MA 912 A 3 4 Solve and graph

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MA. 912. A. 3. 4 Solve and graph simple and compound inequalities in one

MA. 912. A. 3. 4 Solve and graph simple and compound inequalities in one variable and be able to justify each step in a solution.

MA. 912. A. 3. 4 - Solve and graph simple and compound inequalities in

MA. 912. A. 3. 4 - Solve and graph simple and compound inequalities in one variable and be able to justify each step in a solution. Question 1 What is the solution for the inequality shown below? A. x < − 9 C. x < − 3 B. x > − 9 D. x > − 3

MA. 912. A. 3. 4 - Solve and graph simple and compound inequalities in

MA. 912. A. 3. 4 - Solve and graph simple and compound inequalities in one variable and be able to justify each step in a solution. Question 1 ANSWER: A. What is the solution for the inequality shown below? A. x < − 9 C. x < − 3 B. x > − 9 D. x > − 3

MA. 912. A. 3. 4 - Solve and graph simple and compound inequalities in

MA. 912. A. 3. 4 - Solve and graph simple and compound inequalities in one variable and be able to justify each step in a solution. Question 2 Which graph represents the solution set for the inequality shown below? A. B. C. D.

MA. 912. A. 3. 4 - Solve and graph simple and compound inequalities in

MA. 912. A. 3. 4 - Solve and graph simple and compound inequalities in one variable and be able to justify each step in a solution. Question 2 ANSWER: C. Which graph represents the solution set for the inequality shown below? A. B. C. D.

MA. 912. A. 3. 4 - Solve and graph simple and compound inequalities in

MA. 912. A. 3. 4 - Solve and graph simple and compound inequalities in one variable and be able to justify each step in a solution. Question 3 What is the solution for the inequality shown below? A. x ≤ 2 or x ≥ 5 C. x ≥ − 5 or x ≤ − 2 B. 2 ≤ x ≤ 5 D. − 5 ≥ x ≥ − 2

MA. 912. A. 3. 4 - Solve and graph simple and compound inequalities in

MA. 912. A. 3. 4 - Solve and graph simple and compound inequalities in one variable and be able to justify each step in a solution. Question 3 Answer: B. What is the solution for the inequality shown below? A. x ≤ 2 or x ≥ 5 C. x ≥ − 5 or x ≤ − 2 B. 2 ≤ x ≤ 5 D. − 5 ≥ x ≥ − 2

MA. 912. A. 3. 4 - Solve and graph simple and compound inequalities in

MA. 912. A. 3. 4 - Solve and graph simple and compound inequalities in one variable and be able to justify each step in a solution. Question 4 Which graph represents the solution set for the compound inequality shown below? A. B. C. D.

MA. 912. A. 3. 4 - Solve and graph simple and compound inequalities in

MA. 912. A. 3. 4 - Solve and graph simple and compound inequalities in one variable and be able to justify each step in a solution. Question 4 Answer: A. Which graph represents the solution set for the compound inequality shown below? A. B. C. D.

MA. 912. A. 3. 4 - Solve and graph simple and compound inequalities in

MA. 912. A. 3. 4 - Solve and graph simple and compound inequalities in one variable and be able to justify each step in a solution. Question 5 Mark was the only student in class to get problem 34 from last night's homework correct. His teacher asked him to show his work to the class. The inequality the students had to solve was. Mark wrote the steps shown below on the board. Which of the following explains step 4 of his solution? A. B. C. D. The associative property was applied. The distributive property was applied. You must change the direction of the inequality symbol whenever you divide both sides of the inequality by an even number. You must change the direction of the inequality symbol whenever you divide both sides of the inequality by a negative number.

MA. 912. A. 3. 4 - Solve and graph simple and compound inequalities in

MA. 912. A. 3. 4 - Solve and graph simple and compound inequalities in one variable and be able to justify each step in a solution. Question 5 Answer: D. Mark was the only student in class to get problem 34 from last night's homework correct. His teacher asked him to show his work to the class. The inequality the students had to solve was. Mark wrote the steps shown below on the board. Which of the following explains step 4 of his solution? A. B. C. The associative property was applied. The distributive property was applied. You must change the direction of the inequality symbol whenever you divide both sides of the inequality by an even number. D. You must change the direction of the inequality symbol whenever you divide both sides of the inequality by a negative number.