Module 2 Topic 2 Solving Linear Equations and

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Module 2, Topic 2: Solving Linear Equations and

Module 2, Topic 2: Solving Linear Equations and

Properties of Equality

Properties of Equality

Basic Number Properties

Basic Number Properties

Solve the equation and check your solution. Write the property that justifies each step

Solve the equation and check your solution. Write the property that justifies each step of your solving strategy. 3(2 x + 1) = 4 x + 6 6 x + 3 = 4 x + 6 2 x + 3 = 2 x = 3 6 Property Distributive Property Subtraction Property of Equality Division Property of Equality ?

 • What is a solution When an equation contains a anyway? ? variable,

• What is a solution When an equation contains a anyway? ? variable, we can solve the equation. • A solution to an equation is a value for the variable that makes the equation a true statement.

Linear Equations can have: • One solution • No solutions • Infinite solutions

Linear Equations can have: • One solution • No solutions • Infinite solutions

One solution: There is one number that, when substituted for the variable, makes the

One solution: There is one number that, when substituted for the variable, makes the equation true. When you solve for the variable, you will get one real number. 4 x – 6 = 14 4 x = 20 x=5

No solution: There are no numbers that would make the equation true. When you

No solution: There are no numbers that would make the equation true. When you try to solve the equation, you will get a FALSE statement 3 x + 7 = 3 x + 4 -3 x 7≠ 4

Infinite solutions: Using any real number in place of the variable would make the

Infinite solutions: Using any real number in place of the variable would make the equation true. When you solve the equation, you will get the exact 12 xsame + 4 = thing 4(3 x +on 1) both sides of the 12 x + 4 equation. = 12 x + 4 -12 x 4=4

Determine if the equation has one solution, no solutions, or infinite solutions. Show your

Determine if the equation has one solution, no solutions, or infinite solutions. Show your work. o 2 t y b term s!) h c a iply e e fraction t l u (M th f o d i get r 3 x + 12 = 3 x – 4 + 17 3 x + 13 = 3 x + 13 ! s n o i t u l o s -3 x e t i n i f n I 13 = 13

Lesson 2: Literal Equations

Lesson 2: Literal Equations

Forms of Linear General Form Factored Form Standard Form* Equations y = ax +

Forms of Linear General Form Factored Form Standard Form* Equations y = ax + b Example: y = 3 x + 9 y = a(x – c) Example: y = 3(x + 3) *A must be a positive integer Ax + By = C Example: 3 x – y = -9

Changing between forms of linear equations: (Goal: Ax + By = C) y =

Changing between forms of linear equations: (Goal: Ax + By = C) y = ¾ x 7 Write the equation y = ¾ x - 7 in property 4 y = 4(¾ x –standard 7) multiplicationform distributive property 4 y = 3 x – 28 addition property 28 + 4 y = 3 x subtraction property 28 = 3 x – 4 y Standard Form 3 x – 4 y = 28

Changing between forms of linear equations: (Goal: y = ax + b) 4 x

Changing between forms of linear equations: (Goal: y = ax + b) 4 x + 2 y = 24 Write the equation 4 x + 2 y = 24 in subtraction property 2 y = -4 x + 24 general form division property - General form y = -2 x + 12 y = a(x - c) Now, change (Goal: that to factored Factored form y = -2(x – 6) distributive propertyform

Literal Equations: • variables represent specific measures • Seen most often when you study

Literal Equations: • variables represent specific measures • Seen most often when you study • d = rt formulas • A = ½ bh • Examples: • C = 2πr

Solving Literal Equations

Solving Literal Equations

Solving Literal Equations: Example (Goal: isolate “t”) Given the equation d = rt, solve

Solving Literal Equations: Example (Goal: isolate “t”) Given the equation d = rt, solve for t d = rt Division property of equality

Solving Literal Equations: Another Example Solve for W: A = 2(L + W) Division

Solving Literal Equations: Another Example Solve for W: A = 2(L + W) Division property of equality Subtraction property of equality

Lesson 3: Solving Inequalities

Lesson 3: Solving Inequalities

Alan’s camping troop is selling popcorn to earn money for an upcoming camping trip.

Alan’s camping troop is selling popcorn to earn money for an upcoming camping trip. Each camper starts with a credit of $25 toward his sales, and each box of popcorn sells for $3. 75. 1. Write a function, f(b), to show Alan’s total sales as a function of the number of boxes (b) of popcorn he sells. 2. Determine the slope and the y-intercept and explain what they mean in terms of the situation.

