MECE251 Fluids Lesson 7 part I Manometers 1

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MECE-251 Fluids, Lesson 7 (part I): Manometers 1 - Read Text Sections Monday 2

MECE-251 Fluids, Lesson 7 (part I): Manometers 1 - Read Text Sections Monday 2 - Solve Chapter Problems Tuesday 3 & 4 – Lectures, Example, and Review Problems Wednesday Thursday 5 - Solve Case Study 6 - Complete On-line Lesson Quiz R·I·T MECE-251 Friday Saturday or Sunday 1

Objectives • Compute the hydrostatic pressures and forces on submerged surfaces on static fluid.

Objectives • Compute the hydrostatic pressures and forces on submerged surfaces on static fluid. • Use the principle of static equilibrium to solve for the forces involves in buoyancy problems. R·I·T MECE-251 2

2. 1 Pressure § The basic property of a static fluid is pressure. §

2. 1 Pressure § The basic property of a static fluid is pressure. § Pressure is defined as the amount of normal surface force exerted by a fluid on any boundary it is in contact with. It can be written as: Unit: N / m 2 or Pascal (Pa). (Also frequently used is bar, where 1 bar = 105 Pa). R·I·T MECE-251 3

Image from ODL Jan 2005 Open University Malaysia R·I·T MECE-251 4

Image from ODL Jan 2005 Open University Malaysia R·I·T MECE-251 4

Hydrostatic Force on Plane Surface Force = Pressure x Area of plane F =

Hydrostatic Force on Plane Surface Force = Pressure x Area of plane F = PA § This force will act vertically downward and through the center of pressure. F=PA= gh. A R·I·T Figure 2. 17: Resultant force on horizontal plane h MECE-251 5

3. 4. 2 Pascal’s Paradox R·I·T MECE-251 6

3. 4. 2 Pascal’s Paradox R·I·T MECE-251 6

3. 4. 3 Hydraulic Jack R·I·T MECE-251 7

3. 4. 3 Hydraulic Jack R·I·T MECE-251 7

Pressure Transmission Hydraulic Lift From Munson R·I·T MECE-251 8

Pressure Transmission Hydraulic Lift From Munson R·I·T MECE-251 8

Dams R·I·T MECE-251 9

Dams R·I·T MECE-251 9

The next few slides are for information only – we won’t be using for

The next few slides are for information only – we won’t be using for problems

 • Resultant Force and Center of Pressure on a Submerged Plane Surface in

• Resultant Force and Center of Pressure on a Submerged Plane Surface in a Liquid p = gh Fundamentals of Fluid Mechanics, 5/E by Bruce Munson R·I·T MECE-251 11

The total force can be written as: where is the pressure at the centroid

The total force can be written as: where is the pressure at the centroid of the area and equals ghcentroid The boxed equation is known as the hydrostatic force equation. We have thus replaced an integral involving a variable pressure by a constant resultant pressure: R·I·T MECE-251 12

Hydrostatic Buoyant Force Fb = g Fb = buoyant force • R·I·T = displaced

Hydrostatic Buoyant Force Fb = g Fb = buoyant force • R·I·T = displaced volume of fluid MECE-251 13

Next Steps L 7 Task 4 A: Please review the lecture on line. L

Next Steps L 7 Task 4 A: Please review the lecture on line. L 7 Task 4 B: Please review the example problems on line. L 7 Task 4 C: Then, solve the review problem. L 7 Task 5: L 7 Task 6: Form groups and work on your case study. Take the Lesson 7 quiz. Reference: Schaum’s Outline of Thermodynamics for Engineers, Second Edition, M. C. Potter and C. W. Somerton, Mc. Graw Hill R·I·T MECE-251 14