Let us discuss the harmonic oscillator Let us
- Slides: 86
Let us discuss the harmonic oscillator
Let us discuss the harmonic oscillator E = T + V = ½mv 2 + ½kx 2
Let us discuss the harmonic oscillator E = T + V = ½mv 2 + ½kx 2 H = px 2/2 m + ½kx 2
Let us discuss the harmonic oscillator E = T + V = ½mv 2 + ½kx 2 H = px 2/2 m + ½kx 2 By a change of variables
Let us discuss the harmonic oscillator E = T + V = ½mv 2 + ½kx 2 H = px 2/2 m + ½kx 2 By a change of variables x = q(mω)-½ ω = (k/m)½
Let us discuss the harmonic oscillator E = T + V = ½mv 2 + ½kx 2 H = px 2/2 m + ½kx 2 By a change of variables x = q(mω)-½ ω = (k/m)½ We get a rather neater equation for the Hamiltonian
Let us discuss the harmonic oscillator E = T + V = ½mv 2 + ½kx 2 H = px 2/2 m + ½kx 2 By a change of variables x = q(mω)-½ ω = (k/m)½ We get a rather neater equation for the Hamiltonian H = ½ω(p 2 + q 2)
H = ½ω(p 2 + q 2) Let’s now consider this set of commutators
H = ½ω(p 2 + q 2) Let’s now consider this set of commutators NB that I have set ħ = 1 to simplify the relations
H = ½ω(p 2 + q 2) Let’s now consider this set of commutators NB that I have set ħ = 1 to simplify the relations [q, p] = i [H, q] = ω(-ip) [H, p] = ωiq
H = ½ω(p 2 + q 2) Let’s now consider this set of commutators NB that I have set ħ = 1 to simplify the relations [q, p] = i [H, q] = ω(-ip) [H, p] = ωiq From this set of quantum mechanical definitions
H = ½ω(p 2 + q 2) Let’s now consider this set of commutators NB that I have set ħ = 1 to simplify the relations [q, p] = i [H, q] = ω(-ip) [H, p] = ωiq From this set of quantum mechanical definitions We can invent a couple of B-type operators
H = ½ω(p 2 + q 2) Let’s now consider this set of commutators NB that I have set ħ = 1 to simplify the relations [q, p] = i [H, q] = ω(-ip) [H, p] = ωiq From this set of quantum mechanical definitions We can invent a couple of B-type operators ie operators that follow the form
H = ½ω(p 2 + q 2) Let’s now consider this set of commutators NB that I have set ħ = 1 to simplify the relations [q, p] = i [H, q] = ω(-ip) [H, p] = ωiq From this set of quantum mechanical definitions We can invent a couple of B-type operators ie operators that follow the form AB – BA = k. B
AB – BA = k. B
[H , F+] = – ωF+ HF+ – F+H = – ωF+ Now let’s operate with both sides of this expression on a particular eigenfunction En
[H , F+] = – ωF+ HF+ – F+H = – ωF+ Now let’s operate with both sides of this expression on a particular eigenfunction En ie the nth eigenfunction defined by
[H , F+] = – ωF+ HF+ – F+H = – ωF+ Now let’s operate with both sides of this expression on a particular eigenfunction En ie the nth eigenfunction defined by H En = En En
[H , F+] = – ωF+ HF+ – F+H = – ωF+ Now let’s operate with both sides of this expression on a particular eigenfunction En ie the nth eigenfunction defined by H En = En En H F+ En – F+H En = – ωF+ En
[H , F+] = – ωF+ HF+ – F+H = – ωF+ Now let’s operate with both sides of this expression on a particular eigenfunction En ie the nth eigenfunction defined by H En = En En H F+ En – F+H En = – ωF+ En H F+ En – En. F+ En = – ωF+ En
[H , F+] = – ωF+ HF+ – F+H = – ωF+ Now let’s operate with both sides of this expression on a particular eigenfunction En ie the nth eigenfunction defined by H En = En En H F+ En – F+H En = – ωF+ En H F+ En – En. F+ En = – ωF+ En H F+ En = (En – ω) F+ En
[H , F+] = – ωF+ HF+ – F+H = – ωF+ Now let’s operate with both sides of this expression on a particular eigenfunction En ie the nth eigenfunction defined by H En = En En H F+ En – F+H En = – ωF+ En H F+ En – En. F+ En = – ωF+ En H F+ En = (En – ω) F+ En So F+ has operated on En to produce a new eigenfunction with eigenvalue En – ω
