Lens Equation Word Problems Seo Physics Word problem

Lens Equation Word Problems Seo Physics

Word problem terminologies 1) Spherical center = radius of curvature 2) Focal point = half of the radius of curvature 3) Converging lens = convex lens 4) Diverging lens = concave lens 5) Double concave lens = concave mirror

Mirror equation review Lens Equation? 1 do + 1 di = 1 f do di

Magnification review Magnification ratio equation? hi = -di = M do ho ho hi

Practice 1 An object is 3. 3 cm high is 22. 0 cm from a concave lens. The radius of curvature is 25 cm. A) Draw the Ray Diagram 3. 3 cm 22 cm hi B) Image Characteristics Image is Reduced, Real, and Inverted

Practice 1 (con. ) An object is 3. 3 cm high is 22. 0 cm from a concave lens. The radius of curvature is 25 cm. (Focal length is half of the radius curvature. f= 12. 5 cm). 1 C) Find the Image distance 1 di = 1 - 1 12. 5 cm 22 cm -di x h o do = di 1 f = 0. 08 cm- 0. 045 cm di = 29. 0 cm D) Find the height of the Image = 1 do 1/di= 0. 0345 cm hi + hi hi ho = -di do = -29 cm 22 cm = M hi = -4. 35 cm x 3. 3 cm

DIY A bird 2. 0 cm high is 30. 0 cm from a concave lens. The radius of curvature is 20. 0 cm. A) Draw the Ray Diagram 2 cm 30 cm hi B) Image Characteristics Image is Reduced, Real, and Inverted

DIY (con. ) A bird 2. 0 cm high is 30. 0 cm from a concave mirror. The radius of curvature is 20. 0 cm (focal length is half of the radius curvature= 10 cm) 1 C) Find the Image distance 1 di = 1 - 10 cm 1 30 cm D) Find the height of the Image = -di x h o do 1 = di 1 f = 0. 1 cm – 0. 03 cm di = 15 cm 1/di= 0. 0667 cm hi do + hi hi = -di = M do ho hi = -1 cm = -15 cm x 2. 0 cm 30 cm

Practice 2 A bird that is 5 cm high is placed 15 cm in front of a converging lens with focal length of 20 cm. A) Draw the Ray Diagram ho 15 cm 20 cm hi B) Image Characteristics • Image is Reduced, Inverted and Virtual

Practice 2 (con. ) A bird that is 5 cm high is placed 15 cm in front of a converging lens with focal length of 20 cm. 1 + 1 = 1 f di do = 1 - 1 = 0. 05 cm – 0. 067 cm 20 cm 15 cm C) Find the Image distance 1 di di = -58. 82 cm 1/di= -0. 017 cm D) Find the height of the Image hi = -di x h o do hi hi ho = -di do = M hi = 19. 60 cm = 58. 82 cm x 5. 0 cm 15 cm

DIY A bird is 10 cm high and placed 35 cm in front of a converging lens with radius of curvature of 20 cm. A) Draw the Ray Diagram ho 35 cm 20 cm hi B) Image Characteristics • Image is Reduced, Inverted and Virtual

DIY (con. ) A bird is 10 cm high and placed 35 cm in front of a converging lens with radius of curvature of 20 cm. 1 + do C) Find the Image distance 1 di = 1 - 1 10 cm 35 cm D) Find the height of the Image = -di x h o do = 1 f = 0. 1 cm – 0. 03 cm di = 14. 28 cm 1/di= 0. 07 cm hi 1 di hi hi ho = -di do = M hi = -4. 08 cm = -14. 28 cm x 10. 0 cm 35 cm