Lecture 10 MetalOxideSemiconductor MOS FieldEffect Transistors FET MOSFET

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Lecture 10 Metal-Oxide-Semiconductor (MOS) Field-Effect Transistors (FET) MOSFET Bias Analysis

Lecture 10 Metal-Oxide-Semiconductor (MOS) Field-Effect Transistors (FET) MOSFET Bias Analysis

Goals • Investigate circuits that bias transistors into different operating regions. • • Two

Goals • Investigate circuits that bias transistors into different operating regions. • • Two Supplies Biasing Four Resistor Biasing Two Resistor Biasing using Current Mirror • Understand Bias Point Stability • Investigate DC Analysis for P-Channel Transistor

Bias Analysis Approach • Assume an operation region (generally the saturation region) • Use

Bias Analysis Approach • Assume an operation region (generally the saturation region) • Use circuit analysis to find VGS • Use VGS to calculate ID, and ID to find VDS • Check validity of operation region assumptions • Change assumptions and analyze again if required. NOTE : An enhancement-mode device with VDS = VGS is always in saturation

Bias Analysis of n-channel MOSFET we start the analysis by assuming certain operating region

Bias Analysis of n-channel MOSFET we start the analysis by assuming certain operating region VGS< VTN Cutoff region i. D=0 Check VGS> Vt VDS < VGS –VTN Triode region VDS > VGS –VTN Sat. region

Example-1 Biasing using two voltage supplies for gate and drain terminal

Example-1 Biasing using two voltage supplies for gate and drain terminal

Example 2 ( Biasing in Triode Region) Also But VDS<VGS-VTN. Hence, saturation region assumption

Example 2 ( Biasing in Triode Region) Also But VDS<VGS-VTN. Hence, saturation region assumption is incorrect Using triode region equation, Assumption: IG=IB=0, transistor is saturated (since VDS= VGS) Analysis: VGS=VDD=4 V and ID=1. 06 m. A VDS<VGS-VTN, transistor is in triode region Q-pt: (1. 06 m. A, 2. 3 V)

Four-Resistor and Two-Resistor Biasing • Provide excellent bias for transistors in discrete circuits. •

Four-Resistor and Two-Resistor Biasing • Provide excellent bias for transistors in discrete circuits. • Stabilize bias point with respect to device parameter and temperature variations using negative feedback. • Use single voltage source to supply both gate-bias voltage and drain current. • Generally used to bias transistors in saturation region. • Two-resistor biasing uses lesser components that fourresistor biasing and also isolates drain and gate terminals

Bias Analysis: Example 3 (Four-Resistor Biasing) Assumption: Transistor is saturated, IG=IB=0 Analysis: First, simplify

Bias Analysis: Example 3 (Four-Resistor Biasing) Assumption: Transistor is saturated, IG=IB=0 Analysis: First, simplify circuit, split VDD into two equal-valued sources and apply Thevenin transformation to find VEQ and REQ for gate-bias voltage Problem: Find Q-pt (ID, VDS) Approach: Assume operation region, find Q-point, check to see if result is consistent with operation region

Bias Analysis: Example 3 (Four-Resistor Biasing) (contd. ) Since VGS<VTN for VGS= -2. 71

Bias Analysis: Example 3 (Four-Resistor Biasing) (contd. ) Since VGS<VTN for VGS= -2. 71 V and MOSFET will be cut-off, and ID= 34. 4 m. A Also, Since IG=0, VDS>VGS-VTN. Hence saturation region assumption is correct. Q-pt: (34. 4 m. A, 6. 08 V) with VGS= 2. 66 V

Two Resistor Biasing the MOSFET using a large drain-to-gate feedback resistance, RG. VDD> Vt

Two Resistor Biasing the MOSFET using a large drain-to-gate feedback resistance, RG. VDD> Vt MOS is ON and always in saturation (diode connected transistor)

Bias Analysis: Example 4 (Two-Resistor Biasing) Since VGS<VTN for VGS= -0. 769 V and

Bias Analysis: Example 4 (Two-Resistor Biasing) Since VGS<VTN for VGS= -0. 769 V and MOSFET will be cut-off, Assumption: IG=IB=0, transistor is saturated (since VDS= VGS) Analysis: and ID= 130 m. A VDS>VGS-VTN. Hence saturation region assumption is correct. Q-pt: (130 m. A, 2. 00 V)

Additional Biasing Circuits_2 Using constant current source

Additional Biasing Circuits_2 Using constant current source

How to implement a current source (Current mirrors) For Q 1 For Q 2

How to implement a current source (Current mirrors) For Q 1 For Q 2

N-branch current mirror Iref I 1 I 2 (W/L)1 (W/L)2 In W/L (W/L)n

N-branch current mirror Iref I 1 I 2 (W/L)1 (W/L)2 In W/L (W/L)n

n-channel and P-Channel MOSFETs

n-channel and P-Channel MOSFETs

DC –Analysis of P-channel MOS Note: The direction of current is out of the

DC –Analysis of P-channel MOS Note: The direction of current is out of the drain for a PMOS

Bias Analysis: Example 5 (Two-Resistor biasing for PMOS Transistor) Also Since VGS= -0. 369

Bias Analysis: Example 5 (Two-Resistor biasing for PMOS Transistor) Also Since VGS= -0. 369 V is less than VTP= -2 V, VGS = -3. 45 V Assumption: IG=IB=0, transistor is saturated (since VDS= VGS) ID = 52. 5 m. A and VGS = -3. 45 V Analysis: Hence saturation assumption is correct. Q-pt: (52. 5 m. A, -3. 45 V)

Example The circuit below uses a p-channel enhancement MOSFET with k’(W/L) = 2 m.

Example The circuit below uses a p-channel enhancement MOSFET with k’(W/L) = 2 m. A/V 2 and Vt = -1 V. Find the value for R that produces V 0 = 10 V.

Modifications to Drain Current Equations Channel-Length Modulation Increasing v. DS beyond v. DSsat causes

Modifications to Drain Current Equations Channel-Length Modulation Increasing v. DS beyond v. DSsat causes the channel pinch-off point to move slightly away from the drain, thus reducing the effective channel length (by ΔL). Effect of v. DS on i. D in the saturation region. The MOSFET parameter VA depends on the process technology and, for a given process, is proportional to the channel length L. It can be called; channel length modulation (λ), or Early voltage (VA)

Example • A saturated MOSFET is operated with a constant v. GS. The drain

Example • A saturated MOSFET is operated with a constant v. GS. The drain current, i. D, is found to be 2 m. A for v. DS = 4 V and 2. 2 m. A for v. DS = 8 V. Find the values of VA, λ and ro.

Including the effect of Channel Length Modulation in the MOSFET model (Valid in the

Including the effect of Channel Length Modulation in the MOSFET model (Valid in the Saturation region) Output resistance

Bias-Point Stability for MOS Amplifiers (source degeneration) i. D Variations in K’(W/L) VG Rs

Bias-Point Stability for MOS Amplifiers (source degeneration) i. D Variations in K’(W/L) VG Rs RS Rs VGS=VG-i. DRS Large Rs stable bias point but requires large supply voltage Rs is called degeneration resistance VGS Vt 1 Vt 2 Variation in Vt