products Lesson 8 -4

Understand how to find squares and products of sums and differences.

Understand how to find squares and products of sums and differences.

Square of a Sum Find (7 z + 2)2. (a + b)2 = a

Square of a Sum Find (7 z + 2)2. (a + b)2 = a 2 + 2 ab + b 2 Square of a sum (7 z + 2)2 = (7 z)2 + 2(7 z)(2) + (2)2 a = 7 z and b = 2 = 49 z 2 + 28 z + 4 Answer: 49 z 2 + 28 z + 4 Simplify.

Find (3 x + 2)2.

Find (3 x + 2)2.

Square of a Difference Find (3 c – 4)2. (a – b)2 = a

Square of a Difference Find (3 c – 4)2. (a – b)2 = a 2 – 2 ab + b 2 Square of a difference (3 c – 4)2 = (3 c)2 – 2(3 c)(4) + (4)2 a = 3 c and b = 4 = 9 c 2 – 24 c + 16 Answer: 9 c 2 – 24 c + 16 Simplify.

Find (2 m – 3)2.

Find (2 m – 3)2.

Square of a Difference GEOMETRY Write an expression that represents the area of a

Square of a Difference GEOMETRY Write an expression that represents the area of a square that has a side length of 3 x + 12 units. The formula for the area of a square is A = s 2 Area of a square A = (3 x + 12)2 s = (3 x + 12) A = (3 x)2 + 2(3 x)(12) + (12)2 a = 3 x and b = 12 A = 9 x 2 + 72 x + 144 Simplify. Answer: The area of the square is 9 x 2 + 72 x + 144 square units.

GEOMETRY Write an expression that represents the area of a square that has a

GEOMETRY Write an expression that represents the area of a square that has a side length of (3 x – 4) units.

Product of a Sum and a Difference Find (9 d + 4)(9 d –

Product of a Sum and a Difference Find (9 d + 4)(9 d – 4). (a + b)(a – b) = a 2 – b 2 (9 d + 4)(9 d – 4) = (9 d)2 – (4)2 = 81 d 2 – 16 Answer: 81 d 2 – 16 a = 9 d and b = 4 Simplify.

Find (3 y + 2)(3 y – 2).

Find (3 y + 2)(3 y – 2).

Homework p. 489 #23 -53 odd, 48

Homework p. 489 #23 -53 odd, 48