Mass Mass Problems Five Steps to Problem Solving

Mass : Mass Problems Five Steps to Problem Solving

Step #1 Identify the GIVEN (#) and the UNKNOWN (? ? ? ) Balance the equation

Step #2 Convert the GIVEN in grams into MOLES. Use a FLM and the formula mass of the GIVEN.

Step #3 Determine the Ratio of moles of GIVEN to moles of UNKNOWN. Coefficients in front of GIVEN and UNKNOWN

Step #4 Determine the number of moles of UNKNOWN formed. G : ? ? ? multiply then divide

Step #5 Convert the moles of UNKNOWN into grams of UNKNOWN. Use a FLM and the formula mass of the UNKNOWN

If 42. 3 grams of magnesium reacts with an excess of chlorine gas, how many grams of magnesium chloride will be produced? #1 42. 3 g ? ? ? 1) Mg + Cl 2 Mg Cl 2 2) grams X 1. 00 mole = grams 3) G: ? : 4) : 5) mole X grams = 1. 00 moles grams

#1 42. 3 g 1) 1 Mg + Cl 2 2) 3) 4) 5) ? ? ? 1 Mg Cl 2

#1 42. 3 g ? ? ? 1) 1 Mg + Cl 2 1 Mg Cl 2 2) 42. 3 grams X 1. 00 mole = 1. 74 moles 3) 4) 5) 24. 3 grams

#1 42. 3 g ? ? ? 1) 1 Mg + Cl 2 1 Mg Cl 2 2) 42. 3 grams X 1. 00 mole = 1. 74 moles 3) G: ? 4) 5) 24. 3 grams 1 : 1

#1 42. 3 g ? ? ? 1) 1 Mg + Cl 2 1 Mg Cl 2 2) 42. 3 grams X 1. 00 mole = 1. 74 moles 3) G: ? 4) 5) 24. 3 grams 1 : 1 1. 74 : 1. 74

#1 42. 3 g ? ? ? 1) 1 Mg + Cl 2 1 Mg Cl 2 2) 42. 3 grams X 1. 00 mole = 1. 74 moles 24. 3 grams 3) G: ? 1 : 1 4) 1. 74 : 1. 74 5) 1. 74 mole X 95. 3 grams = 166 grams 1. 00 mole

How many grams of Ag. Cl are produced from the reaction of 5. 00 grams of Ag(NO 3) reacting with an excess of Ba. Cl 2 #2 5. 00 g ? ? ? 1)2 Ag(NO 3) + 1 Ba. Cl 2 2 Ag. Cl + 1 Ba(NO 3)2 2) 5. 00 grams X 1. 00 mole = 0. 0294 moles 170 grams 3) G: ? 2 : 2 4) 0. 0294 : 0. 0294 5) 0. 0294 mole X 144 grams = 4. 23 grams 1. 00 mole

1)____________________ 2) _____grams X 1. 00 mole = ____moles 3) G: ? 4) ____: ____ 5) _______ mole X grams = ______grams 1. 00 mole

BALANCING 1) 1 1 1 6) 2 3 2 2 2) 2 2 1 7) 2 1 1 2 3) 1 1 8) 1 3 2 3 4) 1 2 9) 2 1 1 2 5) 1 1 2 1 10) 6 6 1 6