Noble Gas Configuration I What are Noble Gases

Noble Gas Configuration

I. What are Noble Gases A. Noble gases are found in group 8 A B. The elements are called noble because they are non-reactive and very stable. C. The do not tend to form compounds Why would we call them noble gasses? Why are they nonreactive? What do they have in common? What is the goal of each atom?

II. Complete Electron Configuration A. What is the electron configuration for Ne? B. Ne: 1 s 22 p 6 C. What is the electron configuration for Mg? D. Mg: 1 s 22 p 63 s 2 E. What do both electron configurations have in common? F. [Ne] =1 s 22 p 6

III. Noble Gas Configuration (Abbreviated Configuration) A. Using neon’s configuration and then adding magnesium’s extra electrons we can get the noble gas configuration. B. Ne: 1 s 22 p 6 C. Mg: 1 s 22 p 63 s 2 D. Noble gas configuration Mg: [Ne]3 s 2 E. Only use noble gases in the brackets.

IV. Which Noble Gas is Used? A. To figure out which noble gas to use find the noble gas that is closest to the element without going over in atomic number B. Which noble gas is closest without going over? 1. Rb [Kr] 2. Cl [Ne] 3. Ra [Rn]

V. What About the Other Electrons? A. To know what to write for the other electrons that are not included in the noble gas, understanding the periodic table is important. B. The periodic table is organized by blocks according to the energy sublevels

VI. Blocks of the Periodic Table A. There are s, p, f, and d blocks of the periodic table which correspond to the energy sublevels.

VII. s Block Elements A. Write the closest noble gas without going over in brackets. B. Use the row number to get the energy level. C. Count the number of electrons until you get to the element in the s block. 1 2 3 4 5 6 7 Mg: [Ne] 3 s 2 Mg

Question Time • Try other s-block elements. Write the noble gas configuration of the following elements • Cs [Xe]6 s 1 1 2 • Ca [Ar]4 s 2 3 4 2 [Xe]6 s • Ba 5 6 7

VIII. p block elements (Between 518) A. Write the closest noble gas without going over in brackets. B. Use the row number to get the energy level. C. Write s 2 after the row number because you have to go through the s-block to get to the p-block. D. Write the row number again 1 E. The write “p” and then count 2 the number of p electrons you 3 must get through to get to your 4 element as a superscript 5 6 7 Si: [Ne] 3 s 2 3 p 2 Si

Question Time • Try other p-block elements. Write the noble gas configuration of the following elements • N [He]2 s 22 p 3 1 • S [Ne]3 s 23 p 4 23 4 2 5 • Cl [Ne]3 s 3 p 5 6 7

IX. d block elements (Between 2148) A. Write the closest noble gas without going over in brackets. B. Use the row number to get the energy level. C. Write s 2 after the row number because you have to go through the s-block to get to the d-block. D. Write one less than the row number (d-block elements are always one less than the row number)**d for down one row number E. The write “d” and then count the number of d electrons you must get through to get to your element as a superscript Co: [Ar] 4 s 2 3 d 7 1 2 3 4 5 6 7 3 d 4 d 5 d 6 d Co

Question Time • Try other d-block elements. Write the noble gas configuration of the following elements 23 d 2 [Ar]4 s • Ti 1 2 10 • Zn [Ar]4 s 3 d 23 d 5 4 [Ar]4 s • Mn 4 d 5 6 7 5 d 6 d

X. p block elements (Between 3153) A. Write the closest noble gas without going over in brackets. B. Use the row number to get the energy level. C. Write s 2 after the row number because you have to go through the sblock to get to the p-block. D. Write one less than the row number (d-block elements are always one less than the row number)**d for down one row number E. The write “d” and then count the number of d electrons you must get through to get to your element as a superscript F. Write the row number again and “p” and count over the number of p electrons until you get to your element Br: [Ar] 4 s 2 3 d 10 4 p 5 1 2 3 4 5 6 7 3 d 4 d 5 d 6 d Br

Question Time • Try other p-block elements. Write the noble gas configuration of the following elements • Sn[Kr]5 s 24 d 105 p 2 23 d 104 p 4 1 [Ar]4 s 2 • Se 3 4 5 6 7