Lecture 6 Chapter 3 3 3 1 Why

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Lecture 6 Chapter 3 第 3章 3. 1 Why Use an RNA Intermediate? 3.

Lecture 6 Chapter 3 第 3章 3. 1 Why Use an RNA Intermediate? 3. 1 为什么使用RNA 3. 2 Mechanism of Transcription 3. 2 转录机理 3. 3 Regulation of Gene Expression 3. 3 原核生物基因 in Prokaryotes 表达调控 3. 3. 1 Coordinate Regulation 3. 3. 1 协同调控 3. 3. 2 The Lac Operon 3. 3. 2 乳糖操纵子 3. 3. 3 The Trp Operon 3. 3. 3 色氨酸操纵子 3. 3. 4 Ara & Gal Operons 3. 3. 4 Ara与Gal 3. 4 Experiments 1 / 46 3. 4 实验研究

Review of Lecture 5 A 1 → An RNA intermediate is used because …

Review of Lecture 5 A 1 → An RNA intermediate is used because … 使用RNA中间物是因为. . . A 2 → The player is RNA polymerase ! RNA聚合酶是玩家 ! A 3 → Transcription is initiated at the promoter region. σ subunit of the RNA polymerase is responsible for recognizing the promoter. 转录是从启动子区域起始的,RNA 聚合酶的σ亚基负责识别启动子。 A 4 → Transcription errors can be corrected in two ways 有两种方式可以用来纠正转录错误 A 5 → Transcription can be terminated in two ways 转录能以两种方式终止 2 / 46

A 1 → An RNA intermediate is used because … 使用RNA中间物是因为. . . Chromosomes

A 1 → An RNA intermediate is used because … 使用RNA中间物是因为. . . Chromosomes are large and complex 染色体庞大又复杂 DNA must be kept stable DNA必须保持稳定 One m. RNA, many proteins 一条m. RNA, 多个蛋白质 More opportunities for regulation 更多调控机会 3 / 46

A 2 → The player is RNA polymerase ! RNA聚合酶是玩家 ! 4 / 46

A 2 → The player is RNA polymerase ! RNA聚合酶是玩家 ! 4 / 46

A 3 → Transcription is initiated at the promoter region. σ subunit of the

A 3 → Transcription is initiated at the promoter region. σ subunit of the RNA polymerase is responsible for recognizing the promoter. 转录是从启动子区域起始的,RNA聚合酶的 σ亚基负责识别启动子。 5 / 46

A 4 → Transcription errors can be corrected in two ways 有两种方式可以用来纠正转录错误 6 /

A 4 → Transcription errors can be corrected in two ways 有两种方式可以用来纠正转录错误 6 / 46

A 5 → Transcription can be terminated in two ways 转录能以两种方式终止 7 / 46

A 5 → Transcription can be terminated in two ways 转录能以两种方式终止 7 / 46

Questions for Lecture 6 Q 1 → How can E. coli survive when there

Questions for Lecture 6 Q 1 → How can E. coli survive when there is only lactose ? 只有乳糖时大肠杆菌如何生存呢? 8 / 46

Vocabulary of Lecture 6 gene expression coordinate regulation polycistronic m. RNA cistron operator lactose

Vocabulary of Lecture 6 gene expression coordinate regulation polycistronic m. RNA cistron operator lactose galactose permease galactosidase 9 / 46 (1/2) 基因表达 协同调控 多顺反子m. RNA 顺反子 操纵基因 乳糖 半乳糖 渗透酶 半乳糖苷酶

Vocabulary of Lecture 6 transacetylase repressor catabolite activator protein adenylyl cyclase partial diploid negative

Vocabulary of Lecture 6 transacetylase repressor catabolite activator protein adenylyl cyclase partial diploid negative regulation positive regulation allolactose mammalian gut 10 / 46 (2/2) 转乙酰基酶 阻遏蛋白 代谢物激活蛋白(CAP) 腺苷酸环化酶 部分二倍体 负调控 正调控 异乳糖 哺乳动物 肠,消化道

3. 3 Regulation of gene expression in prokaryotes 3. 3 原核生物基因表达调控 3. 3. 1

3. 3 Regulation of gene expression in prokaryotes 3. 3 原核生物基因表达调控 3. 3. 1 Coordinate Regulation 3. 3. 1 协同调控 3. 3. 2 The Lac Operon 3. 3. 2 乳糖操纵子 3. 3. 3 The Trp Operon 3. 3. 3 色氨酸操纵子 3. 3. 4 Ara & Gal Operons 3. 3. 4 阿拉伯糖与 半乳糖操纵子 11 / 46

Regulation of gene expression 基因表达调控 Condition A 12 / 46

Regulation of gene expression 基因表达调控 Condition A 12 / 46

Regulation of gene expression 基因表达调控 Condition B 13 / 46

Regulation of gene expression 基因表达调控 Condition B 13 / 46

3. 3. 1 Coordinate Regulation 协同调控 Coordinate regulation: Transcriptional regulation in which a set