How to solve inequalities #1: Look at the graph How many boxes (b) must

How to solve inequalities #1: Look at the graph How many boxes (b) must Alan sell in order to make at least $1600? b ≥ 420

How many boxes (b) does Alan sell if he makes less than 700? b

How many boxes (b) does Alan sell if he makes less than 700? b < 180

How to solve inequalities #2: Solve it algebraically It’s almost exactly like solving an

How to solve inequalities #2: Solve it algebraically It’s almost exactly like solving an equation! One important rule: If you multiply by a negative number, reverse the sign

#2: Solve it algebraically How many boxes (b) must Alan sell in order to

#2: Solve it algebraically How many boxes (b) must Alan sell in order to make at least $1600? f(b) = 3. 75 b + 25 ≥ 1600 3. 75 b ≥ 1575 3. 75 b ≥ 420 Subtraction Property of Equality Division Property of Equality

#2: Solve it algebraically How many boxes (b) does Alan sell if he makes

#2: Solve it algebraically How many boxes (b) does Alan sell if he makes less than 700? f(b) = 3. 75 b + 25 < 700 3. 75 b < 675 3. 75 b < 180 Subtraction Property of Equality Division Property of Equality

#2: Solve it algebraically Try solving this one: -3 x + 35 > 47

#2: Solve it algebraically Try solving this one: -3 x + 35 > 47 -3 x > 12 -3 Subtraction Property of Equality -3 x < -4 Division Property of Equality One important rule: If you multiply by a negative number, reverse the sign

How to graph solutions to inequalities Ø Put a dot and a line on

How to graph solutions to inequalities Ø Put a dot and a line on the number line. o Open circle does not include the number (< or >) • Closed circle includes the number (≤ or ≥)

How to graph solutions to inequalities x < -5 x > -5

How to graph solutions to inequalities x < -5 x > -5

How to graph solutions ≤to inequalities x ≤ -1 x ≥ -1

How to graph solutions ≤to inequalities x ≤ -1 x ≥ -1

One important rule: If you multiply by a negative number, reverse the sign

One important rule: If you multiply by a negative number, reverse the sign

Lesson 4: Compound Inequalities

Lesson 4: Compound Inequalities

(x) 0. 01 ≤ x ≤ 20 20 < x ≤ 50 50 <

(x) 0. 01 ≤ x ≤ 20 20 < x ≤ 50 50 < x < 75 75 ≤ x < 100 ≤ x

Compound Two simple inequalities are combined. Inequalities 1. Disjunction: • The union of two

Compound Two simple inequalities are combined. Inequalities 1. Disjunction: • The union of two simple inequalities • Key word: “OR” • ONE condition has to be satisfied

Example: To get the discount movie ticket price, you must be under 12 years

Example: To get the discount movie ticket price, you must be under 12 years old or 65 and up. Disjunction/Union 65 ≤ x x < 12 1 5 10 15 55 20 60 65 70 75 x < 12 or 65 ≤ x 10 20 30 40 50 60 70 80 90

How to solve Unions: Solve each side and keep the “or” in between them

How to solve Unions: Solve each side and keep the “or” in between them x + 5 > 14 -5 -5 OR x>9 0 1 2 3 x < 9 3 3 x<3 3 4 5 6 7 8 9 10 11 12

Compound Two simple inequalities are combined. Inequalities 2. Conjunction: • The intersection of two

Compound Two simple inequalities are combined. Inequalities 2. Conjunction: • The intersection of two simple inequalities. • Key word: “AND” • BOTH condition must be satisfied

Example: To enlist in the United States army, you must be at least. Intersection

Example: To enlist in the United States army, you must be at least. Intersection 17 years old and younger than 35. 17 ≤ x x < 35 17 ≤ x and x < 35

Conjunctions Compact form: (“AND”) 17 ≤ x and x < 35 Can be written

Conjunctions Compact form: (“AND”) 17 ≤ x and x < 35 Can be written as: 17 ≤ x < 35

How to solve Unions: Isolate the variable between the two sides 4 ≤ 2

How to solve Unions: Isolate the variable between the two sides 4 ≤ 2 x + 2 < 12 -2 -2 2 ≤ 2 x 2 0 1 2 -2 < 10 2 1≤x <5 3 4 5 6 7 8 9 10 2 11 12