En
En En – ω En – 2ω Let’s ladder down till we get to the last eigenvalue at which a next application of F+ would produce an eigenstate with negative energy which we shall posutlate is not allowed and so F+ must annihilate this last eigenstate ie F+ E↓ = 0
En En – ω En – 2ω F+ E↓ Aaaaghhhhh…… E↓ Let’s ladder down till we get to the last eigenvalue at which a next application of F+ would produce an eigenstate with negative energy which we shall posutlate is not allowed and so F+ must annihilate this last eigenstate ie F+ E↓ = 0
F+F– = (q + ip)(q – ip) = q 2 – iqp + ipq +p 2
F+F– = (q + ip)(q – ip) = q 2 – iqp + ipq +p 2 = q 2 – i[q, p] + p 2
F+F– = (q + ip)(q – ip) = q 2 – iqp + ipq +p 2 = q 2 – i[q, p] + p 2 = q 2 + p 2 + 1
They are F± = q ± ip By inspection we can show that [H , F+] = – ωF+ [H , F–] = + ωF– These are of the form [A , B] = k. B So the Fs are B-type operators
Now H can be factorised as H = ½ω(F+F– – 1) H = ½ω(F– F+ + 1) H = ½ω(F+ F– – 1) H = ½ω(F– F+ + 1)
Now H can be factorised as H = ½ω(F+F– – 1) H = ½ω(F– F+ + 1) H{F+ En } = (En – ω){F+ En } H{F– En } = (En– ω){F– En }
Now H can be factorised as H F+ En = ½ω(F+F– – 1) F+ En H{F+ En } = (En – ω){F+ En } H{F– En } = (En– ω){F– En }
Let us discuss the harmonic oscillator E = T + V = ½m 2 + ½kx 2 H = p 2/2 m + ½kx 2 By a change of variables x = q(mω)-½ ω = (k/m)½ We get a rather neater equation for the Hamiltonian H = ½ω(p 2 + q 2)
Let us discuss the harmonic oscillator E = T + V = ½m 2 + ½kx 2 H = p 2/2 m + ½kx 2 By a change of variables x = q(mω)-½ ω = (k/m)½ We get a rather neater equation for the Hamiltonian H = ½ω(p 2 + q 2)
H = ½ω(p 2 + q 2) Let’s now consider this set of commutators NB that I have set ħ = 1 to simplify the relations [q, p] = i [H, q] = ω(-ip) [H, p] = ωiq From this set of quantum mechanical definitions We can invent a couple of B-type operators ie one that follows the form AB – BA = ±k. B
[q, p] = i [H, q] = ω(–ip) [H, p] = ω(iq) From this set of quantum mechanical definitions We can invent a couple of B-type operators ie one that follows the form AB – BA = ±k. B F+ = q + ip [H, F+] = [H, q] + i[H, p] = ω(–ip) + iω(iq) = ω(–ip – q) = – ωF+ [H, F+] = –ωF+ and [H , F–] = +ωF–
[H , F+] = – ωF+ HF+ – F+H = – ωF+ Operate on a particular eigenfunction En ie the nth eigenfunction defined by H En = En En with both sides H F+ En – F+H En = – ωF+ En H F+ En – En. F+ En = – ωF+ En H F+ En = (En – ω) F+ En
They are F± = q ± ip By inspection we can show that [H , F+] = – ωF+ [H , F–] = + ωF– These are of the form [A , B] = k. B So the Fs are B-type operators
Now H can be factorised as H = ½ω(F+F– – 1) H = ½ω(F– F+ + 1) H = ½ω(F+ F– – 1) H = ½ω(F– F+ + 1)
Now H can be factorised as H = ½ω(F+F– – 1) H = ½ω(F– F+ + 1) H{F+ En } = (En – ω){F+ En } H{F– En } = (En– ω){F– En }
Now H can be factorised as H F+ En = ½ω(F+F– – 1) F+ En H{F+ En } = (En – ω){F+ En } H{F– En } = (En– ω){F– En }
H = ½ω(p 2 + q 2) Let’s now consider this set of commutators NB that I have set ħ = 1 to simplify the relations [q, p] = i [H, q] = ω(-ip) [H, p] = ωiq From this set of quantum mechanical definitions We can invent a couple of B-type operators ie one that follows the form AB – BA = ±k. B
[q, p] = i [H, q] = ω(–ip) [H, p] = ω(iq) From this set of quantum mechanical definitions We can invent a couple of B-type operators ie one that follows the form AB – BA = ±k. B F+ = q + ip [H, F+] = [H, q] + i[H, p] = ω(–ip) + iω(iq) = ω(–ip – q) = – ωF+ [H, F+] = –ωF+ and [H , F–] = +ωF–
[H , F+] = – ωF+ HF+ – F+H = – ωF+ Operate on a particular eigenfunction En ie the nth eigenfunction defined by H En = En En with both sides H F+ En – F+H En = – ωF+ En H F+ En – En. F+ En = – ωF+ En H F+ En = (En – ω) F+ En
