Mr Sims Quadratic Equation in standard form ax

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Ó Mr. Sims

Ó Mr. Sims

Quadratic Equation (in standard form) ax 2 + bx + c = 0 Example:

Quadratic Equation (in standard form) ax 2 + bx + c = 0 Example: Algebra 2 Section 7. 3 Quadratic Formula 3 x 2 + 5 x – 4 = 0 One way to solve a quadratic equation is to use the quadratic formula: Solve: 3 x 2 + 5 x – 4 = 0 a= 3 b= 5 c=-4 Ó Mr. Sims

Solve each equation by using the quadratic formula. (final answers should be in simplest

Solve each equation by using the quadratic formula. (final answers should be in simplest radical form) 1. 4 x 2 + x – 2 = 0 a= 4 b= 1 c = -2 2. 2 n 2 – n – 2 = 0 a= 2 b = -1 c = -2 Ó Mr. Sims

3. t 2 + 4 t – 1 = 0 a= 1 b= 4

3. t 2 + 4 t – 1 = 0 a= 1 b= 4 c = -1 factor 2 out of numerator Ó Mr. Sims

4. 4 n 2 + 7 = 12 n -12 n get equation in

4. 4 n 2 + 7 = 12 n -12 n get equation in standard form (ax 2 + bx + c = 0) -12 n 4 n 2 – 12 n + 7 = 0 a= 4 b = -12 c= 7 factor 4 out of numerator 2 Ó Mr. Sims

5. -x 2 = 16 x + 46 +x 2 get equation in standard

5. -x 2 = 16 x + 46 +x 2 get equation in standard form (ax 2 + bx + c = 0) +x 2 + 16 x + 46 = 0 a= 1 b = 16 c = 46 factor 2 out of numerator Ó Mr. Sims

change 3, 800 to scientific notation =. 45 × 103 divide and subtract exponents

change 3, 800 to scientific notation =. 45 × 103 divide and subtract exponents when dividing = 4. 5 × 102 change to true scientific notation Ó Mr. Sims

volume of a cylinder V = πr 2 h r = 7 ft V

volume of a cylinder V = πr 2 h r = 7 ft V = π(72)(24) V = π(49)(24) V = 1176π Ó Mr. Sims

Algebra 2 Section 7. 3 A Assignment Solve each equation by using the quadratic

Algebra 2 Section 7. 3 A Assignment Solve each equation by using the quadratic formula. 1. ) 3 y 2 + 7 y + 3 = 0 2. ) 2 y 2 – 4 y + 1 = 0 3. ) 2 x 2 + 6 x + 3 = 0 4. ) 0 = 4 x 2 + 8 x + 1 5. ) 3 x 2 + 6 x = 2 Ó Mr. Sims

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