Oscillations Kinematics sinusoidal waves Dynamics Newtons law and

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Oscillations • Kinematics - sinusoidal waves • Dynamics -Newton’s law and Hooke’s law. •

Oscillations • Kinematics - sinusoidal waves • Dynamics -Newton’s law and Hooke’s law. • Energetics – Conservation of Energy • Mass on a spring • Pendulum

Oscillations • • • repetitive displacements with a time period provide the basis for

Oscillations • • • repetitive displacements with a time period provide the basis for measuring time serve as the starting point for describing wave motion. Example- Mass on a spring

Mass on a Spring Hooke’s Law -Force exerted by spring is proportional to the

Mass on a Spring Hooke’s Law -Force exerted by spring is proportional to the displacement from the equilibrium position. F= −kx k - Force constant Units N/m

Hooke’s Law

Hooke’s Law

Vertical direction The force of gravity is cancelled by the force of the spring.

Vertical direction The force of gravity is cancelled by the force of the spring. Equilibrium position The force on the object when it is displaced upward by a distance y from the equilibrium position is only Due to the spring. Fy= −ky = mg

Dynamics

Dynamics

The restoring force is proportional to the displacement for small displacements. F= −mgsinθ F=

The restoring force is proportional to the displacement for small displacements. F= −mgsinθ F= −mgθ for small θ F= - mgs L Equivalent to Hookes Law with k=mg/L ω = √(k/m ) ω = √(g/L ) T = 1/f then becomes Tpendulum = 2π √(L/g) The period is dependent on L but independent of m

 • For SHM, you can apply the second law to get F =

• For SHM, you can apply the second law to get F = - Kx = ma a = - (K/m)x X = R cosѲ a = (v 2/R)cos Ѳ A = (v 2/R 2)(Rcos Ѳ) = v 2/R 2)x

For a reference circle 2πA = v 0 T Ei = Ef T =

For a reference circle 2πA = v 0 T Ei = Ef T = (2πA)/v 0 ½ k. A 2 = ½ mv 02 Tspring = 2π √(m/k) A/v 0 = √(m/k)