3. 3. 1 Coordinate Regulation 协同调控 Coordinate regulation: Transcriptional regulation in which a set of genes are regulated together. Operator 操纵基因 14 / 46 协同调控:一组基因在一 起进行调控的转录调控方 式。

Polycistronic m. RNA 多顺反子m. RNA Polycistronic m. RNA Translation Protein 1 Protein 2 15

Polycistronic m. RNA 多顺反子m. RNA Polycistronic m. RNA Translation Protein 1 Protein 2 15 / 46 Protein 3

3. 3. 2 The lac Operon / 乳糖操纵子 Lac operon: An operon containing genes

3. 3. 2 The lac Operon / 乳糖操纵子 Lac operon: An operon containing genes involved in lactose metabolism. lac操纵子:含有乳糖( lactose)代谢基因的操 纵子。 The lac operon 16 / 46

Q 1 → How can E. coli survive when there is only lactose ?

Q 1 → How can E. coli survive when there is only lactose ? 只有乳糖时大肠杆菌如何生存呢? What will E. coli do with the lactose? Lactose 乳糖 17 / 46 Glucose 葡萄糖 E. coli: “I do not usually eat lactose, but in case when there is no glucose. . . ”

The Conditions of Lactose Metabolism 乳糖代谢的条件 乳糖 半乳糖 E. coli: “This is my favorite!”

The Conditions of Lactose Metabolism 乳糖代谢的条件 乳糖 半乳糖 E. coli: “This is my favorite!” 18 / 46 葡萄糖

How to use lactose / 如何利用乳糖 E. coli: “I need lactose permease, β-galactosidase, and

How to use lactose / 如何利用乳糖 E. coli: “I need lactose permease, β-galactosidase, and transacetylase. ” 19 / 46

When to use lactose / 何时利用乳糖 Glucose + Lactose + Glucose – Lactose +

When to use lactose / 何时利用乳糖 Glucose + Lactose + Glucose – Lactose + 20 / 46 Glucose – Lactose – E. coli: “I will use lactose only when there is no glucose and there is lactose. ”

Regulated Expression of Lactose Metabolizing Genes 乳糖代谢基因表达调控 1. Negative Regulation – the lac Repressor

Regulated Expression of Lactose Metabolizing Genes 乳糖代谢基因表达调控 1. Negative Regulation – the lac Repressor 负调控──lac阻遏蛋白 2. Positive Regulation – CAP 正调控──CAP 21 / 46

Negative regulation and positive regulation 负调控与正调控 Negative regulation: With respect 负调控:关于转录,意思 to transcription, means

Negative regulation and positive regulation 负调控与正调控 Negative regulation: With respect 负调控:关于转录,意思 to transcription, means that the 是当一种蛋白质结合上去 binding of a protein causes 以后引起转录的阻遏。 repression of transcription. Positive regulation: In reference to transcription, denotes the activation of transcription by binding of a protein. 22 / 46 正调控:关于转录,表示 通过一种蛋白质的结合而 激活转录。

1. Negative Regulation – When there is no lactose 负调控──当没有乳糖时 23 / 46

1. Negative Regulation – When there is no lactose 负调控──当没有乳糖时 23 / 46

Negative Regulation – When there is lactose 负调控──当有乳糖时 24 / 46

Negative Regulation – When there is lactose 负调控──当有乳糖时 24 / 46

CAP-c. AMP complex CAP c. AMP DNA c. AMP的浓度与葡萄糖的浓度成反比 26 / 46

CAP-c. AMP complex CAP c. AMP DNA c. AMP的浓度与葡萄糖的浓度成反比 26 / 46

Adenylyl Cyclase (AC) Glucose inhibits the activity of AC. ATP AC O—CH 2 O

Adenylyl Cyclase (AC) Glucose inhibits the activity of AC. ATP AC O—CH 2 O c. AMP O P——O O 27 / 46 A OH

CAP – “The accelerator” lac repressor – “The brake” Brake 刹车 Accelerator 加速器 28

CAP – “The accelerator” lac repressor – “The brake” Brake 刹车 Accelerator 加速器 28 / 46

A 1 → Regulation of lac operon 乳糖操纵子的调控 29 / 46

A 1 → Regulation of lac operon 乳糖操纵子的调控 29 / 46

Now showing The lac operon 30 / 46 File: biophoto 7  Genetics: A

Now showing The lac operon 30 / 46 File: biophoto 7 Genetics: A Conceptual Approach The lac operon (15’)

The lac operon (1/10) To utilize lactose as an energy source, E. coli must

The lac operon (1/10) To utilize lactose as an energy source, E. coli must produce the enzymes necessary for its metabolism. 31 / 46

The lac operon (2/10) The genes for these enzymes are adjacent to one another

The lac operon (2/10) The genes for these enzymes are adjacent to one another on the bacterial chromosome and are transcribed together. A group of bacterial genes that are transcribed together is called an operon. 32 / 46

