MARK MAXIMISER 6789 1 E What is the

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MARK MAXIMISER 6789 – 1 E ① What is the next term in this

MARK MAXIMISER 6789 – 1 E ① What is the next term in this sequence? Date: /20 ② ③ 5, 25, 125 73° 52° Find the area of this triangle (2 dp). 2 1 2 ④ ⑤ ⑥ 2 2 1 ⑦ Find the equation of this circle. ⑧ The histogram shows information about ⑨ 8 cm 46° package weights. 20 packages weighed between 20 & 30 kg. Estimate how many weighed more than 45 kg. (− 5, 2) 2 1 ⑩ P is the point on the line such that AP: PB = 3: 2 ⑪ A 2 a O 3 b B Frequency Density 6 cm 0 20 2 30 40 50 Weight (kg) 60 2

MARK MAXIMISER 6789 – 1 E ① What is the next term in this

MARK MAXIMISER 6789 – 1 E ① What is the next term in this sequence? Date: ② ③ 5, 25, 125 73° Alternate Segment Theorem Find the area of this triangle (2 dp). /20 52° 73° 2 1 2 ④ ⑤ ⑥ 2 2 1 ⑦ Find the equation of this circle. ⑧ The histogram shows information about ⑨ 8 cm 46° package weights. 20 packages weighed between 20 & 30 kg. Estimate how many weighed more than 45 kg. (− 5, 2) 2 1 ⑩ P is the point on the line such that AP: PB = 3: 2 ⑪ A 2 a O 3 b B Frequency Density 6 cm 0 20 2 30 40 50 Weight (kg) 60 2

MARK MAXIMISER 6789 – 1 E ① What is the next term in this

MARK MAXIMISER 6789 – 1 E ① What is the next term in this sequence? Date: ② ③ 5, 25, 125 73° Alternate Segment Theorem Find the area of this triangle (2 dp). /20 52° 73° 2 1 2 ④ ⑤ ⑥ 2 2 1 ⑦ Find the equation of this circle. ⑧ The histogram shows information about ⑨ 8 cm 46° package weights. 20 packages weighed between 20 & 30 kg. Estimate how many weighed more than 45 kg. (− 5, 2) 10 + 5 = 15 6 2 1 ⑩ P is the point on the line such that AP: PB = 3: 2 ⑪ A 2 a P O 3 b B Frequency Density 6 cm 4 2 0 20 2 10 20 30 40 50 Weight (kg) 5 60 2

Questions? Comments? Suggestions? …or have you found a mistake!? Any feedback would be appreciated

Questions? Comments? Suggestions? …or have you found a mistake!? Any feedback would be appreciated . Please feel free to email: tom@goteachmaths. co. uk