Lecture slides to accompany Engineering Economy 8 th

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Lecture slides to accompany Engineering Economy, 8 th edition Leland Blank, Anthony Tarquin ©Mc.

Lecture slides to accompany Engineering Economy, 8 th edition Leland Blank, Anthony Tarquin ©Mc. Graw-Hill Education. All rights reserved. Authorized only for instructor use in the classroom. No reproduction or further distribution permitted without the prior written consent of Mc. Graw-Hill Education.

Chapter 3 Combining Factors and Spreadsheet Functions ©Mc. Graw-Hill Education. All rights reserved. Authorized

Chapter 3 Combining Factors and Spreadsheet Functions ©Mc. Graw-Hill Education. All rights reserved. Authorized only for instructor use in the classroom. No reproduction or further distribution permitted without the prior written consent of Mc. Graw-Hill Education.

LEARNING OUTCOMES 1. Shifted uniform series 2. Shifted series and single cash flows 3.

LEARNING OUTCOMES 1. Shifted uniform series 2. Shifted series and single cash flows 3. Shifted gradients ©Mc. Graw-Hill Education.

Shifted Uniform Series A shifted uniform series starts at a time other than period

Shifted Uniform Series A shifted uniform series starts at a time other than period 1 The cash flow diagram below is an example of a shifted series Series starts in period 2, not period 1 Shifted series usually require the 4 2 3 0 1 5 use of multiple factors Remember: When using P/A or A/P factor, PA is always one year ahead of first A When using F/A or A/F factor, F A is in same year as last A ©Mc. Graw-Hill Education.

Example Using P/A Factor: Shifted Uniform Series • 0 1 0 5 2 1

Example Using P/A Factor: Shifted Uniform Series • 0 1 0 5 2 1 3 4 5 2 3 4 Actual 6 year Series year A = $10, 000 • • ©Mc. Graw-Hill Education.

Example Using F/A Factor: Shifted Uniform Series How much money would be available in

Example Using F/A Factor: Shifted Uniform Series How much money would be available in year 10 if $8000 is deposited each year in years 3 through 10 at an interest rate of 10% per year? Cash flow diagram is: Actual year 0 10 1 2 0 8 3 1 4 2 5 3 4 • ©Mc. Graw-Hill Education. 6 7 5 8 6 9 7 Series year

Shifted Series and Random Single Amounts For cash flows that include uniform series and

Shifted Series and Random Single Amounts For cash flows that include uniform series and randomly placed single amounts: Uniform series procedures are applied to the series amounts Single amount formulas are applied to the one-time cash flows The resulting values are then combined per the problem statement The following slides illustrate the procedure ©Mc. Graw-Hill Education.

Example: Series and Random Single Amounts (1) Find the present worth in year 0

Example: Series and Random Single Amounts (1) Find the present worth in year 0 for the cash flows shown using an interest rate of 10% per year. 0 9 1 10 2 3 4 5 6 ©Mc. Graw-Hill Education. 1 10 2 0 3 1 4 2 5 3 8 $2000 0 9 • 7 6 4 7 5 8 6 Actual 7 year 8 Series year

Example: Series and Random Single Amounts (2) P A 0 9 1 10 2

Example: Series and Random Single Amounts (2) P A 0 9 1 10 2 0 3 1 2 • ©Mc. Graw-Hill Education. 4 5 3 6 4 7 5 $2000 8 6 Actual year 7 8 Series year

Example Worked a Different Way (Using F/A instead of P/A for uniform series) The

Example Worked a Different Way (Using F/A instead of P/A for uniform series) The same re-numbered diagram from the previous slide is used 0 9 1 10 2 0 3 1 4 2 5 3 6 4 7 5 8 6 7 8 $2000 • As shown, there are usually multiple ways to work equivalency problems ©Mc. Graw-Hill Education.

Example: Series and Random Amounts • 0 7 1 2 8 3 0 5

Example: Series and Random Amounts • 0 7 1 2 8 3 0 5 4 1 2 • • ©Mc. Graw-Hill Education. 5 6 3 $1000 4

Shifted Arithmetic Gradients Shifted gradient begins at a time other than between periods 1

Shifted Arithmetic Gradients Shifted gradient begins at a time other than between periods 1 and 2 Present worth PG is located 2 periods before gradient starts Must use multiple factors to find PT in actual year 0 To find equivalent A series, find PT at actual time 0 and apply (A/P, i, n) ©Mc. Graw-Hill Education.

Example: Shifted Arithmetic Gradient John Deere expects the cost of a tractor part to

Example: Shifted Arithmetic Gradient John Deere expects the cost of a tractor part to increase by $5 per year beginning 4 years from now. If the cost in years 1 -3 is $60, determine the present worth in year 0 of the cost through year 10 at an interest rate of 12% per year. 0 1 3 2 0 60 60 4 1 60 2 65 Actual years 10 5 3 8 Gradient years 70 95 • • Next, move P 2 back to • year 0 Next, find PA for the $60 amounts of years 1 and 2 Finally, add P 0 and PA to get PT in year 0 ©Mc. Graw-Hill Education. • •

Shifted Geometric Gradients Shifted gradient begins at a time other than between periods 1

Shifted Geometric Gradients Shifted gradient begins at a time other than between periods 1 and 2 Equation yields Pg for all cash flows (base amount A 1 is included) Equation (i ≠ g): • For negative gradient, change signs on both g values There are no tables for geometric gradient factors ©Mc. Graw-Hill Education.

Example: Shifted Geometric Gradient • ©Mc. Graw-Hill Education. (1)

Example: Shifted Geometric Gradient • ©Mc. Graw-Hill Education. (1)

Example: Shifted Geometric Gradient • ©Mc. Graw-Hill Education. (2)

Example: Shifted Geometric Gradient • ©Mc. Graw-Hill Education. (2)

Negative Shifted Gradients • • • For negative geometric gradients, change signs on both

Negative Shifted Gradients • • • For negative geometric gradients, change signs on both g values • • • All other procedures are the same as for positive gradients ©Mc. Graw-Hill Education.

Example: Negative Shifted Arithmetic Gradient • 0 1 2 0 6 3 1 700

Example: Negative Shifted Arithmetic Gradient • 0 1 2 0 6 3 1 700 4 2 650 3 600 5 4 550 500 6 5 Actual years 7 Gradient years 450 Solution: Gradient G first occurs between actual years 2 and 3; these are gradient years 1 and 2 PG is located in gradient year 0 (actual year 1); base amount of $700 is in gradient years 1 -6 • ©Mc. Graw-Hill Education.

Summary of Important Points P for shifted uniform series is one period ahead of

Summary of Important Points P for shifted uniform series is one period ahead of first A; n is equal to number of A values F for shifted uniform series is in same period as last A; n is equal to number of A values For gradients, first change equal to G or g occurs between gradient years 1 and 2 • • ©Mc. Graw-Hill Education.