MAD Practice 1 6 Mean Absolute Deviation Practice

MAD Practice #1 -6

Mean Absolute Deviation Practice 1. Daily Visitors to a Web Site: The MAD is 18. 48 indicating the average difference of visits to a web site from the mean is 18. 48 times. The data is spread out in relation to the mean. Step 2 (cont. ): Use Step 2: Find the Step 1: Find the Mean distance each element is from the mean the absolute value of each distance Step 3: Calculate the mean of these distances

Mean Absolute Deviation Practice 2. Zoo Admission Prices: The MAD is 0. 5 indicating the average difference of prices from the mean is $0. 50. The data is less spread out and closer to the mean. Step 1: Find the Mean Step 2: Find the distance each element is from the mean Step 2 (cont. ): Use the absolute value of each distance Step 3: Calculate the mean of these distances

Mean Absolute Deviation Practice 3. Height of Waterslides: Splash Lagoon vs. Wild Water Bay Step 1: Find the Mean of Splash Lagoon Step 2: Find the distance each element is from the mean and use the absolute value of each distance Step 3: Calculate the mean of these distances Step 1: Find the Mean of Wild Water Bay Step 2: Find the distance each element is from the mean and use the absolute value of each distance Step 3: Calculate the mean of these distances

Mean Absolute Deviation Practice 3. Height of Waterslides: Splash Lagoon vs. Wild Water Bay

Mean Absolute Deviation Practice 3. Height of Waterslides: Splash Lagoon vs. Wild Water Bay The MAD for Splash Lagoon is 10. 32. The MAD for Wild Water Bay is 12. 48. A lower MAD indicates the data is less spread out and closer to the mean. Therefore, the height of the waterslides at Splash Lagoon are closer to the mean height demonstrating less variation in the height of each slide in comparison to the slides at Wild Water Bay.

Mean Absolute Deviation Practice 4. Known Moons of Planets: The MAD is 17. 875 indicating the average difference of the number of moons per planet from the mean is 17. 875. The data is spread out in relation to the mean. Step 2: Find the Step 2 (cont. ): Use Step 1: Find the Mean distance each element is from the mean the absolute value of each distance Step 3: Calculate the mean of these distances

Mean Absolute Deviation Practice 5. Hard Drive (gigabytes): The MAD is 158. 75 indicating the average difference of the number of gigabytes per hard drive from the mean is 158. 75. The data is significantly spread out in relation to the mean. Step 1: Find the Mean Step 2: Find the distance each element is from the mean Step 2 (cont. ): Use the absolute value of each distance Step 3: Calculate the mean of these distances

Mean Absolute Deviation Practice 6. Digital Camera Prices: The MAD is 26. 76 indicating the average difference of the prices from the mean is $26. 76. The data is spread out in relation to the mean. Step 1: Find the Mean Step 2: Find the distance each element is from the mean Step 2 (cont. ): Use the absolute value of each distance Step 3: Calculate the mean of these distances

Mean Absolute Deviation Practice Homework: Find the MAD for problem 7, Grand Slam Singles Titles Won (10 different tennis players) Step 1: Find the Mean Step 2: Find the distance each element is from the mean Step 2 (cont. ): Use the absolute value of each distance Step 3: Calculate the mean of these distances

Homework: Find the mean absolute deviation (MAD) for problem 7, Grand Slam Singles Titles Won (10 different tennis players) 7. Singles Titles Won: The MAD is 2. 02 indicating 4. Grand Known. Slam Moons of Planets: the average difference of the number of titles won from the mean is 2. 02. The data is less spread out and closer to the Step 2: Find the Step 2 (cont. ): Use mean. Step 1: Find the Mean distance each element is from the mean the absolute value of each distance Step 3: Calculate the mean of these distances