n En En – ω En – 2ω Let’s ladder down till we get to the last eigenvalue at which a next application of F+ would produce an eigenstate with negative energy which we shall posutlate is not allowed and that must annihilate this last eigenstate ie F+ E↓ = 0 F+ Aaaaghhhhh…… E↓
They are F± = q ± ip By inspection we can show that [H , F+] = – ωF+ [H , F–] = + ωF– These are of the form [A , B] = k. B So the Fs are B-type operators
Now H can be factorised as H = ½ω(F+F– – 1) H = ½ω(F– F+ + 1) H = ½ω(F+ F– – 1) H = ½ω(F– F+ + 1)
Now H can be factorised as H = ½ω(F+F– – 1) H = ½ω(F– F+ + 1) H{F+ En } = (En – ω){F+ En } H{F– En } = (En– ω){F– En }
Now H can be factorised as H F+ En = ½ω(F+F– – 1) F+ En H{F+ En } = (En – ω){F+ En } H{F– En } = (En– ω){F– En }
[A , B] = 0 If A and B commute there exist eigenfunctions that are simultaneously eigenfunctions of both operators A and B and one can determine simultaneously the values of the quantities represented by the two operators but if they do not commute one cannot determine the values of the quantities simultaneously
- Relaxation time of damped harmonic oscillator
- Simple harmonic oscillator
- Morse potential
- Frequency of oscillation
- Simple harmonic oscillator amplitude
- Mechanical energy
- Hooke's law simple definition
- Selection rule for simple harmonic oscillator
- Harmonic oscillator propagator
- Harmonic oscillator selection rules
- Harmonic oscillator spring
- Q factor damped harmonic oscillator
- 戴明鳳
- Energy of harmonic oscillator
- Harmonic oscillator
- Tension wave
- Let me let me let me
- Amateurs discuss tactics professionals discuss logistics
- Let discuss what wearing
- Lets think in english
- Let's discuss the story so far
- An oscillator converts
- Oscillator definition
- In a voltage shunt feedback circuit,
- Lc oscillator simulation
- Barkhausen criteria of oscillator
- Application of programmable unijunction transistor
- An oscillator converts …………….. *
- Lc oscillator
- Need of oscillator
- Lc feedback oscillator
- Types of oscillator
- Relaxation oscillator schmitt trigger
- Voltage controlled oscillator
- Minecraft 102
- Colpitts oscillator frequency formula
- L c oscillator
- Op amp oscillator
- Mti radar with power amplifier transmitter
- Oscillator analog electronics
- What is audio oscillator
- Half center oscillator
- Series fed hartley oscillator
- Oscillator phase noise 50low
- Barkhausen criteria of oscillator
- Osilator amstrong
- Trigger
- Barkhausen criteria of oscillator
- Ujt relaxation oscillator
- Zener diodes exhibit
- Malha
- Properties of ultrasonic waves
- Cmos lc oscillator
- Phase shift oscillator
- He who has ears to hear let him hear revelation
- Indirect object answers the question
- What did you say
- Các châu lục và đại dương trên thế giới
- Từ ngữ thể hiện lòng nhân hậu
- Tư thế ngồi viết
- Diễn thế sinh thái là
- V. c c
- 101012 bằng
- Hát lên người ơi alleluia
- Khi nào hổ mẹ dạy hổ con săn mồi
- đại từ thay thế
- Vẽ hình chiếu vuông góc của vật thể sau
- Quá trình desamine hóa có thể tạo ra
- Cong thức tính động năng
- Thế nào là mạng điện lắp đặt kiểu nổi
- Hát kết hợp bộ gõ cơ thể
- Tỉ lệ cơ thể trẻ em
- Lời thề hippocrates
- Dạng đột biến một nhiễm là
- Vẽ hình chiếu đứng bằng cạnh của vật thể
- độ dài liên kết
- Môn thể thao bắt đầu bằng từ đua
- Khi nào hổ mẹ dạy hổ con săn mồi
- điện thế nghỉ
- Biện pháp chống mỏi cơ
- Trời xanh đây là của chúng ta thể thơ
- Gấu đi như thế nào
- Lp html
- Thiếu nhi thế giới liên hoan
- Số nguyên tố là
- Phối cảnh
- Một số thể thơ truyền thống