The lac operon (3/10) At one end of the lac operon is a set

The lac operon (3/10) At one end of the lac operon is a set of structural genes, lac. Z, lac. Y, and lac. A, that encodes the enzymes necessary for metabolizing lactose. These three genes have a common promoter. 33 / 46

The lac operon (4/10) The regulator gene lac. I is located upstream of the

The lac operon (4/10) The regulator gene lac. I is located upstream of the structural genes. The lac. I gene encodes a repressor protein and is controlled by its own promoter. This repressor protein may bind to a region of the operon called the operator. The operator overlaps the 3’ end of the promoter and the 5’ end of the lac. Z gene. 34 / 46

The lac operon (5/10) The lac operon is inducible—that is, the structural genes are

The lac operon (5/10) The lac operon is inducible—that is, the structural genes are expressed only in the presence of lactose. Active repressor proteins are encoded by the regulator gene. In the absence of lactose, these repressors bind to the operator and prevent RNA polymerase from initiating transcription. 35 / 46

The lac operon (6/10) When lactose is present, it is readily converted into allolactose,

The lac operon (6/10) When lactose is present, it is readily converted into allolactose, which may then come into contact with the repressor protein. Allolactose binds to the repressor protein and causes a conformational change that prevents the repressor from binding to the operator region of the DNA. 36 / 46

The lac operon (7/10) With the operator site open, RNA polymerase is able to

The lac operon (7/10) With the operator site open, RNA polymerase is able to bind to the operon promoter and transcribe the structural genes. The resulting m. RNA is then translated, leading to the production of the three enzymes, β-galactosidase, premease, and transacetylase, encoded by lac. Z, lac. Y, and lac. A, respectively. 37 / 46

The lac operon (8/10) Lactose is a carbohydrate found in milk. It can be

The lac operon (8/10) Lactose is a carbohydrate found in milk. It can be metabolized by E. coli bacteria that reside in the mammalian gut. Because lactose is too large to diffuse across the bacterial membrane, it must be actively transported into the cell by permease, encoded by the lac. Y gene of the lac 38 / 46 operon.

The lac operon (9/10) To utilize lactose as an energy source, E. coli bacteria

The lac operon (9/10) To utilize lactose as an energy source, E. coli bacteria use the enzyme β-galactosidase, encoded by the lac. Z gene of the lac operon, to break lactose down into glucose and galactose. The function in lactose metabolism of the third enzyme, transacetylase, aslo produced by the lac operon, is not known. 39 / 46

The lac operon (10/10) Here, we explore the effects of the lac repressor and

The lac operon (10/10) Here, we explore the effects of the lac repressor and operator genotypes in a partial diploid. Select one genotype for lac. I and one genotype for lac. O, and drag them to these places on the plasmid copy of the operon. The chromosome copy is fixed as wild type. 40 / 46

Now showing again 41 / 46

Now showing again 41 / 46

Now showing Regulation of Transcription Initiation 42 / 46 File: Molecular Biology of the

Now showing Regulation of Transcription Initiation 42 / 46 File: Molecular Biology of the Gene Interactive animations Chapter 16 Regulation of Transcription Initiation. (~20’)

Essentials of Lecture 6 / 第 6讲要点 A 1 → 43 / 46 Regulation

Essentials of Lecture 6 / 第 6讲要点 A 1 → 43 / 46 Regulation of lac operon 乳糖操纵子的调控

A 1 → Regulation of lac operon 乳糖操纵子的调控 44 / 46

A 1 → Regulation of lac operon 乳糖操纵子的调控 44 / 46

Lecture 7 Chapter 3 第 3章 3. 1 Why Use an RNA Intermediate? 3.

Lecture 7 Chapter 3 第 3章 3. 1 Why Use an RNA Intermediate? 3. 1 为什么使用RNA 3. 2 Mechanism of Transcription 3. 2 转录机理 3. 3 Regulation of Gene Expression 3. 3 原核生物基因 in Prokaryotes 表达调控 3. 3. 1 Coordinate Regulation 3. 3. 1 协同调控 3. 3. 2 The Lac Operon 3. 3. 2 乳糖操纵子 3. 3. 3 The Trp Operon 3. 3. 3 色氨酸操纵子 3. 3. 4 Ara & Gal Operons 3. 3. 4 Ara与Gal 3. 4 Experiments 45 / 46 3. 4 实验研究

Questions for Lecture 7 Q 1 → How should E. coli control tryptophan production?

Questions for Lecture 7 Q 1 → How should E. coli control tryptophan production? 大肠杆菌该如何控制色氨酸的生产呢? Q 2 → E. coli: what should I do with the arabinose ? 大肠杆菌:我应该如何对待阿拉伯糖呢? Q 3 → E. coli: what should I do with the galactose ? 大肠杆菌:我应该如何对待半乳糖呢? 46 / 46