LO Able to use the quadratic formula November

LO: Able to use the quadratic formula November 2016 Quadratic Formula Expand simplify the following: (x + 3)(x + 4) (x + 5)(x – 2) Factorise the following: 4 ap + 8 pt 5 ac – 15 bc Rearrange the letters to find the maths term: RCFIETSAO UOSNTOIL UETAQNOI

SMSC: To work in a group. British Values: Respect and tolerance of opinions. Lesson Challenges: Able to factorise quadratics Re-cap Able to substitute into the quadratic formula Able to solve equations using the quadratic formula Grade 5 Grade 6 What will you achieve and learn today?

Any quadratic equation of the form: ax 2 + bx + c = 0 can be solved by substituting the values of a, b and c into the formula: -b ± x= 2 b 2 a – 4 ac

ax 2 + bx + c = 0

Jigsaw ax 2 + bx + c = 0 -b ± x= 2 b 2 a – 4 ac

Use the quadratic formula to solve: x 2 – 7 x + 8 = 0 1 x 2 – 7 x + 8 = 0 -b ± b 2 – 4 ac x= 2 a

Use the quadratic formula to solve: 2 x 2 + 5 x – 1 = 0 -b ± b 2 – 4 ac x= 2 a

Use the quadratic formula to solve: 9 x 2 – 12 x + 4 = 0 -b ± b 2 – 4 ac x= 2 a

Use the quadratic formula to solve: x 2 + x + 3 = 0 1 x 2 + 1 x + 3 = 0 -b ± b 2 – 4 ac x= 2 a

From using the quadratic formula, -b ± b 2 – 4 ac x= 2 a we can use the solution to b 2 – 4 ac, to decide how many solutions there are. • When b 2 – 4 ac is positive, there are two solutions. • When b 2 – 4 ac is equal to zero, there is one solution. • When b 2 – 4 ac is negative, there are no solutions.

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SMSC: To work in a group. British Values: Respect and tolerance of opinions. Lesson Challenges: Able to factorise quadratics Re-cap Able to substitute into the quadratic formula Able to solve equations using the quadratic formula Grade 5 Grade 6 What will you achieve and learn today?