Maths Year 3 Length and Measurement Times tables

Maths Year 3 Length and Measurement

Times tables practice (do this daily) 0 x 2=0 7 x 2 = 14 0 x 3=0 7 x 3 = 21 1 x 2=2 8 x 2 = 16 1 x 3=3 8 x 3 = 24 2 x 2=4 9 x 2 = 18 2 x 3=6 9 x 3 = 27 3 x 2=6 10 x 2 = 20 3 x 3=9 10 x 3 = 30 4 x 2=8 11 x 2 = 22 4 x 3 = 12 11 x 3 = 33 5 x 2 = 10 12 x 2 = 24 5 x 3 = 15 12 x 3 = 36 6 x 2 = 12 6 x 3 = 18

Times tables practice (do this daily) 0 x 5=0 7 x 5 = 35 0 x 10 = 0 7 x 10 = 70 1 x 5=5 8 x 5 = 40 1 x 10 = 10 8 x 10 = 80 2 x 5 = 10 9 x 5 = 45 2 x 10 = 20 9 x 10 = 90 3 x 5 = 15 10 x 5 = 50 3 x 10 = 30 10 x 10 = 100 4 x 5 = 20 11 x 5 = 55 4 x 10 = 40 11 x 10 = 110 5 x 5 = 25 12 x 5 = 60 5 x 10 = 50 12 x 10 =120 6 x 5 = 30 6 x 10 = 60

New times table (practice daily) 0 x 4=0 7 x 4 = 28 1 x 4=4 8 x 4 = 32 2 x 4=8 9 x 4 = 36 3 x 4 = 12 10 x 4 = 40 4 x 4 = 16 11 x 4 = 44 5 x 4 = 20 12 x 4 = 48 6 x 4 = 24

Thursday 4 th March LO: To measure perimeter Arithmetic 1. 2. 3. 4. 625 + 235 = 387 - 245 = 8 x _ = 32 Double 91 = 1. 77 + 20 = 2. 55 - 20 = 3. _ x 4 = 0 4. Double 55 =

Perimeter What do you think the word ‘perimeter’ means? Discuss with someone at home and see what you come up with. Do you have the same ideas?

Perimeter is the distance around a twodimensional shape. Add the side lengths to find the perimeter of regular polygons. What 2 D shapes do we already know?

In your books Remember to explain WHY in full sentences please.

Answer We can not find the perimeter of some of these images because they are not complete 2 D shapes. There are 2 shapes that are not complete and so we would be unable to work out their perimeter. What do you think about the 3 rd shape?

Finding the perimeter To find the perimeter, all we need to do is use the knowledge and skills that we already have to help us. When we find the perimeter, we are just adding different lengths together. Use your addition skills to find the perimeters of the shapes on the next slide.

What method could you use? 4 cm 5 cm 3 cm 6 cm 5 cm 10 cm 12 cm

3. 10 + 10 = 30 Answer 1. 4 cm 5 cm 3 cm 6 cm 5 + 5 = 10 3+3=6 10 x 3 = 30 10+ 6 = 16 Perimeter =30 cm Perimeter = 16 cm 5 cm 1. 6 + 6 = 12 5+4=9 12 + 9 = 21 10 cm OR 4. 12 +12 = 48 OR Perimeter = 21 cm 12 x 4 = 48 Perimeter = 48 cm 12 cm

Now use what you know to answer the following questions about perimeter

Answers

Final question Remember… try to make as many different shapes as you can using 8 centimeter squares.

Friday 5 th March Please do the times tables from the beginning of the powerpoint. LO: To measure perimeter Arithmetic 1. 2. 3. 4. 475 + 375 = 585 - 172 = 9 x __ = 45 Half of 78 = 1. 40 + 50 = 2. 80 - 25 = 3. 5 x __ = 15 4. Half of 48 =

Recap Please remind yourselves what perimeter is. What operation of number do we use to calculate the perimeter? What other skills can we use to help us?

Answers Perimeter is the total length of all the edges of a 2 D shape. We use addition to work out the perimeter We can use our times tables/counting in 2’s, 3’s and 4’s etc to help us. We MUST answer with the unit of measure. E. g. cm

Your turn in your books

Answers 1. 6 + 6 = 12 2+2=4 12 + 4 = 16 cm 1. 2. 4+4=8 We can use our times tables to work the perimeter out too. 1. 2 x 6 = 12 4+4=8 2 x 4=4 8 + 8 = 24 cm 12 + 4 = 16 cm 1. 3 + 3 = 6 3+3=6 6 + 6 = 12 cm 1. 6 x 4 = 24 cm 3. 3 x 4 = 12 cm

Your turn Remember to use two DIFFERENT methods.

Answers 1. 5 + 5 + 5 = 20 cm Or 5 x 4 = 20 cm 1. 10 + 10 = 40 mm Or 10 x 4 = 40 mm You must remember it is mm here!

Missing number… HINT- We can use the INVERSE to work out missing number problems.

Answer 3 cm We know that this side is equal to the one parallel because this is a rectangle. 5 cm Now we know we have 10 cm so far so we need the last 2 sides to add up to 6 cm We must divide 6 by 2 to work out what numbers add together to make 6. The answer is 3 cm.

Now use your knowledge to help you solve the last 3 problems Remember to: Read the problem carefully Highlight the key information Decide what operation of number/method you need to use Check your answer Don’t forget the unit of measure if needed.

Problems

Answers