MARK MAXIMISER Gin invested 1300 She received 7

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MARK MAXIMISER Gin invested £ 1300. She received 7% compound ① interest for 2

MARK MAXIMISER Gin invested £ 1300. She received 7% compound ① interest for 2 years. How much did Gin earn? (− 8, 1) 2 2 1 ④ The length of one side of a cube is 2. 3 cm to ⑤ Write down the quadratic formula. ⑥ 2 2 2 ⑦ ⑧ P is the point on the line such that AP: PB = 2: 1 ⑨ A 1 0 1 0 180 − 1 2 a 360 64° O 1 ⑩ Prove the product of 2 consecutive ⑪ 4 2 odd numbers is always odd. 8 cm /22 ③ 1 decimal place. Find the upper bound for the surface area of the cube. Find the equation of this circle. Date: ② Describe the shaded region as an inequality 6789 – 2 B b B 11 cm 3

MARK MAXIMISER Gin invested £ 1300. She received 7% compound ① interest for 2

MARK MAXIMISER Gin invested £ 1300. She received 7% compound ① interest for 2 years. How much did Gin earn? 1300 × 1. 072 = £ 1488. 37 – 1300 = £ 188. 37 6789 – 2 B = 5 2 1 ④ The length of one side of a cube is 2. 3 cm to ⑤ Write down the quadratic formula. ⑥ 2. 352 × 6 = 33. 135 cm 2 2 (− 8, 1) ⑦ A 0 180 − 1 2 a 360 64° O 1 ⑩ Prove the product of 2 consecutive ⑪ 4 2 odd numbers is always odd. 8 cm 2 ⑧ P is the point on the line such that AP: PB = 2: 1 ⑨ 1 1 2 0 ③ 2 Find the equation of this circle. /22 ② Describe the shaded region as an inequality 1 decimal place. Find the upper bound for the surface area of the cube. Date: b B 11 cm 3

MARK MAXIMISER Gin invested £ 1300. She received 7% compound ① interest for 2

MARK MAXIMISER Gin invested £ 1300. She received 7% compound ① interest for 2 years. How much did Gin earn? 1300 × 1. 072 = £ 1488. 37 – 1300 = £ 188. 37 6789 – 2 B 2 2 1 ④ The length of one side of a cube is 2. 3 cm to ⑤ Write down the quadratic formula. ⑥ 1 decimal place. Find the upper bound for the surface area of the cube. 2. 352 × 6 = 33. 135 cm 2 2 Find the equation of this circle. (− 8, 1) ⑦ 1 64° 8 cm 8. 36… cm A 20° 0 180 20° − 1 20° P ⑪ 4 O 1 odd numbers is always odd. 2 a 360 ⑩ Prove the product of 2 consecutive 11 cm 2 ⑧ P is the point on the line such that AP: PB = 2: 1 ⑨ 1 2 0 ③ /22 ② Describe the shaded region as an inequality = 5 Date: 2 B b 3

Questions? Comments? Suggestions? …or have you found a mistake!? Any feedback would be appreciated

Questions? Comments? Suggestions? …or have you found a mistake!? Any feedback would be appreciated . Please feel free to email: tom@goteachmaths. co. uk